Currently for a body with HTML: hello</div><p>hai</p><span>Welcome</span> on alerting $('body').html() it alerts hello<p>hai</p><span>Welcome</span> . Fiddle But I want it to display hello</div><p>hai</p><span>Welcome</span> ie Alert HTML as it is written within the body. I can see the exact code whe
目前，对于使用HTML： hello</div><p>hai</p><span>Welcome</span> $('body').html()提供$('body').html()警报hello<p>hai</p><span>Welcome</span> 。 小提琴 但是我希望它显示hello</div><p>hai</p><span>Welcome</span> 即警报HTML，因为它在正文中写入。 当我查看页面的源代码时，我可以看到确切的代码。我真的
I'm writing the JS for a chat application I'm working on in my free time, and I need to have HTML identifiers that change according to user submitted data. This is usually something conceptually shaky enough that I would not even attempt it, but I don't see myself having much of a choice this time. What I need to do then is to escape the HTML id to make sure it won't allow for X
我正在为空闲时间正在编写的聊天应用程序编写JS，并且需要根据用户提交的数据改变HTML标识符。 通常情况下，这通常是一些不稳定的事情，我甚至不会去尝试，但是这次我没有看到自己有太多的选择。 然后我需要做的就是转义HTML标识以确保它不会允许XSS或破坏HTML。 代码如下： var user_id = escape(id) var txt = '<div class="chut">'+ '<div class="log" id="chut_'+user_id+'"></div>'+
I know my PHP but I got only very basic JavaScript knowledge, probably because I try to avoid to use JavaScript at all because there is always the risk of visitors having disabled JavaScript's in their browsers... However now I need a certain task in a html form that might only be solved by using JavaScript. I have one textarea and one checkbox. The checkbox is checked by default when the
我知道我的PHP，但我只有非常基础的JavaScript知识，可能是因为我尽量避免使用JavaScript，因为浏览器总是存在浏览器禁用JavaScript的风险......但是现在我需要一个特定的任务可能只能通过使用JavaScript解决的html表单。 我有一个textarea和一个复选框。 加载页面时默认选中该复选框。 如果用户在textarea内单击，我希望复选框自动取消选中。 如果用户点击textarea外的任何地方，并且由于某种原因没有在textarea中写入任何
I am sorry if this is a dumb or easy question but I am fairly new to Javascript/jQuery. The past month I have really started to delve into the land of scripting and have seen two different, maybe three, ways people use var in Javascript/jQuery. The way I use a var is like so, var nav = $('nav'); nav.hide(); A very common way I have seen people use vars, var nav = $('nav'); $(nav).hide();
我很抱歉，如果这是一个愚蠢或容易的问题，但我是相当新的Javascript / jQuery。 在过去的一个月中，我真的开始深入研究脚本领域，并且看到了两种不同的，也许是三种人们在Javascript / jQuery中使用var方式。 我使用var的方式就是这样， var nav = $('nav'); nav.hide(); 我见过一种非常常见的方式使用变种， var nav = $('nav'); $(nav).hide(); 从答案中， var $nav = $('nav'); $nav.hide(); 从我通过搜索Google
什么是正确的方法来检查JavaScript之间的字符串平等？ always Until you fully understand the differences and implications of using the == and === operators, use the === operator since it will save you from obscure (non-obvious) bugs and WTFs. The "regular" == operator can have very unexpected results due to the type-coercion internally, so using === is always the recommended approach. Fo
什么是正确的方法来检查JavaScript之间的字符串平等？ 总是直到你完全理解的差异和使用的影响==和===运营商，使用===运营商，因为它可以使你免于晦涩（非显而易见性）的错误和WTFs。 由于内部类型强制，“常规” ==运算符可能会产生非常意想不到的结果，所以使用===始终是推荐的方法。 为了深入了解这一点以及Javascript的其他“好与坏”部分，请阅读Douglas Crockford先生及其工作。 有一个伟大的Google技术讲座，他总结了很多
Notice while on Google's homepage, with no focus on any element, pressing BACKSPACE will put the focus into the search toolbar instead of navigating back. How can I accomplish this? I keep running into this problem with users in my app. They don't have focus on any element and hit BACKSPACE which throws them out of the app. 如果我们正在处理textarea或input之外的退格键，我会将事件处理
注意，在Google的首页上，没有关注任何元素，按下BACKSPACE会将焦点放到搜索工具栏中，而不是返回。 我怎样才能做到这一点？ 我一直在用我的应用程序遇到这个问题。 他们没有专注于任何元素，并击中将其抛出应用程序的BACKSPACE。 如果我们正在处理textarea或input之外的退格键，我会将事件处理函数绑定到keydown并阻止该事件的默认操作： $(document).on("keydown", function (e) { if (e.which === 8 && !$(e
What is the difference between the !== operator and the != operator. Does it behave similar to the === operator where it compares both value and the type? Yes, it's the same operator like === , just for inequality: !== - returns true if the two operands are not identical. This operator will not convert the operands types, and only returns false if they are the same type and value. —Wik
！==运算符和！=运算符有什么区别？ 它是否与===运算符类似，它比较值和类型？ 是的，它是像===一样的运算符，仅用于不平等： !== - 如果两个操作数不相同，则返回true。 该运算符不会转换操作数类型，只有在类型和值相同时才返回false。 -Wikibooks 是， !==是!=运算符的严格版本，如果操作数的类型不同，则不会执行类型强制： 0 != '' // false, type coercion made 0 != '0' // false false != '
i am working on splicing the old object ie first added object in an array when new element(object) is added in to it automatically. this is the sample code i worked on var sampleArr = [{"id":4,"hostName":"henry"}, {"id":3,"hostName":"jeff"}, {"id":2,"hostName":"mark"}, {"id":1,"hostName":"holder"}]; the above array contains 4
我正在拼接旧对象，即当新元素（对象）自动添加到数组中时，首先在数组中添加对象。 这是我工作的示例代码 var sampleArr = [{"id":4,"hostName":"henry"}, {"id":3,"hostName":"jeff"}, {"id":2,"hostName":"mark"}, {"id":1,"hostName":"holder"}]; 当添加5个对象（{“id”：5，“hostName”：“punk”}）时，上面的数组包含4个对象我想拼接第一个添加的对
I have the following dataset Input: dataset[0]=[{data:29, color:"y"},{data:44, color:"g"}] dataset[1]=[{data:16, color:"r"},{data:23, color:"m"},{data:23, color:"b"}] I am showing this information on bar chart, however bar chart attempting to group them. And it does not give me what I expect. http://jsfiddle.net/7dhb4jh0/1 Therefore,I need to have the following output before I feed my bar
我有以下数据集 输入： dataset[0]=[{data:29, color:"y"},{data:44, color:"g"}] dataset[1]=[{data:16, color:"r"},{data:23, color:"m"},{data:23, color:"b"}] 我在条形图上显示这些信息，但条形图试图对它们进行分组。 它并不能给我我所期望的。 http://jsfiddle.net/7dhb4jh0/1 因此，在输入条形图之前，我需要输出以下内容 通过添加{data:0, color:null}来匹配两个数据集长度的所需输出背后的逻辑有两件事情涉
I have an array like this: var oldArray = [{'value': '1', 'label': 'a'}, {'value': '2', 'label': 'b'}] what I want is using spread operator add a new object at the beginning of that array: BTW this works: var oldArray = [{'value': '1', 'label': 'a'}, {'value': '2', 'label': 'b'}] var newObj = {'value': 'all', 'label': 'all'} var result = [newObj, ...oldArray] But generates a key "newOb
我有一个这样的数组： var oldArray = [{'value': '1', 'label': 'a'}, {'value': '2', 'label': 'b'}] 我想要的是使用spread运算符在该数组的开头添加一个新对象： 顺便说一句这个工程： var oldArray = [{'value': '1', 'label': 'a'}, {'value': '2', 'label': 'b'}] var newObj = {'value': 'all', 'label': 'all'} var result = [newObj, ...oldArray] 但是像这样产生一个关键的“newObj”： var oldArray = [newObj :