<testimonials> <testimonial id="4c050652f0c3e"> <nimi>John</nimi> <email>test@test.com</email> <text>Some text</text> <active>1</active> </testimonial> <testimonial id="4c05085e1cd4f"> <name>ats</name> <email>some@test.ee</email> &l
<testimonials> <testimonial id="4c050652f0c3e"> <nimi>John</nimi> <email>test@test.com</email> <text>Some text</text> <active>1</active> </testimonial> <testimonial id="4c05085e1cd4f"> <name>ats</name> <email>some@test.ee</email> &l
I'm writing a small script which generates some configuration for devices. I want to have separate file, where I'm storing configuration, and change some strings during printing the content of the configuration to the browser. How can I replace string in a line of the file with a variable from $_POST['somevariable']? -- Additional info -- I have several types of devices. I
我正在编写一个小脚本，为设备生成一些配置。 我想在单独的文件中存储配置，并在将配置内容打印到浏览器时更改一些字符串。 我怎样才能替换文件行中的字符串与变量从$ _POST ['somevariable']？ - 附加信息 - 我有几种类型的设备。 我想为每种类型的设备使用单独的配置模板文件。 如果有人想改变某些类型的设备的配置，他们会改变该文件而不是php文件。 但为了在php中使用这个模板，我必须在打印到网页之前
I'm quiet basic user of php & sql and wanted to do a shopping cart system I need your help for this script. The result is all the list from the table is displayed from the page and i wanted to to have a popup page where if you click one of the product it will display from the popup If you notice i added an anchor tag as this is the link which leads to a popup page the popup informatio
我很安静的PHP和SQL的基本用户，并希望做一个购物车系统，我需要你的帮助这个脚本。 结果是从表中显示的所有列表都显示在页面上，我希望有一个弹出页面，如果您点击某个产品，它将从弹出窗口中显示 如果您注意到我添加了一个锚标签，因为这是导致弹出页面的链接，弹出信息仍然在一个页面下： ` <table width="800px" border="0" cellpadding="0" cellspacing="7">
What function do you use to get innerHTML of a given DOMNode in the PHP DOM implementation? Can someone give reliable solution? Of course outerHTML will do too. Compare this updated variant with PHP Manual User Note #89718: <?php function DOMinnerHTML(DOMNode $element) { $innerHTML = ""; $children = $element->childNodes; foreach ($children as $child) {
您在PHP DOM实现中使用什么函数来获取给定DOMNode的innerHTML？ 有人能提供可靠的解决方案 outerHTML当然也会。 将此更新的变体与PHP手册用户注释＃89718进行比较： <?php function DOMinnerHTML(DOMNode $element) { $innerHTML = ""; $children = $element->childNodes; foreach ($children as $child) { $innerHTML .= $element->ownerDocument->saveHTML($child); }
I'm trying to replace video links inside a string - here's my code: $doc = new DOMDocument(); $doc->loadHTML($content); foreach ($doc->getElementsByTagName("a") as $link) { $url = $link->getAttribute("href"); if(strpos($url, ".flv")) { echo $link->outerHTML(); } } Unfortunately, outerHTML doesn't work when I'm trying to get the html code for
我试图替换字符串内的视频链接 - 这是我的代码： $doc = new DOMDocument(); $doc->loadHTML($content); foreach ($doc->getElementsByTagName("a") as $link) { $url = $link->getAttribute("href"); if(strpos($url, ".flv")) { echo $link->outerHTML(); } } 不幸的是，当我试图获取像<a href='http://www.myurl.com/video.flv'></a>这样的完整超链接的html代码
I have category ( title ) start with alphabetical A $sql = "select * from category_data WHERE category LIKE 'A%'"; And is working, but how I can select from database the category ( title ) which don't start with [AZ] or [1-9] just with symbols SELECT * FROM category_data WHERE ASCII(UPPER(LEFT(category,1))) IN(...) You can pass allowed ASCII characters in your IN clause. If you want to
我有类别（标题）以字母A开头 $sql = "select * from category_data WHERE category LIKE 'A%'"; 并且正在工作，但我如何从数据库中选择不以[AZ]或[1-9]开头的category ( title ) ，而是使用符号 SELECT * FROM category_data WHERE ASCII(UPPER(LEFT(category,1))) IN(...) 您可以在IN子句中传递允许的ASCII字符。 如果你想跳过特定的范围，你可以使用NOT BETWEEN x AND y; 你可以简单地使用MySQL的REGEXP函数SELECT * FR
I'm trying to get the timezone offset like this $zone = new DateTimeZone('Europe/Oslo'); $c = new DateTime(null, $zone); $offset = $c->getOffset(); $transitions = $zone->getTransitions(time(), time()); echo '<pre>',print_r($transitions),'</pre>'; which returns the offset in seconds which is fine. But this offset is not working correctly for timezone 'Pacific/Fiji'
我试图得到像这样的时区偏移量 $zone = new DateTimeZone('Europe/Oslo'); $c = new DateTime(null, $zone); $offset = $c->getOffset(); $transitions = $zone->getTransitions(time(), time()); echo '<pre>',print_r($transitions),'</pre>'; 它以秒为单位返回偏移量，这很好。 但是这个抵消在时区“太平洋/斐济”上无法正常工作。 对于斐济，它返回46800（即格林威治标准时间+13），这是不正确的，它应
I am working on a calendar application. In this users from different time-zones create/view events. I am thinking to follow below method to save event time in UTC and display them in user's local time. Note: user has their preferred timezone setting. To save event start time as UTC timestamp: $timezone = new DateTimeZone( $user_timezone_name ); $utcOffset = $timezone->getOffset( new
我正在处理日历应用程序。 来自不同时区的这些用户创建/查看事件。 我在考虑按照下面的方法保存UTC中的事件时间并将它们显示在用户的当地时间。 注意：用户有他们的首选时区设置。 将事件开始时间保存为UTC时间戳： $timezone = new DateTimeZone( $user_timezone_name ); $utcOffset = $timezone->getOffset( new DateTime( $event_start_time_string_local ) ); $event_start_timestamp_local = maketime( $event_star
I am storing time zone by offset-from-UTC for an application using this dropdown: <select id="timezone" name="timezone" > <option value="-12">[UTC - 12] Baker Island Time</option> <option value="-11">[UTC - 11] Niue Time, Samoa Standard Time</option> <option value="-10">[UTC - 10] Hawaii-Aleutian Standard Time, Cook Island Time</option> <option value=
我正在使用此下拉列表按偏移量从UTC存储时区： <select id="timezone" name="timezone" > <option value="-12">[UTC - 12] Baker Island Time</option> <option value="-11">[UTC - 11] Niue Time, Samoa Standard Time</option> <option value="-10">[UTC - 10] Hawaii-Aleutian Standard Time, Cook Island Time</option> <option value="-9.5">[UTC - 9:30] Marquesas Islan
I have a general question about dealing with daylight saving time. I guess its not really PHP specific, but I am writing in PHP, so I figure it wouldn't hurt to include it. I have a calendar app built using jquery fullcalendar. The user views events in their local timezone and my server stores them as UTC datetimes in mysql. (Other questions on stackoverflow suggest that this is the best
我有一个关于处理夏令时的一般问题。 我想它并不是真正的PHP特定的，但我用PHP编写，所以我认为包含它并没有什么坏处。 我有一个使用jquery fullcalendar构建的日历应用程序。 用户在本地时区查看事件，我的服务器将它们存储为mysql中的UTC日期时间。 （在stackoverflow上的其他问题表明，这是处理时区的最佳方式。）因此，每次用户保存或查看日历上的事件时都会进行转换。 这工作正常，但我很困惑如何最好地处理夏令时。