I'm currently trying to implement a treemap algorithm in Javascript. More specifically the algorithm described in Squarified Treemaps. The pseudo code given looks like the following: procedure squarify(list of real children, list of real row, real w) begin real c = head(children); if worst(row, w) <= worst(row++[c], w) then squarify(tail(children),row++[c], w) else
我目前正在尝试在Javascript中实现树形图算法。 更具体地说是Squarified Treemaps中描述的算法。 给出的伪代码如下所示： procedure squarify(list of real children, list of real row, real w) begin real c = head(children); if worst(row, w) <= worst(row++[c], w) then squarify(tail(children),row++[c], w) else layoutrow(row); squarify(children,[], width()); fi end
I've been having some trouble with a recursive chain of observables. I am working with RxJS, which is currently in version 1.0.10621, and contains most basic Rx functionality, in conjunction with Rx for jQuery. Let me introduce an example scenario for my problem: I am polling the Twitter search API (JSON response) for tweets/updates containing a certain keyword. The response also include
我一直在观察对象的递归链中遇到一些麻烦。 我正在使用RxJS，它目前在版本1.0.10621中，并且包含大部分基本的Rx功能，以及Rx for jQuery。 让我为我的问题介绍一个示例场景：我正在轮询包含特定关键字的推文/更新的Twitter搜索API（JSON响应）。 响应还包括一个“refresh_url”，用于生成后续请求。 对该后续请求的响应将再次包含新的refresh_url等。 Rx.jQuery允许我使Twitter搜索API调用一个可观察事件，该事件会产生
First of all I want to mention that I know how isNaN() and Number.isNaN() work. I am reading The Definite Guide by David Flanagan and he gives an example for how to check if the value is NaN : x !== x This will result in true if and only if x is NaN . But now I have a question: why does he use strict comparison? Because it seems that x != x behaves the same way. Is it safe to use both ve
首先我想提一下，我知道isNaN()和Number.isNaN()是如何工作的。 我正在阅读David Flanagan的The Definite Guide，他给出了一个如何检查该值是否为NaN的例子： x !== x 当且仅当x是NaN这才会true 。 但是现在我有一个问题：为什么他使用严格的比较？ 因为它似乎 x != x 表现方式相同。 使用这两个版本是否安全？或者我在JavaScript中缺少一些值，它将返回x !== x false true ，并且x != x false ？ 首先，让我指出NaN
Possible Duplicate: JavaScript === vs == : Does it matter which “equal” operator I use? The 3 different equals I'm trying to understand what is happening here: data.toPage = $('div#someID'); if ( typeof data.toPage === "string" ) { // sth console.log("hello"); } So I'm checking for a string am I not? I'm curious because my console "helloes". Th
可能重复： JavaScript === vs ==：这与我使用的“平等”运算符有关吗？ 3个不同的等于 我试图了解这里发生了什么： data.toPage = $('div#someID'); if ( typeof data.toPage === "string" ) { // sth console.log("hello"); } 所以我正在检查一个字符串，我不是吗？ 我很好奇，因为我的控制台“helloes”。 感谢您的一些意见！ ==这是相等的运算符，如果两个操作数相等，则返回布尔值true。 Jav
I am new on Javascript. However I want to implement the jquery plugin for File uploading. Here is the setup guide I found but I have no basic knowledge on how to setup this. I am using python (flask) as my server side implementation From the setup guide heading, Using jQuery File Upload (UI version) with a custom server-side upload handler I have no idea on how to setup point 1, 4, 5
我是Javascript新手。 不过，我想实现文件上传的jquery插件。 这里是我找到的设置指南，但我没有关于如何设置的基本知识。 我使用python（瓶）作为我的服务器端实现 从设置指南标题中， 使用jQuery文件上传（UI版本）和自定义的服务器端上传处理程序 我不知道如何设置点1，4，5 对于1，什么是上传处理程序？ 以及如何在python（瓶）实现？ 为4，什么剂量“上传jQuery文件上传文件夹到您的网站。”？ 它有什么用途
I am using this piece of code to determine the client screen resolution, and then logging it <input type="hidden" id="DFF63C7E-FB32-49AE-8ADA-3AB5C4834FB0" name="DFF63C7E-FB32-49AE-8ADA-3AB5C4834FB0"/> <input type="hidden" id="565C07CF-0D37-41DE-B47D-A247E9BD231B" name="565C07CF-0D37-41DE-B47D-A247E9BD231B" /> <script type="text/javascript" language="javascript"> docu
我正在使用这段代码来确定客户端屏幕分辨率，然后将其记录下来 <input type="hidden" id="DFF63C7E-FB32-49AE-8ADA-3AB5C4834FB0" name="DFF63C7E-FB32-49AE-8ADA-3AB5C4834FB0"/> <input type="hidden" id="565C07CF-0D37-41DE-B47D-A247E9BD231B" name="565C07CF-0D37-41DE-B47D-A247E9BD231B" /> <script type="text/javascript" language="javascript"> document.getElementById("DFF63C7E-FB32
I have a simple file watcher build with chokidar require('chokidar').watch('./target.txt', {}).on('all', function(event, path) { console.log(event, path); }).on('ready', function() { console.log('ready'); }); It causes change event every time when I re-save file even without changes. Is there a way to make this fire events only if actual content has been changed? You can use the stats pa
我有一个简单的文件观察者建立与chokidar require('chokidar').watch('./target.txt', {}).on('all', function(event, path) { console.log(event, path); }).on('ready', function() { console.log('ready'); }); 每当我重新保存文件，即使没有更改，它都会导致change事件。 只有在实际内容发生变化时才有办法让这种火灾事件发生？ 您可以使用add和change提供的stats参数。 这只适用于文件大小的变化，这对大多数情况
Project that I am working at (node.js) implies a lot of operations with file system (copying/reading/writing etc). I'd like to know, what methods are the fastest, and I'd be happy for some advice. 这是使用流在一行代码中复制文件的好方法： var fs = require('fs'); fs.createReadStream('test.log').pipe(fs.createWriteStream('newLog.log')); 相同的机制，但是这增加了错误处理： function copyFile
我在（node.js）工作的项目意味着很多使用文件系统的操作（复制/读取/写入等）。 我想知道，哪种方法最快，我很乐意提供一些建议。 这是使用流在一行代码中复制文件的好方法： var fs = require('fs'); fs.createReadStream('test.log').pipe(fs.createWriteStream('newLog.log')); 相同的机制，但是这增加了错误处理： function copyFile(source, target, cb) { var cbCalled = false; var rd = fs.createReadStream(sou
//How much pizza each party goer will recieve const slices = 3; //Number of slices 8 var people = 8; //Number of people 25 var pizzas = 10; //Number of pizzas 10 //pizzas ordered times the number of slices, divided by the number of people & asign slicePerson variable var slicePerson = (slices * pizzas)/people; //print out how many pieces per person console.lo
//How much pizza each party goer will recieve const slices = 3; //Number of slices 8 var people = 8; //Number of people 25 var pizzas = 10; //Number of pizzas 10 //pizzas ordered times the number of slices, divided by the number of people & asign slicePerson variable var slicePerson = (slices * pizzas)/people; //print out how many pieces per person console.lo
According to Google Calculator (-13) % 64 is 51 . According to Javascript (see this JSBin) it is -13 . How do I fix this? Number.prototype.mod = function(n) { return ((this%n)+n)%n; }; 采取这篇文章：JavaScript模块错误 Using Number.prototype is SLOW, because each time you use the prototype method your number is wrapped in an Object . Instead of this: Number.prototype.mod = function(n) {
根据谷歌计算器(-13) % 64是51 。 根据Javascript（见这JSBin）它是-13 。 我该如何解决？ Number.prototype.mod = function(n) { return ((this%n)+n)%n; }; 采取这篇文章：JavaScript模块错误 使用Number.prototype是SLOW，因为每次使用原型方法时，您的数字都包装在Object 。 取而代之的是： Number.prototype.mod = function(n) { return ((this % n) + n) % n; } 使用： function mod(n, m) { return ((n %