I am trying to enable the .zip extension in PHP, but the function below returns false. if (!extension_loaded('zip')) { return false; } How do I enable the .zip extension with out using php.ini? Is it possible to enable using ini_set() ? Provided that you actually have the ZIP extension available on the server, you could use dl() to dynamically load it (<5.3). if (!extension_loaded('
我试图在PHP中启用.zip扩展，但下面的函数返回false。 if (!extension_loaded('zip')) { return false; } 如何使用php.ini启用.zip扩展？ 是否可以启用ini_set() ？ 假设您的服务器上实际上有ZIP扩展名，您可以使用dl()动态加载它（<5.3）。 if (!extension_loaded('zip')) { // Attempt to load the zip $prefix = (PHP_SHLIB_SUFFIX === 'dll') ? 'php_' : ''; dl($prefix . 'zip.' . PHP_SHLIB_SUFF
Given a credit card number and no additional information, what is the best way in PHP to determine whether or not it is a valid number? Right now I need something that will work with American Express, Discover, MasterCard, and Visa, but it might be helpful if it will also work with other types. There are three parts to the validation of the card number: PATTERN - does it match an issuers pa
给定一个信用卡号码并且没有附加信息，PHP中确定它是否是有效数字的最佳方法是什么？ 现在我需要一些能够与美国运通，Discover，MasterCard和Visa合作的东西，但如果它也可以与其他类型一起使用，它可能会有所帮助。 验证卡号有三个部分： PATTERN - 它是否符合发行者模式（例如VISA /万事达卡等） CHECKSUM - 它是否实际检查总和（例如，在“34”之后不只是13个随机数字，使其成为AMEX卡号） 真的存在 - 它实际上是否有
This is my regular expression code: "onlyLetterSp": { "regex": /^[a-zA-Z ']+$/, "alertText": "* Letters only" } How can I change this to allow English characters as well as Japanese? I found this link: http://www.localizingjapan.com/blog/2012/01/20/regular-expressions-for-japanese-text/ There are apparently a few different character sets for different types of Japanese. Hiragana
这是我的正则表达式代码： "onlyLetterSp": { "regex": /^[a-zA-Z ']+$/, "alertText": "* Letters only" } 我怎样才能改变这个以允许英文字符和日文？ 我发现这个链接： http://www.localizingjapan.com/blog/2012/01/20/regular-expressions-for-japanese-text/ 显然，针对不同类型的日语有几种不同的字符集。 例如平假名是： [x3041-x3096] 您必须寻找u正则表达式修饰符，它代表Unicode。 有了它，你可
Possible Duplicate: For each in a array. How to do that in javascript? Hey I was needing some help with finding a good for each equivalent from PHP to javascript. I've tried using jQuery.each() but I'm not sure I've done it correctly. Here is the code I've been needing to convert. I need to fix each foreach to javascript. if(calculate){ // got complete, calculate pos
可能重复： 对于数组中的每一个。 如何在JavaScript中做到这一点？ 嘿，我需要一些帮助，找到从PHP到JavaScript的每个等价物的好处。 我试过使用jQuery.each（），但我不确定我是否做得正确。 这是我一直需要转换的代码。 我需要修复每个foreach到javascript。 if(calculate){ // got complete, calculate possible solution // use decimals? Does this work in the form? foreach(values as valName1 =>
This question already has an answer here: Interpolation (double quoted string) of Associative Arrays in PHP 4 answers 有了数组和函数，你需要把curley括号： $jsql_ae3 = mysql_query("select products.formats from products where products.id='{$jrowa2['id']}'") or die(mysql_error()); When you use an array like this $jrowa2['id'] inside a string with double quotes, PHP you do interpolation and try
这个问题在这里已经有了答案： PHP 4中关联数组的插值（双引号字符串）的答案 有了数组和函数，你需要把curley括号： $jsql_ae3 = mysql_query("select products.formats from products where products.id='{$jrowa2['id']}'") or die(mysql_error()); 当你使用这样的数组 $jrowa2['id'] 在一个带双引号的字符串中，PHP会进行插值并尝试解释它，但在这种情况下，您不能使用围绕该键的简单引号，只需编写密钥（因为它已经在
echo "<OPTION value=$data2['product_id']>$data2['product_id']</OPTION>"; This gives me the following error: PHP Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING Can you help me out please? How do I fix this error? echo "<OPTION value=".$data2['product_id'].">".$data2['product_id']."</OPTION>"; Either
echo "<OPTION value=$data2['product_id']>$data2['product_id']</OPTION>"; 这给了我以下错误： PHP解析错误：语法错误，意外的T_ENCAPSED_AND_WHITESPACE，期望T_STRING或T_VARIABLE或T_NUM_STRING 你能帮我吗？ 我如何解决这个错误？ echo "<OPTION value=".$data2['product_id'].">".$data2['product_id']."</OPTION>"; 或 echo "<OPTION value=$data2[product_id]>$data2[product_id
I have been scripting PHP for for about 9 months now and im starting to run into a problem with my if conditions. This has never happened before. if ($reason != "9ee1e1f4fbf1"){ XXXXXXXXX } I even tried putting the 9ee1ef4fbf1 in parenthesis and that didnt work. i keep getting this: Parse error: syntax error, unexpected T_IF in /home/content/49/549/html/index.php on line 21 The problem
我一直在为php编写脚本大约9个月，并且即将开始遇到与我的条件有关的问题。 这从来没有发生过。 if ($reason != "9ee1e1f4fbf1"){ XXXXXXXXX } 我甚至试图将9ee1ef4fbf1放在括号内，并没有奏效。 我不断收到这个： Parse error: syntax error, unexpected T_IF in /home/content/49/549/html/index.php on line 21 问题出在if的上面 。 也许忘了分号？ 请在if语句前张贴行。 通常，当你在PHP中遇到unexpected ____
I'm doing this simple website, and I have run into this error: My function: <?php function user_exists($username) { $username = sanitize($username); $query = mysqli_query($connect, "SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username'"); return (mysqli_result($query, === 0) 1) ? true : false; } ?> My php error log: PHP Parse error: syntax error, unexp
我正在做这个简单的网站，我遇到了这个错误： 我的功能： <?php function user_exists($username) { $username = sanitize($username); $query = mysqli_query($connect, "SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username'"); return (mysqli_result($query, === 0) 1) ? true : false; } ?> 我的php错误日志： PHP Parse error: syntax error, unexpected '===' (T_IS_IDENTICA
<?php if(isset($_POST['zapisz'])) { $zapytanie_update = mysql_query("UPDATE `emotki` SET `kod` = '".$_POST['kod']."',`opis` = '".$_POST['opis']."', `glowna` = '".$_POST['glowna']."' WHERE id= $id"); echo 'Emotka zapisana.<br/><a href="index.php">« Powrót</a>'; } $usun = $_POST['usun']; if(isset($usun == 1) { $usuwaj = mysql_q
<?php if(isset($_POST['zapisz'])) { $zapytanie_update = mysql_query("UPDATE `emotki` SET `kod` = '".$_POST['kod']."',`opis` = '".$_POST['opis']."', `glowna` = '".$_POST['glowna']."' WHERE id= $id"); echo 'Emotka zapisana.<br/><a href="index.php">« Powrót</a>'; } $usun = $_POST['usun']; if(isset($usun == 1) { $usuwaj = mysql_q
I have a textbox that is an optional field for users to enter a number in to. If there is a number in there, I want to check to make sure it is less than 500 and then do something with it. Here is what I am currently doing: if($textbox!="" && <=500) { //action here } I tried replacing && with andif but still get an error Parse error: syntax error, unexpected T_IS_SMALLER_O
我有一个文本框是用户输入数字的可选字段。 如果在那里有一个号码，我想检查一下，确保它小于500，然后用它做点什么。 这是我目前正在做的事情： if($textbox!="" && <=500) { //action here } 我尝试使用andif替换&&但仍然出现错误解析错误：语法错误，意外的T_IS_SMALLER_OR_EQUAL 最简单的方法是什么？ 你需要在这两个语句中使用变量preg_match（'/ d /'，$ textbox）== 1将确保它是一个i