JQuery remove styles added

I am new to Javascript, I am using Backbone So I add a style like this(to a link when its clicked) $(eventC.target.parentNode).css('border', '1px solid red'); I want the previous link to be cleared of the red border I added when I click on new link I looked at link below jQuery - remove style added with .css() function So in essence I want to do this: $(OLDLINK).css('border', 'none');

JQuery删除添加的样式

我是Javascript新手,我使用骨干所以我添加这样的风格(点击时链接到一个链接) $(eventC.target.parentNode).css('border', '1px solid red'); 我希望前面的链接清除我点击新链接时添加的红色边框 我查看了jQuery下的链接 - 使用.css()函数添加的删除样式 所以本质上我想这样做: $(OLDLINK).css('border', 'none'); $(NewLINK).css('border', '1px solid red'); 我从骨干中获得的事件 有没有简单的方法来做到

grid, JS

In my HTML, I have one parent div and have 25 div's inside it. <div class="container> <div class="faces"></div> <div class="faces"></div> <div class="faces"></div> . . . . . </div> I'm using CSS grids .container { display: grid; grid-template-columns: repeat(5, auto); margin: 2% auto; width: 750px; grid

网格,JS

在我的HTML中,我有一个父div,里面有25个div。 <div class="container> <div class="faces"></div> <div class="faces"></div> <div class="faces"></div> . . . . . </div> 我正在使用CSS网格 .container { display: grid; grid-template-columns: repeat(5, auto); margin: 2% auto; width: 750px; grid-gap: 1px; } .container >

How to wait for effect queue to complete in jQuery call sequence

I am looking for some function that: would be able to wait for all effects in the queue to finish could be used in the classical jQuery call sequence Example: I want to do some animations and then some operations after they finish: $('.obs_list') .delay(500) .animate({ 'background-color' : '#ffcc33' }, 200) .delay(1000) .animate({ 'background-color' : 'transparent' }, 200

如何等待效果队列在jQuery调用序列中完成

我正在寻找一些功能: 将能够等待队列中的所有效果完成 可以用在经典的jQuery调用序列中 例: 我想做一些动画,然后完成一些操作: $('.obs_list') .delay(500) .animate({ 'background-color' : '#ffcc33' }, 200) .delay(1000) .animate({ 'background-color' : 'transparent' }, 2000) .THE_FUNCTION_I_AM_LOOKING_FOR() .css({ 'color' : 'red' }) // this should come *after* the effects above

Overwrite a css rule using javascript or jquery

Is it possible to overwrite a css rule using jquery or javascript? Let's say I have a table, with a bunch of rows, and each row holds a specific type of data. Each row (tr) has a class added to it, so we can differentiate between the data types it is holding. For this example let's say the rows, with class "names" holds information about persons, and the rows with class &qu

使用javascript或jquery覆盖一个css规则

是否有可能覆盖使用jQuery或JavaScript的CSS规则? 比方说,我有一个表,有一堆行,每行都有一个特定类型的数据。 每行(tr)都添加了一个类,所以我们可以区分它所持有的数据类型。 对于这个例子,我们假设行的类名为“names”,保存有关人员的信息,而类“company”的行保存有关公司的信息。 假设我们的桌子上方有一个过滤器,我们可以在桌子上隐藏并显示所有公司或人员。 当我们选择一个复选框时,我们要么将特定行的显示

Best way to dynamically add and remove style on elements

I am using mouseenter and mouseleave events on some elements to change their appearance. I am able to do so using either of the following two strategies: $(this).css('someProperty','someValue') to add and then $(this).removeAttr('style') to remove $(this).addClass('someClass') to add and then $(this).removeClass('someClass') to remove What is the bes

动态添加和删除元素样式的最佳方法

我在一些元素上使用mouseenter和mouseleave事件来改变它们的外观。 我可以使用以下两种策略中的任何一种来做到这一点: $(this).css('someProperty','someValue')添加,然后$(this).removeAttr('style')删除 $(this).addClass('someClass')添加,然后$(this).removeClass('someClass')删除 最好的办法是什么? 绝对选项2.样式应该在样式表中定义。 还有toggleClass ,如果它

Changing color back to default in CSS and Jquery

This question already has an answer here: How can I remove a style added with .css() function? 16 answers 在应用css之前重置所有其他li元素$('li').on('click', function() { $('li').css('color', '');//WIll remove `color` css from all `li` elements $(this).css('color', 'red');//Will apply `red` to current element });<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.

在CSS和Jquery中将颜色更改回默认值

这个问题在这里已经有了答案: 如何删除使用.css()函数添加的样式? 16个答案 在应用css之前重置所有其他li元素$('li').on('click', function() { $('li').css('color', '');//WIll remove `color` css from all `li` elements $(this).css('color', 'red');//Will apply `red` to current element });<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script> <

How to remove style property

Possible Duplicate: jQuery - remove style added with .css() function I want to remove the style property from the div , i cannot use the removeAttribute and removeProperty as removeAttribute removes whole style and remove Property doesnot works in ie. Is there any other way to do it. <div style="visiblity:hidden;margin-right:10px;margin-left:10px"> I want to remove only visibility st

如何删除样式属性

可能重复: jQuery - 删除添加了.css()函数的样式 我想从div中删除样式属性,我不能使用removeAttribute和removeProperty作为removeAttribute删除整个样式并删除属性不会在ie中工作。 有没有其他办法可以做到这一点。 <div style="visiblity:hidden;margin-right:10px;margin-left:10px"> 我想只删除可见性样式属性。 像这样使用.css $(elementSelect).css('marginRight', null); 要么 $(elementSelect).css

How to reload or rerender CSS for a single HTML element?

This question already has an answer here: How can I remove a style added with .css() function? 16 answers With jQuery, you are adding your styles to the style attribute of the element. It is removed again, if you call the function again with an empty string ( "" ). This will remove the property in the style attribute. If you have eg this command: $('.foo').css('height', '100px

如何重新加载或重新渲染单个HTML元素的CSS?

这个问题在这里已经有了答案: 如何删除使用.css()函数添加的样式? 16个答案 使用jQuery,您可以将样式添加到元素的style属性中。 如果再次使用空字符串( "" )调用该函数,它将被删除。 这将删除style属性中的属性。 如果你有例如这个命令: $('.foo').css('height', '100px'); 你可以通过撤消它 $('.foo').css('height', ''); 另请参阅此处的讨论:https://stackoverflow.com/a/4036868/3233827

vscode Intellisense NodeJs

In vscode, developers have the ability to hover over methods and properties of variables and objects in our code, and it will show you information regarding them. Unfortunately, that is lost once we pass the code to a module inside of another file (since javascript is statically typed). Is there any way possible for me to explicitly type a parameter passed to a module? Or maybe a source-map of

vscode智能感知NodeJs

在vscode中,开发人员有能力将鼠标悬停在代码中变量和对象的方法和属性上,并向您显示有关它们的信息。 不幸的是,一旦我们将代码传递给另一个文件中的模块(因为JavaScript是静态类型的),这会丢失。 有没有什么办法可以让我显式地输入传递给模块的参数? 或者可能是某种源图? 我遇到问题的一个例子: app.js var express = require('express') var app = express() var routes = './routes/route.js' route.js modu

Upload file in angular2: Body (FormData) empty

I'm trying to upload a picture with Angular2 to my REST Service (Loopback). The Loopback service works (tested with Postman) and accepts files with the x-www-form-urlencoded header. Here's a simplified service method that sends the POST request: public uploadFile(url : string, file: File): Observable<any> { let headers: Headers = new Headers(); headers.append('Content-Type',

将angular2:Body(FormData)中的文件上传为空

我试图用Angular2上传一张照片到我的REST服务(环回)。 Loopback服务工作(使用Postman进行测试)并使用x-www-form-urlencoded头文件接受文件。 以下是发送POST请求的简化服务方法: public uploadFile(url : string, file: File): Observable<any> { let headers: Headers = new Headers(); headers.append('Content-Type', 'application/x-www-form-urlencoded'); let formData = new FormData(); formData