This question already has an answer here: How do you access the matched groups in a JavaScript regular expression? 14 answers 您可以使用匹配功能。 > var str = "My name is Derek Last Name" undefined > str.match(/My name is (.+)/)[1] 'Derek Last Name'
这个问题在这里已经有了答案： 如何访问JavaScript正则表达式中的匹配组？ 14个答案 您可以使用匹配功能。 > var str = "My name is Derek Last Name" undefined > str.match(/My name is (.+)/)[1] 'Derek Last Name'
This question already has an answer here: How do you access the matched groups in a JavaScript regular expression? 14 answers You have to use regex.exec() instead of .match() . Then you can access the matching groups as an ordinary array: var text = $('.text').html(); var regex = new RegExp('Concept number 1:(.*?)<br>'); var matches = regex.exec(text); console.log(matches[1]);&l
这个问题在这里已经有了答案： 如何访问JavaScript正则表达式中的匹配组？ 14个答案 您必须使用regex.exec()而不是.match() 。 然后您可以像普通数组那样访问匹配的组： var text = $('.text').html(); var regex = new RegExp('Concept number 1:(.*?)<br>'); var matches = regex.exec(text); console.log(matches[1]);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&g
This question already has an answer here: How do you access the matched groups in a JavaScript regular expression? 14 answers In order to work with subpatterns, there is no easy shortcut. Instead, you have to repeatedly execute the regex on the string and collect the subpattern you want. Something like this: var text = "do[A]and[B]", regexp = /[(w+)]/g, result = [], match; while(
这个问题在这里已经有了答案： 如何访问JavaScript正则表达式中的匹配组？ 14个答案 为了与子模式一起工作，没有简单的捷径。 相反，你必须重复执行字符串的正则表达式并收集你想要的子模式。 像这样的东西： var text = "do[A]and[B]", regexp = /[(w+)]/g, result = [], match; while(match = regexp.exec(text)) { result.push(match[1]); } 对于这种特殊情况，你不需要捕获组： >>> "do[A]an
This question already has an answer here: How do you access the matched groups in a JavaScript regular expression? 14 answers Alex already gave you the answer: str.match(/number:s+(d+)$/i)[1] , which means the result at the index of 1. That index in the array is generated by the usage of the () in your regex. The first index (0) is the answer you've been getting.
这个问题在这里已经有了答案： 如何访问JavaScript正则表达式中的匹配组？ 14个答案 Alex已经给出了答案： str.match(/number:s+(d+)$/i)[1] ，表示索引为1的结果。该数组中的索引是由()在你的正则表达式中。 第一个索引（0）是你得到的答案。
This question already has an answer here: How do you access the matched groups in a JavaScript regular expression? 14 answers As per MDN docs : If the regular expression does not include the g flag, returns the same result as RegExp.exec(). The returned Array has an extra input property, which contains the original string that was parsed. In addition, it has an index property, which repr
这个问题在这里已经有了答案： 如何访问JavaScript正则表达式中的匹配组？ 14个答案 根据MDN文档： 如果正则表达式不包含g标志，则返回与RegExp.exec（）相同的结果。 返回的数组有一个额外的输入属性，其中包含被解析的原始字符串。 此外，它还有一个索引属性，它表示字符串中匹配的从零开始的索引。 如果正则表达式包含g标志，则该方法将返回一个包含所有匹配的子字符串而非匹配对象的数组。 被捕获的组不被返回。
This question already has an answer here: How do you access the matched groups in a JavaScript regular expression? 14 answers I believe this is what you're trying to do: How do you access the matched groups in a JavaScript regular expression? Let me know if that helps. Use the exec function of the RegExp object. For that, you'll have to change the syntax to the following: va
这个问题在这里已经有了答案： 如何访问JavaScript正则表达式中的匹配组？ 14个答案 我相信这是你想要做的事情： 如何访问JavaScript正则表达式中的匹配组？ 让我知道这是否有帮助。 使用RegExp对象的exec函数。 为此，您必须将语法更改为以下内容： var pQe = /(^[a-z ... {0,2})/g.exec(inputText) 返回数组的元素1将包含匹配的第一个元素，元素2将包含第二个元素，依此类推。 如果字符串与正则表达式不匹配，
This question already has an answer here: How do you access the matched groups in a JavaScript regular expression? 14 answers 看到这个问题： txt = "Local residents o1__have called g__in o22__with reports..."; var regex = /o([0-9]+)__/g var matches = []; var match = regex.exec(txt); while (match != null) { matches.push(match[1]); match = regex.exec(txt); } alert(matches); You need to
这个问题在这里已经有了答案： 如何访问JavaScript正则表达式中的匹配组？ 14个答案 看到这个问题： txt = "Local residents o1__have called g__in o22__with reports..."; var regex = /o([0-9]+)__/g var matches = []; var match = regex.exec(txt); while (match != null) { matches.push(match[1]); match = regex.exec(txt); } alert(matches); 您需要在正则表达式对象上使用.exec() ，并使用g标志重复调用
What can I use for a JavasScript regular expression to match numbers up to two decimal places? Valid Examples: 123.22 3 22 654 9292929292.12 0.21 3.1 Invalid Examples: 221.1232 4.23332 12.763 如果前导零在01.23和000.2中无效，那么^((?:0|[1-9]d*)(?:.d{1,2})?)$ 您可以使用/^d+(?:.d{1,2})?$/ var re = /^d+(?:.d{1,2})?$/; console.log( re.test('123.22'), re.test('221.1232
我可以使用JavasScript正则表达式来匹配多达两位小数的数字吗？ 有效的例子： 123.22 3 22 654 9292929292.12 0.21 3.1 无效示例： 221.1232 4.23332 12.763 如果前导零在01.23和000.2中无效，那么^((?:0|[1-9]d*)(?:.d{1,2})?)$ 您可以使用/^d+(?:.d{1,2})?$/ var re = /^d+(?:.d{1,2})?$/; console.log( re.test('123.22'), re.test('221.1232') )
I need regex to validate a number that could contain thousand separators or decimals using javascript. Max value being 9,999,999.99 Min value 0.01 Other valid values: 11,111 11.1 1,111.11 INVALID values: 1111 1111,11 ,111 111, I've searched all over with no joy. /^d{1,3}(,d{3})*(.d+)?$/ About the minimum and maximum values... Well, I wouldn't do it with a regex, but you can add loo
我需要使用正则表达式来验证可能包含千位分隔符或使用javascript的小数的数字。 最大值为9,999,999.99最小值0.01其他有效值： 11,111 11.1 1,111.11 无效值： 1111 1111,11 ,111 111, 我已经无所顾忌地搜遍了。 /^d{1,3}(,d{3})*(.d+)?$/ 关于最小值和最大值...呃，我不会用正则表达式来做，但是你可以在开头添加lookahead： /^(?!0+.00)(?=.{1,9}(.|$))d{1,3}(,d{3})*(.d+)?$/ 注意：这允许0,999.00 ，所以您可能想要
This question already has an answer here: Why does a RegExp with global flag give wrong results? 5 answers Ok, i see it now. The key to your problem is the use of the g (global match) flag: when this is specified for a regex, it will be set up such that it can be executed multiple times, beginning each time at the place where it left off last time. It keeps a "bookmark" of sorts
这个问题在这里已经有了答案： 为什么带有全局标志的RegExp会给出错误的结果？ 5个答案 好的，我现在看到它。 解决问题的关键是使用g （全局匹配）标志：当为正则表达式指定时，它将被设置为可以多次执行，每次从它最后一次停止的地方开始执行时间。 它在lastIndex属性中保存了一系列“书签”： var testRegex = /blah/ig; // logs: true 4 console.log(testRegex.test("blah blah"), testRegex.lastIndex); // logs: true