I have an piece of code I want to live on a static website but I want it to pull the latest version of a file in an Amazon AWS S3 bucket to display a link for download. I'm not requiring the user to authenticate in any way with my site. The API I'm using ( aws-sdk for javascript) requires credentials to perform any operation, even on a public bucket. My plan for listing the files is t
我有一段代码希望在静态网站上生活，但我希望它能够在亚马逊AWS S3存储桶中提取最新版本的文件，以显示下载链接。 我不要求用户以任何方式验证我的网站。 我使用的API（ aws-sdk for javascript）需要证书才能执行任何操作，即使在公共存储区中也是如此。 我列出文件的计划是创建一个IAM用户，只能通过以下策略访问此存储桶中的子文件夹，以执行我所需的操作： { "Version": "2012-10-17", "Statement": [ {
When 127.0.0.1 below is omitted app.address() is not null, but when a host is set, it is null. var express = require('express'), app = express.createServer(); app.use(express.logger()); app.get('/', function(req, res){ res.send('Hello World'); }); app.listen(3000, '127.0.0.1'); console.log(app.address()); console.log('Express server started on port %s', app.address().port); Error out
当省略下面的127.0.0.1时，app.address（）不为空，但当设置主机时，它为空。 var express = require('express'), app = express.createServer(); app.use(express.logger()); app.get('/', function(req, res){ res.send('Hello World'); }); app.listen(3000, '127.0.0.1'); console.log(app.address()); console.log('Express server started on port %s', app.address().port); 错误输出： TypeError: Cannot r
I have a string of XML format. As shown below: <gt> <st>sample1</st> <tt>sample2</tt> <tt>sample3</tt> </gt> I need to get the node value in Java script file. How can I get the value? Try this code: var xml = "<gt><st>sample1</st><tt>sample2</tt><tt>sample3</tt></gt&
我有一个XML格式的字符串。 如下所示： <gt> <st>sample1</st> <tt>sample2</tt> <tt>sample3</tt> </gt> 我需要在Java脚本文件中获取节点值。 我如何获得价值？ 试试这个代码： var xml = "<gt><st>sample1</st><tt>sample2</tt><tt>sample3</tt></gt>", xmlDoc = $.parseXML(xml
I would like to know how can we detect whether meteor is running in development or production environment? Thanks You can use process for that, another approach is to use fs and check a file which you put in your dir which is different depending on the environment your application is in. I think the best approach would be to use process.env and checking out COMPUTERNAME . Use " meteo
我想知道我们如何检测流星是否在开发或生产环境中运行？ 谢谢 你可以使用这个过程，另一种方法是使用fs并检查你放在你的dir中的文件，这个文件根据你的应用程序所在的环境而不同。 我认为最好的方法是使用process.env并检出COMPUTERNAME 。 使用“ meteor_runtime_config .ROOT_URL” 这会返回ROOT_URL环境变量。 这是检测环境的最简单方法。 您可以在.bash_profile或.profile中设置此值 export ROOT_URL=http://YOU
I am trying to get the current UTC date to store in my database. My local time is 9:11 pm This equates to 1:11 am UTC. When I look in my database, I notice that 1:11 pm is getting written to. I'm confused. In order to get the UTC time in JavaScript, I'm using the following code: var currentDate = new Date(); var utcDate = Date.UTC(currentDate.getFullYear(), currentDate.getMonth(), cu
我正在尝试获取当前的UTC日期以存储在我的数据库中。 我的当地时间是下午9点11分，这相当于上午1点11分。 当我查看我的数据库时，我注意到下午1:11正在写入。 我很困惑。 为了在JavaScript中获得UTC时间，我使用下面的代码： var currentDate = new Date(); var utcDate = Date.UTC(currentDate.getFullYear(), currentDate.getMonth(), currentDate.getDate(), currentDate.getHours(), currentDate.getMinutes(), currentD
The 'Wat' talk for CodeMash 2012 basically points out a few bizarre quirks with Ruby and JavaScript. I have made a JSFiddle of the results at http://jsfiddle.net/fe479/9/. The behaviours specific to JavaScript (as I don't know Ruby) are listed below. I found in the JSFiddle that some of my results didn't correspond with those in the video, and I am not sure why. I am, howev
CodeMash 2012的'Wat'演讲基本上指出了Ruby和JavaScript的几个奇怪的怪癖。 我在http://jsfiddle.net/fe479/9/上做了一个JSFiddle的结果。 下面列出了特定于JavaScript的行为（因为我不知道Ruby）。 我在JSFiddle中发现，我的一些结果与视频中的结果不一致，我不知道为什么。 然而，我很想知道JavaScript在每种情况下如何处理幕后的工作。 Empty Array + Empty Array [] + [] result: <Empty String> 在J
I'm trying to replace {all-content}^{^} into hat{all-content} . And the string and expected output should be like ... |---------------------|-------------------|-------------------| | String Input | Expected Result | What I get | |---------------------|-------------------|-------------------| | {A}^{^} | hat{A} | hat{A} | |--------------------
我试图将{all-content} ^ {^}替换为 hat {all-content} 。 字符串和预期的输出应该像... |---------------------|-------------------|-------------------| | String Input | Expected Result | What I get | |---------------------|-------------------|-------------------| | {A}^{^} | hat{A} | hat{A} | |---------------------|-------------------|-----------------
I need a regex for so as to convert the string {somestr} to :somestr , but I need to replace only the first and the last occurrences of curly braces, since if there is any occurrence in the middle of a string - it should not be removed. So far I have tried: the incoming string var path = '/claims/{id}' var pathWithoutBraces = path.replace("{", ":").replace("}", "") The output is /cl
我需要一个正则表达式来将字符串{somestr}转换为:somestr ，但我只需要替换大括号的第一个和最后一个出现，因为如果在字符串中间出现任何事件 - 它不应该被删除。 到目前为止，我尝试过： 传入的字符串var path = '/claims/{id}' var pathWithoutBraces = path.replace("{", ":").replace("}", "") 输出是/claims/:id ，这是预期的，但它仍然会取代整个字符串中的所有进一步发生 您可以使用以下内容替换第一个和最
I'm trying to write a regex to search a string and find words wrapped in curly braces that are not wrapped in a span tag with a specific attribute (data-placeholder). Example text: This is a test. Testing <span class="anything">{variable}</span> wrapped without the attribute, but this one <span data-placeholder="val">{variable}</span> is. The first should match, the
我正在尝试编写一个正则表达式来搜索一个字符串，并查找包裹在大括号中的单词，这些大括号没有用特定属性（数据占位符）包裹在span标记中。 示例文本： This is a test. Testing <span class="anything">{variable}</span> wrapped without the attribute, but this one <span data-placeholder="val">{variable}</span> is. The first should match, the second should not, and the last one should
I have been doing research to come up with a standardized Javascript coding style for my team. Most resources now recommend the "Module" pattern that involves closures, such as this: var Module = function() { someMethod = function() { /* ... */ }; return { someMethod: someMethod }; }(); and invoke it like Module.someMethod(); . This approach seems to only w
我一直在研究为我的团队提供标准化的JavaScript编码风格。 大多数资源现在推荐涉及闭包的“模块”模式，例如： var Module = function() { someMethod = function() { /* ... */ }; return { someMethod: someMethod }; }(); 并像Module.someMethod();一样调用它Module.someMethod(); 。 这种方法似乎只适用于在传统的OOP上下文中是静态的方法，例如用于取出/保存数据的存储库类，用于进行外部请求