How do I allow square brackets in my url in Codeigniter

I have a url: "http://example.com/some-var-[2009]-to-[2014]" When I hit the same I get: How do I fix the same ? I want to allow square brackets [2009] & [2014] in my url.

如何在Codeigniter的URL中允许方括号

我有一个网址: "http://example.com/some-var-[2009]-to-[2014]" 当我碰到同样的东西时,我会得到: 我如何解决这个问题? 我想在我的网址中允许方括号[2009]和[2014]。

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I am following along with this post Change the Dashboard Graph in version 1.7/1.12 of Magento to allow the sales of "processing" orders to show up on the dashboard graph. My files are below and within the right directories as well as showing up as active in config>advanced. I have also reindexed, refreshed cache, and refreshed lifetime statistics. I am seeing no errors in the logs

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php parse Syntax error T

This question already has an answer here: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING 4 answers PHP parse/syntax errors; and how to solve them? 13 answers To solve your current issue, remove the single quotes from your $_FILES array: mysqli_query($db_connect, "INSERT INTO `product` (`pname`, `pid`, `disc`, `price`, `size`, `tage`,

php parse语法错误T

这个问题在这里已经有了答案: 语法错误,意外的T_ENCAPSED_AND_WHITESPACE,期望T_STRING或T_VARIABLE或T_NUM_STRING 4个答案 PHP解析/语法错误; 以及如何解决它们? 13个答案 要解决当前的问题,请从$_FILES数组中删除单引号: mysqli_query($db_connect, "INSERT INTO `product` (`pname`, `pid`, `disc`, `price`, `size`, `tage`, `remarks`, `catid`, `img1`, `img2`, `img3`) values('$_POST[pna

SESSION['ye']";

This question already has an answer here: PHP parse/syntax errors; and how to solve them? 13 answers When interpolating array items into a string you need to use the complex interpolation syntax (wrap it in {} ): $sql = "SELECT DISTINCT `sem` from `{$_SESSION['ye']}`"; It is generally simpler to just save the value to an auxiliary variable. It can make your code easier to read: $ye = $

SESSION [ '你们']“;

这个问题在这里已经有了答案: PHP解析/语法错误; 以及如何解决它们? 13个答案 将数组项插入字符串时,需要使用复杂插值语法(将其包装在{} ): $sql = "SELECT DISTINCT `sem` from `{$_SESSION['ye']}`"; 将值保存到辅助变量通常比较简单。 它可以使你的代码更易于阅读: $ye = $_SESSION['ye']; $sql = "SELECT DISTINCT `sem` from `$ye`"; 首先将表格名称分配给变量 $tableName = $_SESSION['ye']; 然后在

How to fix "Unexpected T

This question already has an answer here: Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE) [duplicate] 1 answer Try this one $link = mysql_query(sprintf( "SELECT * FROM users WHERE id='%s' AND password='%s'", mysql_real_escape_string($_SESSION['MM_Username']), mysql_real_escape_string($_SESSION['MM_PASSWORD']), )); It will help you to avoid sql-injec

如何解决“意外的T

这个问题在这里已经有了答案: 解析错误:语法错误,意外''(T_ENCAPSED_AND_WHITESPACE)[duplicate] 1个答案 试试这个 $link = mysql_query(sprintf( "SELECT * FROM users WHERE id='%s' AND password='%s'", mysql_real_escape_string($_SESSION['MM_Username']), mysql_real_escape_string($_SESSION['MM_PASSWORD']), )); 它会帮助你避免sql注入。 请不要使用mysql_函数,因为它在注释中提到

Parse Error: Syntax Error,whitespace error

I get a error like Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) for the below code.. $string="<b style=margin-left:30px;font-size:12px;font-weight:bold>"."< a href='tracklocation.php?deviceid=<?=$row['device_id']?>&vno=<?=$row['vehicle_no']?>'>". $row

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我收到一个错误 解析错误:语法错误,意外的''(T_ENCAPSED_AND_WHITESPACE),等待标识符(T_STRING)或变量(T_VARIABLE)或编号(T_NUM_STRING) 为下面的代码.. $string="<b style=margin-left:30px;font-size:12px;font-weight:bold>"."< a href='tracklocation.php?deviceid=<?=$row['device_id']?>&vno=<?=$row['vehicle_no']?>'>". $row['vehicle_no']."</br> "; 这应

How to get data from database and echo on php page?

How to get the date from database and echo on PHP page? $query = $pdo->prepare('SELECT * FROM shop WHERE shopname=:shopname'); $query->bindParam(':shopname', $shopname, PDO::PARAM_STR); $query->execute(); $result = $query->fetchAll(PDO::FETCH_ASSOC); echo "$result['shopid']"; This gives me the following error: Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITE

如何从数据库中获取数据并在php页面上回显?

如何从数据库中获取日期并在PHP页面上回显? $query = $pdo->prepare('SELECT * FROM shop WHERE shopname=:shopname'); $query->bindParam(':shopname', $shopname, PDO::PARAM_STR); $query->execute(); $result = $query->fetchAll(PDO::FETCH_ASSOC); echo "$result['shopid']"; 这给了我以下错误: 解析错误:语法错误,意外的''(T_ENCAPSED_AND_WHITESPACE),等待标识符(T_STRING)或变量(T_

parse error mysql 2 variables

my code is this $newentry = " UPDATE url FROM auction_media JOIN auctions ON auction_media.auction_id = auctions.auction_id SET media_url = '$row2['url']/$match[0]' WHERE media_type = '3'"; the error i am getting is Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRI

解析错误mysql 2个变量

我的代码是这样的 $newentry = " UPDATE url FROM auction_media JOIN auctions ON auction_media.auction_id = auctions.auction_id SET media_url = '$row2['url']/$match[0]' WHERE media_type = '3'"; 我得到的错误是 解析错误:语法错误,意外的T_ENCAPSED_AND_WHITESPACE,期望T_STRING或T_VARIABLE或T_NUM_STRING $newentry = "UPDATE `url` FR

Parse error received on unexpected T

I am recieving an error on the first line of code below which states: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in ... on line 184 How can this error be fixed in code below: $assessmentform = "<form action='echo htmlentities($_SERVER['PHP_SELF']);' method='post'> <p>Assessments: echo $sessionHTML; </p>

在意外的T上收到解析错误

我在下面的第一行代码中收到错误,其中声明: 解析错误:语法错误,意外的T_ENCAPSED_AND_WHITESPACE,期望T_STRING或T_VARIABLE或T_NUM_STRING in ... on line 184 如何在下面的代码中解决这个错误: $assessmentform = "<form action='echo htmlentities($_SERVER['PHP_SELF']);' method='post'> <p>Assessments: echo $sessionHTML; </p> <p><input id='sessionSubmit' type='submit' value='

Adding a link in an array in PHP using href

This question already has an answer here: PHP parse/syntax errors; and how to solve them? 13 answers No need of the PHP tags. Try with - $table->data[] = array( 'CSE1010', 'Intro To IT', 'Bsc Acc, Mgt', '<a href="edit.php"><u>Edit</u></a>' ); You should use something like this in Moodle $editurl = new moodle_url('/pluginfolder/plugin

使用href在PHP中添加一个链接

这个问题在这里已经有了答案: PHP解析/语法错误; 以及如何解决它们? 13个答案 不需要PHP标签。 试用 - $table->data[] = array( 'CSE1010', 'Intro To IT', 'Bsc Acc, Mgt', '<a href="edit.php"><u>Edit</u></a>' ); 你应该在Moodle中使用这样的东西 $editurl = new moodle_url('/pluginfolder/pluginname/edit.php', array('id' => $id)); $editlink =