This question already has an answer here: How can I know which radio button is selected via jQuery? 29 answers First of all you use same id 4 times. ID have to be unique in document, you cannot set same id to 4 elements. Also I think the way you are getting value from radio button is wrong. This is more or less how you can get value from radio button: ( example from another SO question )
这个问题在这里已经有了答案： 我如何知道通过jQuery选择了哪个单选按钮？ 29个答案 首先你使用相同的id 4次。 ID在文档中必须是唯一的，不能将相同的ID设置为4个元素。 另外我认为你从单选按钮获得价值的方式是错误的。 这或多或少是你如何从单选按钮获得价值的：（例如从另一个SO问题） var optionu = $('input[name=optionu]:checked', '#controls').val() 同时从所有输入[radio]元素中删除id。 <label class
This question already has an answer here: How can I know which radio button is selected via jQuery? 29 answers var selectedValue = $("input[name=form]:checked").val(); You should do it like this: var radio = jQuery('input[name="form"]:checked'); You can then retrieve your radio value or other attributes: var value = radio.val(); It's a good idea to see if any radio is checked before
这个问题在这里已经有了答案： 我如何知道通过jQuery选择了哪个单选按钮？ 29个答案 var selectedValue = $("input[name=form]:checked").val(); 你应该这样做： var radio = jQuery('input[name="form"]:checked'); 然后您可以检索您的无线电值或其他属性： var value = radio.val(); 在做这件事之前查看是否有任何收音机被检查是个好主意： if (radio != undefined) { //do what you need to } 另外，你也可以试
This question already has an answer here: Loop through an array in JavaScript 35 answers You have error in loop ( push(i) instead of push(alphabet[i]) ). Correct loop: for (i=0; i<alphabet.length; i++) { str.push(alphabet[i]); console.log(str.join("")); }
这个问题在这里已经有了答案： 在JavaScript中循环访问数组35个答案 你有循环错误（ push(i)而不是push(alphabet[i]) ）。 正确的循环： for (i=0; i<alphabet.length; i++) { str.push(alphabet[i]); console.log(str.join("")); }
This question already has an answer here: Loop through an array in JavaScript 35 answers 使用循环： <!DOCTYPE html> <html> <body> <div class="example">First div element with class="example".</div> <div class="example">Second div element with class="example".</div> <p>Click the button to change the text of the first div element with cla
这个问题在这里已经有了答案： 在JavaScript中循环访问数组35个答案 使用循环： <!DOCTYPE html> <html> <body> <div class="example">First div element with class="example".</div> <div class="example">Second div element with class="example".</div> <p>Click the button to change the text of the first div element with class="example" (index 0).&l
This question already has an answer here: Loop through an array in JavaScript 35 answers You can use array#some The some() method tests whether at least one element in the array passes the test implemented by the provided function. var arrayFullNames = [{ name: 'David', surname: 'Jones', age: 29 }, { name: 'Jack', surname: 'Sparrow', age: 33 }, { name: 'Monkey', surname: 'Idontknow', age:
这个问题在这里已经有了答案： 在JavaScript中循环访问数组35个答案 你可以使用array#some some（）方法测试数组中是否至少有一个元素传递了由提供的函数实现的测试。 var arrayFullNames = [{ name: 'David', surname: 'Jones', age: 29 }, { name: 'Jack', surname: 'Sparrow', age: 33 }, { name: 'Monkey', surname: 'Idontknow', age: 9 }, { name: 'JavaScript', surname: 'Something', age: '6 weeks' } ]; func
This question already has an answer here: Loop through an array in JavaScript 35 answers You should use a for loop. To iterate on every element matching your array-like object of elements returned by getElementsByClassName . window.onload = function yourFunction(){ var elements = document.getElementsByClassName('icon'); if (elements){ for (var i = 0; i<elements.length; i++)
这个问题在这里已经有了答案： 在JavaScript中循环访问数组35个答案 你应该使用for循环。 对每个元素进行迭代，这些元素与getElementsByClassName返回的元素类型的对象相匹配。 window.onload = function yourFunction(){ var elements = document.getElementsByClassName('icon'); if (elements){ for (var i = 0; i<elements.length; i++){ elements[i].innerHTML = elements[i].innerHTML.repl
This question already has an answer here: Loop through an array in JavaScript 35 answers You can simply use Array#map : data.users.map(e => (e.name.first ? e.name.first : '') + //Handles the first name (e.name.first ? ' ' : '') + //Space between the names (e.name.last ? e.name.last : '') //Handles the last name ); Demo: const data = { "users": [ { "test
这个问题在这里已经有了答案： 在JavaScript中循环访问数组35个答案 你可以简单地使用Array#map ： data.users.map(e => (e.name.first ? e.name.first : '') + //Handles the first name (e.name.first ? ' ' : '') + //Space between the names (e.name.last ? e.name.last : '') //Handles the last name ); 演示： const data = { "users": [ { "test": "123", "name": {
This question already has an answer here: Loop through an array in JavaScript 35 answers You will become an array of objects, that includes an callEvent object that has an dates property which is an array with objects with the propertys startDateTime and endDateTime. It will look like following: [ { callEvent: { dates: [ {startDateTime: '', endDateTime: ''},
这个问题在这里已经有了答案： 在JavaScript中循环访问数组35个答案 您将成为一个对象数组，其中包含一个具有dates属性的callEvent对象，该属性是具有propertys startDateTime和endDateTime的对象的数组。 它将如下所示： [ { callEvent: { dates: [ {startDateTime: '', endDateTime: ''}, // more objects with start- and endDateTime ] } }, // more call
This question already has an answer here: Loop through an array in JavaScript 35 answers here is a JsFiddle is that what you need ? for (var key in family) { var obj = family[key]; for (var prop in obj) { alert(prop + " = " + obj[prop]); } } Here is the way to access the properties directly and not with a loop jsFIddle (Method 2, uncomment)
这个问题在这里已经有了答案： 在JavaScript中循环访问数组35个答案 这里是一个JsFiddle 你需要什么？ for (var key in family) { var obj = family[key]; for (var prop in obj) { alert(prop + " = " + obj[prop]); } } 这是直接访问属性的方式，而不是循环jsFIddle（方法2，取消注释）
This question already has an answer here: Loop through an array in JavaScript 35 answers 我需要的循环看起来像这样function jsonpCallback(data) { $.each(data, function (i, item) { $('#jsonpResult').append( $('<div/>') .addClass("myclass") .text(item.timestamp) //item.timestamp ); }); } Its because your jsonpresponse is one array,
这个问题在这里已经有了答案： 在JavaScript中循环访问数组35个答案 我需要的循环看起来像这样function jsonpCallback(data) { $.each(data, function (i, item) { $('#jsonpResult').append( $('<div/>') .addClass("myclass") .text(item.timestamp) //item.timestamp ); }); } 它的原因是你的jsonpresponse是一个数组，你试图像一个单一的对象一样使