This question already has an answer here: How do I correctly clone a JavaScript object? 54 answers You aren't duplicating q , instead, you're copying a reference to different variable. Both q and duplicateQ point to the same object, the same location in your computer's memory. In order to make this work, you're going to have to clone the object, then you can delete (/ mod
这个问题在这里已经有了答案： 我如何正确克隆一个JavaScript对象？ 54个答案 你不是复制q ，而是复制对不同变量的引用。 q和duplicateQ指向同一个对象，即计算机内存中的相同位置。 为了使这个工作，你将不得不克隆该对象，然后你可以删除（/修改）单独变量的各个属性。 一个快速而肮脏的例子： var a = { a: 1, b: 2 }, b = JSON.parse(JSON.stringify(a)); delete b.a; document.body.textContent = JS
This question already has an answer here: How do I correctly clone a JavaScript object? 54 answers $.extend is only cloning plain objects. If the object has a constructor then it is not cloned, but just copied. From the $.extend source: if ( jQuery.isPlainObject(copy) /* ... */) { // do the recursive $.extend call and clone the object } else if ( copy !== undefined ) {
这个问题在这里已经有了答案： 我如何正确克隆一个JavaScript对象？ 54个答案 $.extend仅克隆普通对象。 如果该对象有一个构造函数，那么它不会被克隆，而只是被复制。 来自$.extend源代码： if ( jQuery.isPlainObject(copy) /* ... */) { // do the recursive $.extend call and clone the object } else if ( copy !== undefined ) { target[ name ] = copy; // ^^^^^ just copy } 所以$.ext
This question already has an answer here: How do I correctly clone a JavaScript object? 54 answers this will assign not by reference <script> var obj = { name: 'abc', age: '30' }; var objTwo = {}; for( var i in obj ) { objTwo[i] = obj[i]; } </script> view fiddle 我会用jQuery来做到这一点： var obj1 = { name: "abc",
这个问题在这里已经有了答案： 我如何正确克隆一个JavaScript对象？ 54个答案 这将不会被引用 <script> var obj = { name: 'abc', age: '30' }; var objTwo = {}; for( var i in obj ) { objTwo[i] = obj[i]; } </script> 查看小提琴 我会用jQuery来做到这一点： var obj1 = { name: "abc", age: 20 } console.log(obj1); var obj2
This question already has an answer here: How do I correctly clone a JavaScript object? 54 answers 你可以使用Object.assign： var fruit = { name: "Apple" }; var vegetable = Object.assign({}, fruit); vegetable.name = "potatoe"; console.log(fruit);
这个问题在这里已经有了答案： 我如何正确克隆一个JavaScript对象？ 54个答案 你可以使用Object.assign： var fruit = { name: "Apple" }; var vegetable = Object.assign({}, fruit); vegetable.name = "potatoe"; console.log(fruit);
Possible Duplicate: How do I correctly clone a JavaScript object? I have this code: var temp = []; var obj = {name:"1"}; temp.push(obj); obj.name = "2"; temp.push(obj); What I'm expecting to be true: temp[0].name == "1" && temp[1].name == "2"; What actually happens: temp[0].name == "2" && temp[1].name == "2"; Why does this happen, and how I can get what I'm expec
可能重复： 我如何正确克隆一个JavaScript对象？ 我有这样的代码： var temp = []; var obj = {name:"1"}; temp.push(obj); obj.name = "2"; temp.push(obj); 我期待的是真实的： temp[0].name == "1" && temp[1].name == "2"; 究竟发生了什么： temp[0].name == "2" && temp[1].name == "2"; 为什么会发生这种情况，以及我如何能够得到我期待的结果？ JavaScript数组持有对象的引用，而不是对象本
This question already has an answer here: How do I correctly clone a JavaScript object? 54 answers let clone = Object.assign( Object.create( Object.getPrototypeOf(orig)), orig) I tried a lot, in the end this worked for me. It also avoids to set the prototype, because they say it slows down the code a lot. And it's a one-liner! const clone = Object.assign( {}, instanceOfBlah ); Objec
这个问题在这里已经有了答案： 我如何正确克隆一个JavaScript对象？ 54个答案 let clone = Object.assign( Object.create( Object.getPrototypeOf(orig)), orig) 我尝试了很多，最终这为我工作。 它也避免了设置原型，因为他们说它会使代码变慢。 这是一个单线！ const clone = Object.assign( {}, instanceOfBlah ); Object.setPrototypeOf( clone, Blah.prototype ); 请注意Object.assign的特性：它执行浅拷贝并且
This question already has an answer here: How can I know which radio button is selected via jQuery? 29 answers 通过使用： function getCheckedRadioValue(name) { return $('input[name='+name+']:radio:checked').val(); } You can do $('input[type=radio]').each(function(){ if($(this).is(':checked')){ alert('this button is checked'); } }); See the working example below: $('butto
这个问题在这里已经有了答案： 我如何知道通过jQuery选择了哪个单选按钮？ 29个答案 通过使用： function getCheckedRadioValue(name) { return $('input[name='+name+']:radio:checked').val(); } 你可以做 $('input[type=radio]').each(function(){ if($(this).is(':checked')){ alert('this button is checked'); } }); 请参阅下面的工作示例： $('button').click(function() { var counter = 1;
This question already has an answer here: How can I know which radio button is selected via jQuery? 29 answers You can test whether a specific one is checked using jQuery as follows: if ($("#radio1").prop("checked")) { // do something } // OR if ($("#radio1").is(":checked")) { // do something } // OR if you don't have ids set you can go by group name and value // (basically you need
这个问题在这里已经有了答案： 我如何知道通过jQuery选择了哪个单选按钮？ 29个答案 您可以测试是否使用jQuery检查特定的一个，如下所示： if ($("#radio1").prop("checked")) { // do something } // OR if ($("#radio1").is(":checked")) { // do something } // OR if you don't have ids set you can go by group name and value // (basically you need a selector that lets you specify the particular inpu
This question already has an answer here: How can I know which radio button is selected via jQuery? 29 answers 尝试像这样：var cname = $（'input：radio [name = radios]：checked'）。val（）;
这个问题在这里已经有了答案： 我如何知道通过jQuery选择了哪个单选按钮？ 29个答案 尝试像这样：var cname = $（'input：radio [name = radios]：checked'）。val（）;
This question already has an answer here: How can I know which radio button is selected via jQuery? 29 answers if ($("#opt1").is(":checked"))) { // do A } else if ($("#opt2").is(":checked")) { // do B } You have a similar answer here: jQuery, checkboxes and .is(":checked") But I saw that you used ids attributes in the options so I use it for your answer..
这个问题在这里已经有了答案： 我如何知道通过jQuery选择了哪个单选按钮？ 29个答案 if ($("#opt1").is(":checked"))) { // do A } else if ($("#opt2").is(":checked")) { // do B } 你在这里有类似的答案：jQuery，复选框和.is（“：checked”） 但是我看到你在选项中使用了id属性，所以我用它来解答。