This question already has an answer here: PHP: Delete an element from an array 34 answers Try like this: foreach ($this->schs_raw as &$object) { if($object['AppService'] == "16295C0C51D8318C2") { unset($object); } } Eventually: foreach ($this->schs_raw as $k => $object) { if($object['AppService'] == "16295C0C51D8318C2") { unset($this->schs_raw[$k
这个问题在这里已经有了答案： PHP：从数组中删除一个元素34个答案 像这样尝试： foreach ($this->schs_raw as &$object) { if($object['AppService'] == "16295C0C51D8318C2") { unset($object); } } 最后： foreach ($this->schs_raw as $k => $object) { if($object['AppService'] == "16295C0C51D8318C2") { unset($this->schs_raw[$k]); } } array_filter会帮助（h
This question already has an answer here: PHP: Delete an element from an array 34 answers 要获得更清晰的代码，请使用array_filter函数http://fr2.php.net/array_filter $result = array_filter($result, function($row) { return $row['Department'] != 'br' || $row['Br_no'] === $row['emp_servicing_bnk']; }); 您可以使用unset()函数销毁数组中的特定键： foreach ($data as $key => $row) { if (/* you
这个问题在这里已经有了答案： PHP：从数组中删除一个元素34个答案 要获得更清晰的代码，请使用array_filter函数http://fr2.php.net/array_filter $result = array_filter($result, function($row) { return $row['Department'] != 'br' || $row['Br_no'] === $row['emp_servicing_bnk']; }); 您可以使用unset()函数销毁数组中的特定键： foreach ($data as $key => $row) { if (/* your condition*/) { un
This question already has an answer here: PHP: Delete an element from an array 34 answers you can try this: $ab = milk; $ba = apple; $ca = bread; $arr=array($ab, $ba, $ca); if (in_array($ba, $arr)) { unset($ba); } hope this may help you.. Yes it has a function. that it unset(). you can use it this way. $ab = milk; $ba = apple; $ca = bread; $array = array($ab, $ba, $ca); Then if you
这个问题在这里已经有了答案： PHP：从数组中删除一个元素34个答案 你可以试试这个： $ab = milk; $ba = apple; $ca = bread; $arr=array($ab, $ba, $ca); if (in_array($ba, $arr)) { unset($ba); } 希望这可以帮助你.. 是的，它有一个功能。 它unset（）。 你可以这样使用它。 $ab = milk; $ba = apple; $ca = bread; $array = array($ab, $ba, $ca); 然后，如果你想从上面的数组中删除$ ba 。 你只需按如下方
This question already has an answer here: PHP: Delete an element from an array 34 answers foreach($search as $item) { unset($item['tag']); echo json_encode($item); } 你可以通过unset（） 您可以在json_encode之前从数组中移除该元素foreach($search as $item) { unset($item['tag']); echo json_encode($item); }
这个问题在这里已经有了答案： PHP：从数组中删除一个元素34个答案 foreach($search as $item) { unset($item['tag']); echo json_encode($item); } 你可以通过unset（） 您可以在json_encode之前从数组中移除该元素foreach($search as $item) { unset($item['tag']); echo json_encode($item); }
This question already has an answer here: PHP: Delete an element from an array 34 answers 从阵列中删除它... $post = $_POST; unset($post['submit']); $data = array_values($post); // get only values $headers = array_keys($post); // keys are headers Drop the name from the Submit button in your html and instead of if(isset($_POST['submit'])) use if($_SERVER["REQUEST_METHOD"] == "POST") arra
这个问题在这里已经有了答案： PHP：从数组中删除一个元素34个答案 从阵列中删除它... $post = $_POST; unset($post['submit']); $data = array_values($post); // get only values $headers = array_keys($post); // keys are headers 从HTML中的提交按钮中删除名称 而不是 if(isset($_POST['submit'])) 使用 if($_SERVER["REQUEST_METHOD"] == "POST") array_pop()将删除数组的最后一个元素： $data = array_pop(arr
Possible Duplicate: How to delete an element from an array in php? I have a list of things, cars for instance $cars[0] = "audi"; $cars[1] = "saab"; $cars[2] = "volvo"; $cars[3] = "vw"; How do i delete "volvo" from the list? $volvoIndex = array_search('volvo', $cars); unset($cars[$volvoIndex]); you can do with unset unset($cars[2]); But after that you need to iterate array with
可能重复： 如何从PHP中的数组中删除元素？ 我有一些东西，例如汽车 $cars[0] = "audi"; $cars[1] = "saab"; $cars[2] = "volvo"; $cars[3] = "vw"; 我如何从列表中删除“沃尔沃”？ $volvoIndex = array_search('volvo', $cars); unset($cars[$volvoIndex]); 你可以用unset做 unset($cars[2]); 但之后，你需要用foreach迭代数组 您可以使用以下方法从数组中删除x元素 array_splice($cars,2,1) 这将删除数组中的第二
Possible Duplicate: How to delete an element from an array in php? For instance, Array( [0] => Array ( [0] => hello [1] => open ) [1] => Array ( [0] => good [1] => center ) [2] => Array ( [0] => hello [1] => close ) ) I want t
可能重复： 如何从PHP中的数组中删除元素？ 例如， Array( [0] => Array ( [0] => hello [1] => open ) [1] => Array ( [0] => good [1] => center ) [2] => Array ( [0] => hello [1] => close ) ) 我想删除操作后键值为1的元素： Array(
I use PHP to proceed latitude/longitude points in order to generate JS and displays points on an OSM Map. I would like to make a new track on the map when I have a pause au 10 minutes or more on the recording. My dataset as currently about 30000 records on about 10 differents tracks (some tracks have about 300 points, others have thousands). I encounter a performance issue with PHP. When th
我使用PHP来执行纬度/经度点以生成JS并在OSM Map上显示点。 当我在录音中暂停10分钟或更长时间时，我想在地图上制作一首新曲目。 我目前的数据集大约有10万个不同轨道上的30000条记录（有些轨道大约有300个点，其他轨道有数千个）。 我遇到了PHP的性能问题。 当环路聚集数百个点时，数据处理速度很快，但如果轨道有数千个点，则性能急剧下降。 这是每个曲目继续每个点所需的时间 +-----------------+-------------------
Possible Duplicate: Best methods to parse HTML with PHP I understand I should be using a html parser like php domdocument (http://docs.php.net/manual/en/domdocument.loadhtml.php) or tagsoup. How would I use php domdocument to extract text between specific tags, for example get text between h1,h2,h3,p,table? It seems I can only do this for one tag only with getelementbytagname. Is there a
可能重复： 用PHP解析HTML的最佳方法 我知道我应该使用像PHP domdocument（http://docs.php.net/manual/en/domdocument.loadhtml.php）或tagsoup这样的html解析器。 如何使用php domdocument提取特定标签之间的文本，例如在h1，h2，h3，p，table之间获取文本？ 看来我只能使用getelementbytagname为一个标签执行此操作。 是否有更好的html解析器用于这样的任务？ 或者我将如何循环访问php domdocument？ 你是正确的
Possible Duplicate: How to parse and process HTML with PHP? I know file_get_contents(url) method, but i wanted is that maybe using file_get_contents(url) at first to pull the contents of a page then is there something methods/functions that can extract or get a certain block of contents from the contents that you get using file_get_contents(url)? Here's a sample: so the code will be li
可能重复： 如何使用PHP解析和处理HTML？ 我知道file_get_contents（url）方法，但我想要的是，可能首先使用file_get_contents（url）来拉取页面的内容，然后是否有方法/函数可以从内容中提取或获取某些内容块使用file_get_contents（url）？ 这里有一个例子： 所以代码将如下所示： $pageContent = file_get_contents('http://www.pullcontentshere.com/'); 这将是$pageContent的输出 <html> <body> &