Check if string contains word (not a sentence string)

This question already has an answer here: How do I check if a string contains a specific word? 37 answers $stringtocheck = "Schiphol-Almere C./Hilversum/Utrecht C."; $searchfor = "Hilversum"; if (strpos($stringtocheck,$searchfor) !== false) { echo 'true'; }

检查字符串是否包含单词(不是一个句子字符串)

这个问题在这里已经有了答案: 如何检查一个字符串是否包含特定单词? 37个答案 $stringtocheck = "Schiphol-Almere C./Hilversum/Utrecht C."; $searchfor = "Hilversum"; if (strpos($stringtocheck,$searchfor) !== false) { echo 'true'; }

Check if word is inside a group of words

This question already has an answer here: How do I check if a string contains a specific word? 37 answers <?php $os = array("Mac", "NT", "Irix", "Linux"); if (in_array("Irix", $os)) { echo "Got Irix"; } if (in_array("mac", $os)) { echo "Got mac"; } ?> http://php.net/manual/en/function.in-array.php You can combine the in_array and explode functions echo ((in_array($search

检查单词是否在一组单词中

这个问题在这里已经有了答案: 如何检查一个字符串是否包含特定单词? 37个答案 <?php $os = array("Mac", "NT", "Irix", "Linux"); if (in_array("Irix", $os)) { echo "Got Irix"; } if (in_array("mac", $os)) { echo "Got mac"; } ?> http://php.net/manual/en/function.in-array.php 你可以结合in_array和explode函数 echo ((in_array($searchTerm, explode(",", $cities)))?"Yes":"No"); 或者

How to find if a variable contains certain character or not ? PHP

This question already has an answer here: How do I check if a string contains a specific word? 37 answers This will work: // use strpos() because strstr() uses more resources if(strpos("user input from search field", "-") === false) { // not found provides a boolean false so you NEED the === } else { // found can mean "found at position 0", "found at position 19", etc... } strpos()

如何找到一个变量是否包含某个字符? PHP

这个问题在这里已经有了答案: 如何检查一个字符串是否包含特定单词? 37个答案 这将工作: // use strpos() because strstr() uses more resources if(strpos("user input from search field", "-") === false) { // not found provides a boolean false so you NEED the === } else { // found can mean "found at position 0", "found at position 19", etc... } strpos() 什么不该做 if(!strpos("user in

PHP if not in string

This question already has an answer here: How do I check if a string contains a specific word? 37 answers I always use this: if (stristr($string, "string")) { //String exists within $string }else{ //String does not exist } http://www.php.net/stristr 尝试这个: if(strpos($string, 'String') !== false) { //string exist } else{ //string not exist }

PHP如果不在字符串中

这个问题在这里已经有了答案: 如何检查一个字符串是否包含特定单词? 37个答案 我总是使用这个: if (stristr($string, "string")) { //String exists within $string }else{ //String does not exist } http://www.php.net/stristr 尝试这个: if(strpos($string, 'String') !== false) { //string exist } else{ //string not exist }

Does array contain (part of) string?

This question already has an answer here: How do I check if a string contains a specific word? 37 answers Loop through the $forbiddennames array and use stripos to check if the given input string matches any of the items in the array: function is_forbidden($forbiddennames, $stringtocheck) { foreach ($forbiddennames as $name) { if (stripos($stringtocheck, $name) !== FALSE) {

数组是否包含(的一部分)字符串?

这个问题在这里已经有了答案: 如何检查一个字符串是否包含特定单词? 37个答案 循环访问$forbiddennames数组并使用stripos来检查给定的输入字符串是否与数组中的任何项匹配: function is_forbidden($forbiddennames, $stringtocheck) { foreach ($forbiddennames as $name) { if (stripos($stringtocheck, $name) !== FALSE) { return true; } } } 并像下面一样使用它: if(is_fo

How to check if a string contain any text

This question already has an answer here: How do I check if a string contains a specific word? 37 answers Use strpos $haystack = "foo bar baz"; $needle = "bar"; if( strpos( $haystack, $needle ) !== false ) { echo ""bar" exists in the haystack variable"; } In your case: if( strpos( $a, 'some text' ) !== false ) echo 'text'; Note that my use of the !== operator (instead of != false

如何检查一个字符串是否包含任何文本

这个问题在这里已经有了答案: 如何检查一个字符串是否包含特定单词? 37个答案 使用strpos $haystack = "foo bar baz"; $needle = "bar"; if( strpos( $haystack, $needle ) !== false ) { echo ""bar" exists in the haystack variable"; } 在你的情况下: if( strpos( $a, 'some text' ) !== false ) echo 'text'; 请注意,我使用!==运算符(而不是!= false或== true或甚至仅if( strpos( ... ) ) { )是由于P

About Mysql Fulltext Search

I have a table and some rows, i want do fulltext search but fulltext col without space. For Example: My MySQL Table: CREATE TABLE IF NOT EXISTS `members` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `username` varchar(255) NOT NULL DEFAULT '', `fulltextcol` varchar(10) NOT NULL DEFAULT '', PRIMARY KEY (`id`), FULLTEXT KEY `fulltextcol` (`fulltextcol`) ) ENGINE=MyISAM DEFAULT C

关于Mysql全文搜索

我有一个表和一些行,我想做全文搜索,但全文没有空格。 例如: 我的MySQL表: CREATE TABLE IF NOT EXISTS `members` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `username` varchar(255) NOT NULL DEFAULT '', `fulltextcol` varchar(10) NOT NULL DEFAULT '', PRIMARY KEY (`id`), FULLTEXT KEY `fulltextcol` (`fulltextcol`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=5 ; 插入: INS

MySQL fulltext search only works in BOOLEAN Mode. How get relevancy?

I want to search in Natural Language Mode to order results by relevancy, but my query only works with BOOLEAN Mode selector. If I use the query without BOOLEAN I get no results. Any idea why this does not work? Or idea how to get results by relevancy (most matched keywords first) with BOOELAN? My query: SELECT *, MATCH(md.keywords) AGAINST('$meta[keywords]' IN BOOLEAN MODE) AS score FROM m

MySQL全文搜索仅适用于BOOLEAN模式。 如何获得相关性?

我想在自然语言模式下搜索以按相关性排序,但我的查询仅适用于BOOLEAN模式选择器。 如果我使用没有BOOLEAN的查询,我不会得到任何结果。 任何想法为什么这不起作用? 或想法如何通过相关性(首先匹配最多的关键字)与BOOELAN得到结果? 我的查询: SELECT *, MATCH(md.keywords) AGAINST('$meta[keywords]' IN BOOLEAN MODE) AS score FROM meta_data AS md INNER JOIN sites AS si ON md.domain = si.domain &&

Bitwise operations on boolean values

From my knowledge, bitwise operators perform a check on all corresponding bits, as in: echo 64 | 32; //prints 96 echo 'a' & 'b'; //prints ` While conditional && and || operators perform operations on boolean values: echo (int)(true && false); //prints: 0 echo (int)(true || false); //prints: 1 When I (in my head) want to predict the result of a bitwise operation, I first

按位操作布尔值

据我所知,按位运算符会对所有相应的位进行检查,如下所示: echo 64 | 32; //prints 96 echo 'a' & 'b'; //prints ` 而条件&&和|| 运算符对布尔值执行操作: echo (int)(true && false); //prints: 0 echo (int)(true || false); //prints: 1 当我(在我的脑海中)想要预测按位运算的结果时,我首先将这些值转换为它们的二进制表示形式(这取决于数据类型)。 在此之后,我将它逐位比较,并将结果

Sending PHP variables back and forth between pages

I've created a registration form that successfully passes its variables from the registration page (go-gold.php) to a summary/verfication page (go-gold-summary.php). The data appears correctly on the second page. However, I want to able to use an image button to return back to the registration page, in case the user made an entry error. Going back, the original form should now be populate

在页面之间来回发送PHP变量

我创建了一个注册表单,成功将其变量从注册页面(go-gold.php)传递到摘要/验证页面(go-gold-summary.php)。 数据在第二页上正确显示。 但是,我希望能够使用图像按钮返回到注册页面,以防用户输入错误。 回过头来,原始表单现在应该填入首次输入的数据。 问题是我无法将第二页的数据重新发送/返回到第一页。 我的文本字段显示为空白。 我不想使用会话变量。 代码从整个页面被截断。 注册页面(go-gold.php): &l