Welcome to this week's episode of Yet Another Time Zone Question : I've done a fair bit of reading on SO, tried to manipulate moment.js and date.js into helping me, and generally been plagued by a feeling of frustration since I started trying to solve this, so if someone could help or point me at the duplicate question on SO that I just haven't been able to find, that'd be aweso
欢迎来到本周的另一个时区问题 ： 我已经完成了一些关于SO的阅读，试图操纵moment.js和date.js来帮助我，并且自从我开始尝试解决这个问题以来，一直受到挫折感的困扰，所以如果有人能够帮助或者指出我在重复的问题上，我只是无法找到，那真棒。 我有一个页面。 此页面显示一系列时间，例如：7：28,7：38,7：48。 我知道这些是AM / PM。 这些时间总是美国/纽约（当夏时制变化时它们不会改变，因为它们对应的事件总是在那个
This question already has an answer here: Daylight saving time and time zone best practices [closed] 30 answers Yours is a duplicate of many other Questions. So I'll be brief. There are two ways to represent three kinds of date-time values: Store and exchange date-time values in UTC if actual moment has passed ( payment made, invoice received, court papers served, shipment arrived, e
这个问题在这里已经有了答案： 夏令时和时区最佳做法[已关闭] 30个答案 你的是许多其他问题的重复。 所以我会简短。 有两种方法可以表示三种日期时间值： 如果实际时间已过（付款，收到发票，送达法庭文件，送货到达等）， 则以UTC保存并交换日期时间值 ，或者如果将来您知道您希望在时间线上有特定时刻，无论政治家是谁重新定义时区，例如更改夏令时（DST）。 对于Java，使用Instant类。 在SQL中使用TIMESTAMP WITH
I have an input field where the user is required to select a date/time The local machine will always be in either GMT or BST depending on the time of year. For those who aren't aware of UK time shenanigans: GMT (Greenwich Mean Time) is always equal to UTC BST (British Summer Time) is GMT+1 during the summer months The dates the users enter will be stored in a database that is set to G
我有一个输入字段，用户需要选择日期/时间本地机器将总是在GMT或BST中，具体取决于一年的时间。 对于那些不知道英国时间诡计的人： GMT（格林威治标准时间）始终等于UTC BST（英国夏令时）在夏季月份为GMT + 1 用户输入的日期将存储在设置为GMT的数据库中，因此永远不会抵消时间。 因此我需要将用户输入的内容转换为GMT / UTC。 但是，我的转换会导致返回相同的日期。 我究竟做错了什么？ https://jsfiddle.net/r
I'm sure there are many ways to achieve that but I'm looking for something "elegant". a = [ 'a', 'b', 'c' ]; magicArrayJoin(a, {value: 255} ); // insert the same object between each item result == [ 'a', {value: 255}, 'b', {value: 255} 'c' ]; All proposals are welcome. :) An ordinary loop seems to be the best: function intersperse(arr, el) { var res
我相信有很多方法可以实现，但我正在寻找“优雅”的东西。 a = [ 'a', 'b', 'c' ]; magicArrayJoin(a, {value: 255} ); // insert the same object between each item result == [ 'a', {value: 255}, 'b', {value: 255} 'c' ]; 所有提案都是受欢迎的 :) 一个普通的循环似乎是最好的： function intersperse(arr, el) { var res = [], i=0; if (i < arr.length) res.push(arr[i++]);
What is the more efficient way to insert an array inside another array. a1 = [1,2,3,4,5]; a2 = [21,22]; newArray - a1.insertAt(2,a2) -> [1,2, 21,22, 3,4,5]; Iterating a2 using splice looks a bit awfull from a performance point of view if a2 array is large. Thanks. You can use splice combined with some apply trickery: a1 = [1,2,3,4,5]; a2 = [21,22]; a1.splice.apply(a1, [2, 0].concat(a2
在另一个数组中插入数组的更有效方法是什么？ a1 = [1,2,3,4,5]; a2 = [21,22]; newArray - a1.insertAt(2,a2) -> [1,2, 21,22, 3,4,5]; 如果a2数组很大，则从性能的角度来看，使用拼接对a2进行迭代看起来有点夸张。 谢谢。 您可以将splice与一些apply技巧结合使用： a1 = [1,2,3,4,5]; a2 = [21,22]; a1.splice.apply(a1, [2, 0].concat(a2)); console.log(a1); // [1, 2, 21, 22, 3, 4, 5]; 在ES2015 +中，您可
This question already has an answer here: How to insert an item into an array at a specific index? 10 answers 使用push命令Arr.push(value)
这个问题在这里已经有了答案： 如何将项目插入到特定索引处的数组中？ 10个答案 使用push命令Arr.push(value)
This question already has an answer here: How to insert an item into an array at a specific index? 10 answers You're looking for the .splice() method for arrays. Read about it here. For your example, it would be something like arr.splice(2,0,'@') This says "go to element 2 of the array, remove 0 elements, and add the element '@'".
这个问题在这里已经有了答案： 如何将项目插入到特定索引处的数组中？ 10个答案 您正在寻找数组的.splice()方法。 在这里阅读。 就你的例子而言，它会是这样的 arr.splice(2,0,'@') 这说“转到数组的元素2，删除0个元素，并添加元素'@'”。
This question already has an answer here: How to insert an item into an array at a specific index? 10 answers 您可以使用Array.splice将项目插入到特定位置的Array中。 const suits = ["hearts", "clubs", "Brooks Brothers", "diamonds", "spades"]; suits.splice(2, 0, 'newItem'); console.log(suits); You should use splice function arr.splice(index, 0, item); will insert item into arr at the spec
这个问题在这里已经有了答案： 如何将项目插入到特定索引处的数组中？ 10个答案 您可以使用Array.splice将项目插入到特定位置的Array中。 const suits = ["hearts", "clubs", "Brooks Brothers", "diamonds", "spades"]; suits.splice(2, 0, 'newItem'); console.log(suits); 你应该使用拼接功能 arr.splice(index, 0, item); 将项目插入到指定索引的arr中（首先删除0个项目，即它只是一个插入）。 var suits = ["he
This question already has an answer here: How to insert an item into an array at a specific index? 10 answers If I understood you right, the problem for you is to how to insert and move elements in array. You can do it with splice method, which has optional parameters for elements to insert: Here is what you need for your example: var myArray = [ {name: "not selected"}, {name: "no
这个问题在这里已经有了答案： 如何将项目插入到特定索引处的数组中？ 10个答案 如果我理解你的话，你的问题是如何插入和移动数组中的元素。 你可以用splice方法来完成，该方法有要插入元素的可选参数： 以下是您需要的示例： var myArray = [ {name: "not selected"}, {name: "not selected"}, {name: "selected"}, {name: "not selected"}, {name: "not selected"}, {name: "not selected"} ];
This question already has an answer here: How to insert an item into an array at a specific index? 10 answers What you want is the splice function: arr.splice(index, 0, item); will insert item into arr at the specified index .
这个问题在这里已经有了答案： 如何将项目插入到特定索引处的数组中？ 10个答案 你想要的是拼接功能： arr.splice(index, 0, item); 将item插入指定index arr中。