So I have a site that I am building and it will be using data in a database to fill out forms on different websites. Now I understand that this can easily be done with cURL or python however when I intercept and read the post data it is usually a huge mess. For instance on this form there is only a option for comment and rating yet contains all types of other garbage: -------------------------
因此，我建立了一个网站，它将使用数据库中的数据填写不同网站上的表单。 现在我明白，使用cURL或python可以很容易地完成这项工作，但是当我拦截并读取发布数据时，这通常是一个巨大的混乱。 例如在这个表格中，只有一个评论和评分选项，但包含所有类型的其他垃圾： -----------------------------122061295120255 Content-Disposition: form-data; name="StylesheetManager_TSSM" -----------------------------122061295120
I want to use a php proxy to resolve the cross domain problem during uploading file. In the script i used php curl to forward request and response, but i don't know how to forward the request body to the server when the request body is multipart/format-data. file_get_contents('php://input') will be null when the Content-Type header is "multipart/form-data". And when using
我想在上传文件时使用php代理来解决跨域问题。 在脚本中，我使用php curl来转发请求和响应，但是当请求主体是multipart / format-data时，我不知道如何将请求主体转发到服务器。 当Content-Type标题为“multipart / form-data”时， file_get_contents（'php：// input'）将为空。 当使用curl_setopt（$ ch，CURLOPT_POSTFIELDS，$ _POST）时 ，可以发送请求正文中的Content-Disposition，而文件的真实数据不能。 我
This question already has an answer here: Can I call curl_setopt with CURLOPT_HTTPHEADER multiple times to set multiple headers? 2 answers You can Use below code to achieve your goal $jsonData1_get_r = array( 'customerMobileNo'=>'9040845440', 'recipientMobileNo'=>'7008565316', 'recipientName'=>'Name Test Test', 'accountNo'=>'5928374737328009',
这个问题在这里已经有了答案： 我可以多次使用CURLOPT_HTTPHEADER调用curl_setopt来设置多个头文件吗？ 2个答案 你可以使用下面的代码来实现你的目标 $jsonData1_get_r = array( 'customerMobileNo'=>'9040845440', 'recipientMobileNo'=>'7008565316', 'recipientName'=>'Name Test Test', 'accountNo'=>'5928374737328009', 'bankName'=>'HDFC', 'accIfs
I'm writing a php application that submits via curl data to sign up for an iContact email list. However I keep getting an invalid email address error. I think this may be due to the fact that I'm escaping the @ symbol so it looks like %40 instead of @. Also, according to the php documentation for curl_setopt with CURLOPT_POSTFIELDS: The full data to post in a HTTP "POST" op
我在写一个通过curl数据提交的php应用程序来注册一个iContact邮件列表。 不过，我一直收到无效的电子邮件地址错误。 我认为这可能是由于我正在逃避@符号，因此它看起来像％40而不是@。 另外，根据curl_setopt的php文档和CURLOPT_POSTFIELDS： 完整的数据在HTTP“POST”操作中发布。 要发布文件，请使用@预先指定文件名并使用完整路径。 那么，无论如何，通过curl在php中传递@符号作为发布数据，而不是首先通过urlencode运
I want to make an login with CURL on a site, looking like http://www.example.com/login.php?return= The parameters are going to send with Post curl_setopt($ch, CURLOPT_POST, TRUE); $data = array ("params" => "param" ); curl_setopt($ch, CURLOPT_POSTFIELDS, $data); CURL is setting an Expect: 100-continue Header and I will get an 417 - Expectation Failed as
我想在网站上使用CURL进行登录，看起来像 http://www.example.com/login.php?return= 参数将随Post发送 curl_setopt（$ ch，CURLOPT_POST，TRUE）; $ data = array（“params”=>“param”）; curl_setopt（$ ch，CURLOPT_POSTFIELDS，$ data）; CURL正在设定一个 期望：100-继续标题 我会得到一个 417 - 期望失败 作为回应。 所以它不起作用。 当我尝试删除Expect标题 curl_setopt（$ ch，CURLOPT_HTT
I have the following php code curl_setopt($ch, CURLOPT_URL, $URL); curl_setopt($ch, CURLOPT_USERAGENT, $this->_agent); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_AUTOREFERER, true); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch, CURLOPT_HTTPHEADER, $this->_headers); curl_setopt($ch, CURLOPT_ENCODING , "gzip"); curl_setopt($ch, CURLOPT_VERBOSE, false); curl_set
我有以下的PHP代码 curl_setopt($ch, CURLOPT_URL, $URL); curl_setopt($ch, CURLOPT_USERAGENT, $this->_agent); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_AUTOREFERER, true); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch, CURLOPT_HTTPHEADER, $this->_headers); curl_setopt($ch, CURLOPT_ENCODING , "gzip"); curl_setopt($ch, CURLOPT_VERBOSE, false); curl_setopt($ch, CUR
Objective: I want to send multiple images using multipart/form-data. Below is a snippet of my code. Problem: On one PC, the multipart attachment is sent by the correct MIME header Content-Type: image/jpeg, but on another PC, the MIME header is Content-Type: application/octet. Question: How can I force cURL to set the correct Content-Type header for the MIME content? $ch = curl_init();
目的： 我想使用multipart / form-data发送多个图像。 以下是我的代码片段。 问题： 在一台PC上，多部分附件由正确的MIME头Content-Type：image / jpeg发送，但在另一台PC上，MIME头为Content-Type：application / octet。 题： 我如何强制cURL为MIME内容设置正确的Content-Type标头？ $ch = curl_init(); $params = array('name' => '@D:globe.jpg'); $base_url = "https://example.com"."?".varEncode($te
I want to login the user when registration success. I'm using Symfony 3 with fos_user. This is the registration code: $userManager = $this->get('fos_user.user_manager'); $user = $userManager->createUser(); $user->setUsername($username); $user->setPlainPassword($password); $user->setEmail($email); $role = "ROLE_USER"; $user->setRoles(array($role)); $user->setEnabled(tru
我想在注册成功时登录用户。 我正在使用Symfony 3和fos_user。 这是注册码： $userManager = $this->get('fos_user.user_manager'); $user = $userManager->createUser(); $user->setUsername($username); $user->setPlainPassword($password); $user->setEmail($email); $role = "ROLE_USER"; $user->setRoles(array($role)); $user->setEnabled(true); $user->setName($name); $userManager->upd
I am trying to sent a Post Request to VendHQ Api using oauth2 auth method. I've the correct code, client_id, client_secret etc as It work fine in Postman but when I try to sent the same data using PHP curl, I get the error: Error 'error' => string 'invalid_request' (length=15) 'error_description' => string 'The request is missing a required parameter, includes an invalid parameter v
我正尝试使用oauth2 auth方法向PostHQ Api发送Post请求。 我有正确的代码，client_id，client_secret等，因为它在Postman中工作正常，但是当我尝试使用PHP curl发送相同的数据时，出现错误： 错误 'error' => string 'invalid_request' (length=15) 'error_description' => string 'The request is missing a required parameter, includes an invalid parameter value, includes a parameter more than once, or is ot
I've created a PHP class that envelopes filter_input functions to make our developer's life easier. To validate an HTML form with url , name and age fields, the code would be like that: $post = Filter::POST(); if ($post->validate_string('name') && $post->validate_integer('age')) { $url = $post->sanitize_url('url'); } It would be the same as: if (filter_input(INPU
我创建了一个包含filter_input函数的PHP类，以使我们的开发人员的工作更轻松。 要使用url ， name和age字段验证HTML表单，代码将如下所示： $post = Filter::POST(); if ($post->validate_string('name') && $post->validate_integer('age')) { $url = $post->sanitize_url('url'); } 这将与以下内容相同： if (filter_input(INPUT_POST,'name',FILTER_UNSAFE_RAW) && filter_input(INPUT_POST