I have a table that contains events, to list these events I loop through the event table, check the event type and look up it's value in it's specific table with it's eventId. At the moment this uses one query to get the 20 events and then up to 3 queries to get the data on those events. I currently have it coded procedurally but need to change it so that at the end it just returns
我有一个包含事件的表，列出这些事件，我循环遍历事件表，检查事件类型并使用它的eventId查找它的特定表中的值。 目前，这使用一个查询来获取20个事件，然后使用3个查询来获取这些事件的数据。 我目前使用程序编码，但需要对其进行更改，以便在最后它仅以数组形式返回数据。 下面是我需要实现的一个Pseduo代码示例： while(eventQuery): if commentQueryResult; $array .= commentQueryResult; if forumP
I have sent $data['items'] to my view which has created an array full of objects which I can echo with a foreach loop. foreach($items as $row) { echo $row->NAME . " - " . $row->COLOUR . "<br>"; } what I want to do is echo them to the browser in groups with the name of the colour as a header tag then start the loop for that colour. I'm just not sure what type of
我已经将$ data ['items']发送到了我的视图，该视图创建了一个充满对象的数组，我可以使用foreach循环来回显对象。 foreach($items as $row) { echo $row->NAME . " - " . $row->COLOUR . "<br>"; } 我想要做的就是用颜色名称作为标题标签将它们回显给浏览器，然后启动该颜色的循环。 我只是不确定要做什么类型的循环，或者我应该在循环中有循环吗？ 蓝色 - 项目1 - 项目3 红 - 项
Apparently, infinity and NaN are not a part of JSON specification, so this PHP code: $numbers = array(); $numbers ['positive_infinity'] = +INF; $numbers ['negative_infinity'] = -INF; $numbers ['not_a_number'] = NAN; $array_print = print_r ($numbers, true); $array_json = json_encode ($numbers); echo "nprint_r(): $array_print"; echo "njson_encode(): $array_json"; Produces this: PHP Warning: jso
显然，无限和NaN不是JSON规范的一部分，所以这个PHP代码： $numbers = array(); $numbers ['positive_infinity'] = +INF; $numbers ['negative_infinity'] = -INF; $numbers ['not_a_number'] = NAN; $array_print = print_r ($numbers, true); $array_json = json_encode ($numbers); echo "nprint_r(): $array_print"; echo "njson_encode(): $array_json"; 产生这个： PHP Warning: json_encode(): double INF does not co
Using CakePHP (On PHP 5.2.6) I do a list query on a table which returns an array like: Array ( [0] => None [3] => Value 1 [5] => Value 2 ) Since it's not a sequential array json_encode() encodes it to an object instead of a JSON array which I need for filling a Jeditable Select. PHP 5.2.6 does not support any additional parameters, so I can't force it to create an JSON en
使用CakePHP（在PHP 5.2.6上）我在一个返回如下数组的表上执行列表查询： 阵列（ [0] => None [3] => Value 1 [5] => Value 2 ） 由于它不是一个顺序数组，json_encode（）将它编码为一个对象，而不是一个JSON数组，我需要填充Jeditable Select。 PHP 5.2.6不支持任何附加参数，所以我不能强制它创建一个JSON编码数组。 我的问题，有谁知道我怎么能以一种干净的方式解决这个问题？ 请参阅http://docs.php.n
I have a web application that pulls data from my newly created JSON API. My static HTML pages dynamically calls the JSON API via JavaScript from the static HTML page. How do I restrict access to my JSON API so that only I (my website) can call from it? In case it helps, my API is something like: http://example.com/json/?var1=x&var2=y&var3=z... which generates the appropriate JSON ba
我有一个Web应用程序从我新创建的JSON API中提取数据。 我的静态HTML页面通过JavaScript从静态HTML页面动态调用JSON API。 我如何限制对我的JSON API的访问，以便只有我（我的网站）可以从它调用？ 如果有帮助，我的API类似于：http：//example.com/json/？var1 = x＆var2 = y＆var3 = z ...它根据查询生成适当的JSON。 我使用PHP来生成我的JSON结果...可以限制对JSON API的访问，就像检查$_SERVER['HTTP_REFERER
I have a PHP class I want to convert to a PHP extension. I checked some tutorials (tuxradar's writing extensions, php.net's extending php, and zend's extension writing) and it's a bit complicated. I found the article "How to write PHP extensions" ( ed note: site is defunct) and I wanted to know if it is possible to use this to make it grab a PHP class from a certain p
我有一个PHP类，我想要转换为PHP扩展。 我检查了一些教程（tuxradar的书写扩展，php.net的扩展php和zend的扩展写作），这有点复杂。 我找到了一篇文章“如何编写PHP扩展”（ 编者注：网站已经失效），我想知道是否有可能使用它来从特定路径获取PHP类（比如/home/website1/public_html/api/class.php ），执行它并返回类实例。 这样它可以在同一服务器上托管的其他网站中使用 - 每个网站都可以简单地调用该函数，并获得它自己
I've got a php script. Most of the time the script returns html, which is working fine, but on one occasion (parameter ?Format=XML) the script returns XML instead of HTML. Is there any way to change the returned mime type of the php output on the fly from text/html to text/xml or application/xml? header('Content-type: application/xml'); header()的PHP文档中提供了更多信息。 Set the Conten
我有一个PHP脚本。 大多数情况下脚本会返回html，但工作正常，但有一次（参数？Format = XML）脚本返回XML而不是HTML。 有没有什么办法可以将PHP输出的返回MIME类型从text / html更改为text / xml或application / xml？ header('Content-type: application/xml'); header()的PHP文档中提供了更多信息。 设置Content-Type标题： header('Content-Type: text/xml'); 尽管你应该使用“application / xml”来代替。 我会回答
How would you prevent a browser from timing out while a long process is running in php? We have a process which accepts a file upload and runs process on the file data. Sometimes this file can be very large with a lot of records, and in these cases the user gets a timeout error. I believe it is a browser timeout because the script is still running in the background and finishes successfully.
如何防止浏览器在php中运行很长的过程时超时？ 我们有一个接受文件上传并对文件数据运行进程的进程。 有时这个文件可能会有很多记录，并且在这些情况下用户会收到超时错误。 我相信这是浏览器超时，因为脚本仍在后台运行并成功完成。 我通常不用php工作（事实上，从来没有在解决这个网站问题），并想知道是否有一种简单的方法来防止浏览器在进程运行时超时。 大多数浏览器在开始接收数据后都不会超时。 因此，你所要做
I work in php, and the concept of interfaces seems to me a little useless here. From reading, I understand that interfaces are part of "design by contract", but without at least guaranteeing a return of a type of a particular kind, there really isn't any contract. It seems it's like a contract that reads, "We agree to do the following: '' " -- there are no te
我在PHP工作，接口的概念在这里似乎有点无用。 从阅读中我了解到接口是“按合同设计”的一部分，但是至少没有保证返回某种特定类型，实际上没有任何合同。 这看起来像是一个合同，上面写着：“我们同意做以下事情：''' - 协议没有条款。 如果我想保证一个对象有一个方法，它看起来并不像接口那样特别有用。 如果我尝试调用某个对象没有的方法，那么我会遇到致命错误，所以我很快发现该类没有具有该名称的方法。
spent a few hours trying to figure this out, but cannot for the life of me figure out what's going wrong. All I'm trying to do is load this: https://recruit.zoho.com/ats/EmbedResult.hr?jodigest=2cV.Sr2As6VxhLMxQGuTNij*g.Fb3J7ysduDs.AC9sU-&atslocale=en_GB&rawdata=json which I believe is json, into either javascript/jquery or php and use the data. I've looked into jsonp, f
花了几个小时试图弄清楚这一点，但不能为我的生活弄清楚发生了什么问题。 我所要做的就是加载这个： https://recruit.zoho.com/ats/EmbedResult.hr?jodigest=2cV.Sr2As6VxhLMxQGuTNij*g.Fb3J7ysduDs.AC9sU-&atslocale=en_GB&rawdata=json 我相信是json，到javascript / jQuery或PHP并使用数据。 我研究过jsonp，接下来是一些教程，使用一些演示作为模板，并且无法使上述数据正常工作。 如果任何人可以摆脱一些光