PDO, Mysql and native prepared statements

The understanding of PDO that I've had up till now is that PDO will use real prepared statements where it can, and emulate them where it can't. I also understood that where mysql was concerned, real prepared statements would be used provided you were communicating with a version of mysql that supported them. In fact the PHP manual page for the MySQL PDO driver says as much. http://php

PDO,Mysql和本地准备的语句

到目前为止,我对PDO的理解是,PDO将使用真实的准备好的语句,并在无法使用的地方模拟它们。 我还了解到,在涉及mysql的情况下,如果您正在与支持它们的mysql版本进行通信,则会使用真实的准备好的语句。 事实上,MySQL PDO驱动程序的PHP手册页也是如此。 http://php.net/manual/en/ref.pdo-mysql.php 然而,在另一个SO问题上,我正在帮助如何用数组中的元素替换char的所有事件? ,有人发表评论说这不是真的,事实上PDO

How do I insert NULL values using PDO?

I'm using this code and I'm beyond frustration: try { $dbh = new PDO('mysql:dbname=' . DB . ';host=' . HOST, USER, PASS); $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh->setAttribute(PDO::MYSQL_ATTR_INIT_COMMAND, "SET NAMES 'utf8'"); } catch(PDOException $e) { ... } $stmt = $dbh->prepare('INSERT INTO table(v1, v2, ...) VALUES(:v1, :v2, ...)')

我如何使用PDO插入NULL值?

我使用这段代码,我无法忍受: try { $dbh = new PDO('mysql:dbname=' . DB . ';host=' . HOST, USER, PASS); $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh->setAttribute(PDO::MYSQL_ATTR_INIT_COMMAND, "SET NAMES 'utf8'"); } catch(PDOException $e) { ... } $stmt = $dbh->prepare('INSERT INTO table(v1, v2, ...) VALUES(:v1, :v2, ...)'); $stmt->bindParam(':v1'

Executing multiple join with expressions on Zend Framework 2

Actually I'm working on a project and I'm looking on how Zend Framework 2 handle complex queries (expecially on how to join n:m tables and how to use GROUP_CONCAT and other functions). Do you know the best practice to execute this query: SELECT o. * , x.group_one, x.group_two FROM table_one AS o LEFT JOIN ( SELECT r.fk1, GROUP_CONCAT( t.field_one ) AS group_one, GROUP_CONCAT( t.field_tw

在Zend Framework 2上执行与表达式的多重连接

其实我正在开发一个项目,我正在研究Zend Framework 2如何处理复杂的查询(特别是如何连接n:m表以及如何使用GROUP_CONCAT和其他函数)。 你知道执行这个查询的最佳实践: SELECT o. * , x.group_one, x.group_two FROM table_one AS o LEFT JOIN ( SELECT r.fk1, GROUP_CONCAT( t.field_one ) AS group_one, GROUP_CONCAT( t.field_two ) AS group_two FROM table_three AS r INNER JOIN table_two AS t ON r.fk2 = t.id GROUP

How to gradually convert a site over to CodeIgniter?

I've been doing a lot of research in regards to OO and MVC for PHP and have nearly made a choice to move to CodeIgniter for an existing large-scale website I manage. I feel that using an OO+MVC environment has a huge organizational and performance advantages and hopefully improved developing speed compared to the existing functional/procedural structure the site uses now. However, due to t

如何逐步将网站转换为CodeIgniter?

对于面向OO和MVC的PHP,我一直在做很多研究,并且几乎可以选择转移到CodeIgniter来管理我现有的大型网站。 我觉得使用OO + MVC环境具有巨大的组织和性能优势,并希望与现在使用的现有功能/程序结构相比,提高了开发速度。 但是,由于网站的规模庞大,我想逐渐将代码转移到CodeIgniter的结构中,从而有一个过渡时间段,其中部分网站位于CI中,而其他网站则位于旧式。 对于从代码结构的角度来看这样做的最佳方式,是否有任何

PHP MySQL for permutations on MySQL Table

I have a mysql table with 7 columns, on which with each row contains integer values. I have a simple site which receives values from the user and I have to try to see if the values sent by the user match or are similiar to any of the rows in the table. So the user writes eg 1 2 3 4 5 6 7 as input. I have to find out if any of the rows in my table are similar to it without order. So 1 2 3 4

PHP MySQL用于MySQL表中的排列

我有一个包含7列的mysql表,每行包含整数值。 我有一个简单的网站接收用户的值,我必须尝试查看用户发送的值是否与表中的任何行匹配或相似。 因此,用户将例如1 2 3 4 5 6 7写入为输入。 我必须查明我的表中的任何行是否与没有订单的行类似。 所以1 2 3 4 5 6 7 = 7 6 5 4 3 2 1等等。 我的表格包含40,000多行数据。 我还必须看到,如果它们共享至少5 , 6或7中共同的数字。 这意味着使用排列来找到所有可能的组合。

PHP script does not run as cron job on Ubuntu Server

I've written a php script that creates a backup of a mysql database and set it to run daily using crontab on Ubuntu server, but the script is never executed (at least so it seems). The script is called backup.php. It generates a backup (sql within a gz archive) and stores it in folder /backup. It adds a few lines of text to /backup/log.txt. The script is called in crontab for root use

PHP脚本不能在Ubuntu服务器上作为cron作业运行

我写了一个php脚本,创建一个mysql数据库的备份,并将其设置为每天在Ubuntu服务器上使用crontab运行,但脚本从不执行(至少看起来如此)。 该脚本称为backup.php。 它会生成一个备份(gz归档中的sql)并将其存储在文件夹/备份中。 它在/backup/log.txt中添加了几行文本。 在crontab中为root用户调用脚本(sudo crontab -e): * * * * * php -f /var/www/cmdb/backup.php (时间需要调整,但这是出于测试目的。) 什

Timezones and cron

I have a MySQL database containing details of shops in different time zones. The timezone of each store is stored in iana format and the MySQL datetimes are stored in UTC. I wish to execute some php code at the end of the day for each shop. This is how I am thinking to approach this but is there a better way? Set a cron to run hourly at xx:59:59. Get the current date at the top of the ph

时区和克朗

我有一个MySQL数据库,其中包含不同时区的商店细节。 每个商店的时区以iana格式存储,并且MySQL日期时间以UTC存储。 我希望在每个商店的一天结束时执行一些php代码。 这就是我正在考虑的方法,但有没有更好的方法? 设置一个cron在xx:59:59每小时运行一次。 获取php脚本顶部的当前日期。 脚本是否保证在23:59:59得到正确的日期? 使用SQL查询返回当天结束时的所有商店。 我不知道如何在查询中检查这一点? 对这

Cron Job to rename web pages

First, let me say that I know nothing about Cron Jobs or PHP files, so please keep my newbie status in mind if you are kind enough to reply - (use small words and speak slowly!) I am the webmaster for our organization's site, and I am trying to do something which should be simple, yet time consuming: Take the main web page on our site and automatically update it during the Thanksgiving and

Cron作业重命名网页

首先,让我说我对Cron Jobs或PHP文件一无所知,所以如果您足够回复,请记住我的新手状态 - (使用小词并慢慢说!) 我是我们组织网站的网站管理员,我正在尝试做一些应该简单而又耗时的事情:在我们网站的主网页上,并在感恩节和圣诞节假期期间自动更新它。 我已经创建了我需要的特定网页,并将它们上传到了GoDaddy服务器,但我实在没有时间按照日期的方法进入并手动重命名这些网页; 我被告知Cron Job只是用来自动保存现有页

Skip autoload files generation in composer?

So - I have a simple PCR0 auto-loader in my bootstrap.php, that should load any PCR0 compatible library class from vendors directory... spl_autoload_register( function( $classname ) { $path = preg_match( '/\\/', $classname ) ? str_replace( '\', DIRECTORY_SEPARATOR, $classname ) : str_replace( '_', DIRECTORY_SEPARATOR, $classname ); $file = VENDORS_PATH . DIRECTORY_SEPARATOR . $p

在作曲家中跳过自动载入文件的生成?

所以 - 我的bootstrap.php中有一个简单的PCR0自动加载程序,它应该从供应商目录加载任何PCR0兼容的库类... spl_autoload_register( function( $classname ) { $path = preg_match( '/\\/', $classname ) ? str_replace( '\', DIRECTORY_SEPARATOR, $classname ) : str_replace( '_', DIRECTORY_SEPARATOR, $classname ); $file = VENDORS_PATH . DIRECTORY_SEPARATOR . $path . '.php'; if ( file_exists(

exclude private property from print

Basically I am using Code Igniter, and the Code Igniter base class is huge, when I print_r some of my objects they have the base class embedded inside them. this makes it a pain to get the information I actually wanted (the rest of the properties). So, I am wondering if there is a way I can hide, or remove the base class object? I have tried clone $object; unset($object->ci); print_r($ob

排除私人财产印刷

基本上我使用的是代码点火器,而代码点火器的基类是巨大的,当我print_r我的一些对象,他们的基类嵌入其中。 这让我很难得到我实际需要的信息(其余属性)。 所以,我想知道是否有一种方法可以隐藏或删除基类对象? 我努力了 clone $object; unset($object->ci); print_r($object); 但当然,慈属性是私人的。 我用于倾销的实际功能是: /** * Outputs the given variables with formatting and location. Huge prop