According the demo on http://bl.ocks.org/mbostock/3883245 I don't know how format time on xAxis this is my code : js: var data = [{ "creat_time": "2013-03-12 15:09:04", "record_status": "ok", "roundTripTime": "16" }, { "creat_time": "2013-03-12 14:59:06", "record_status": "ok", "roundTripTime": "0"
根据http://bl.ocks.org/mbostock/3883245上的演示 我不知道如何在xAxis上格式化时间 这是我的代码：js： var data = [{ "creat_time": "2013-03-12 15:09:04", "record_status": "ok", "roundTripTime": "16" }, { "creat_time": "2013-03-12 14:59:06", "record_status": "ok", "roundTripTime": "0" }, { "c
This is the first time I face the issue and can't figure out why. I'm using d3 to create an icicle chart. There is a click event that is firing and calling changePath(). I see the console log which means that I do have access to $location.path but when I try to set it nothing happens... not a new page not an error page nothing... If I don't change paths via angular my router won
这是我第一次面对这个问题，不知道为什么。 我正在使用d3创建一个冰柱图表。 有一个点击事件触发并调用changePath（）。 我看到控制台日志，这意味着我有权访问$ location.path，但是当我尝试设置它时，没有任何反应......不是新页面而是错误页面没有任何内容......如果我不通过角度更改路径我的路由器不会维护我正在寻找的范围......任何线索？ var parentCtrl = function($scope,$location){ $scope.makeBSC = function()
I am trying to create a Flot pie chart with a link in each wedge, so I can direct users to the appropriate details page on clicking. There is already a similar post at With flot, how can I create a linked pie chart that takes you to other web pages?. I tried the answer on that page with with Flot 0.7 to obtain pie wedges with hyperlinked labels. However, series.URL returns "undefined&quo
我正在尝试创建一个Flot饼图，每个楔形图都有一个链接，因此我可以将用户引导至点击相应的详细信息页面。 在With flot中已经有一个类似的帖子，我怎样才能创建一个链接饼图来把你带到其他网页？ 我使用Flot 0.7在该页面上尝试了这个答案，以获得带有超链接标签的馅饼楔子。 但是，series.URL在labelFormatter函数中返回“undefined”。 我该如何解决这个问题？ 附注 ：我第一次在这里发表。 我试图在上面的链接中询问这个
I'm a keen advocate of feature detection opposed to device detection. I'd like to be able to detect whether a browser (mobile or otherwise) supports Silverlight. I've had a good google and found this Silverlight supported user agent but looking at the last comment it does not seem to be up to date. There is also this SO question Is there a way to test if a browser supports flash/
我非常热衷于功能检测，而不是设备检测。 我希望能够检测浏览器（移动或其他）是否支持Silverlight。 我有一个很好的谷歌，并发现这个Silverlight支持的用户代理，但看看最后的评论它似乎并不是最新的。 还有这个SO问题有没有一种方法来测试浏览器是否支持flash / silverlight？ 但似乎没有回答这个问题。 检测Silverlight是否安装与检测对Silverlight的支持不同。 有没有人有这方面的经验，是否有可能？ 检测Silverl
I'm trying to write a video viewer that draws parts of a video element onto an HTML canvas using drawImage , but this is not supported on some devices (iOS, for example). Rather than sniffing the browser/OS, I'd rather do feature detection and fall back to just playing the normal video on these devices. Is there a reliable way to test for this functionality? check this: function isCa
我试图编写一个使用drawImage将视频元素的一部分绘制到HTML画布上的视频查看器，但某些设备（例如iOS）不支持此视图元素。 我宁愿做功能检测，然后回到在这些设备上播放普通视频，而不是嗅探浏览器/操作系统。 有没有可靠的方法来测试这个功能？ 检查这个： function isCanvasSupported() { var canvas = document.createElement('canvas'); return !!(canvas.getContext && canvas.getContext('2d')); }; 如
How can I detect support for WebP via Javascript? I'd like to use feature detection rather than browser detection if possible, but I can't find a way to do so. Modernizr (www.modernizr.com) doesn't check for it. I think something like this might work: var hasWebP = false; (function() { var img = new Image(); img.onload = function() { hasWebP = !!(img.height > 0 &&a
如何通过Javascript检测对WebP的支持？ 如果可能的话，我想使用功能检测而不是浏览器检测，但我找不到这样做的方法。 Modernizr（www.modernizr.com）不检查它。 我认为这样的事情可能会起作用： var hasWebP = false; (function() { var img = new Image(); img.onload = function() { hasWebP = !!(img.height > 0 && img.width > 0); }; img.onerror = function() { hasWebP = false; };
I know that in Safari on an iPhone you can detect the screen's orientation and change of orientation by listening for the onorientationchange event and querying window.orientation for the angle. Is this possible in the browser on Android phones? To be clear, I am asking whether the rotation of an Android device can be detected by JavaScript running on a standard web page. It is possible
我知道在iPhone上的Safari中，您可以通过侦听onorientationchange事件和查询window.orientation角度来检测屏幕的方向和方向更改。 这在Android手机的浏览器中可能吗？ 很明显，我在问一个标准网页上运行的JavaScript是否可以检测到Android设备的旋转。 这可能是在iPhone上，我想知道是否可以为Android手机完成。 要在Android浏览器上检测方向更改，请将侦听器附加到orientationchange或在window上resize事件resize ： //
This piece of code works great in DESKTOP browsers (code courtesy of @Rob-W), click the thumbnail and the adjacent video will start playing, using YouTube's API. HTML <div id="tabs2"> <div> <img class='thumb' src='http://i2.cdnds.net/11/34/odd_alan_partridge_bio_cover.jpg'> <iframe id="frame1" width="640" height="390" frameborder="0" title="YouTube video pl
这段代码在DESKTOP浏览器（代码礼貌@ @ Rob-W）中效果很好，单击缩略图，相邻视频将使用YouTube的API开始播放。 HTML <div id="tabs2"> <div> <img class='thumb' src='http://i2.cdnds.net/11/34/odd_alan_partridge_bio_cover.jpg'> <iframe id="frame1" width="640" height="390" frameborder="0" title="YouTube video player"type="text/html"src="http://www.youtube.com/embed/u1zgFl
This question already has an answer here: What is the best way to detect a mobile device in jQuery? 49 answers You could use a Responsive Design approach and achieve what you want with only css, using media queries: //THIS CSS CLASS IS APPLIED ALWAYS div.my-option { display: none; } //THIS MEDIA QUERY APPLIES ITS STYLES ONLY WHEN THE SCREEN WIDTH IS <= 767, SO IT'S A SMARTPHONE DISP
这个问题在这里已经有了答案： 在jQuery中检测移动设备的最佳方式是什么？ 49个答案 您可以使用响应式设计方法，并使用媒体查询来实现您只需使用CSS的内容： //THIS CSS CLASS IS APPLIED ALWAYS div.my-option { display: none; } //THIS MEDIA QUERY APPLIES ITS STYLES ONLY WHEN THE SCREEN WIDTH IS <= 767, SO IT'S A SMARTPHONE DISPLAY. //IT OVERRIDES THE ONE ABOVE @media only screen and ( max-width:
This question already has an answer here: What is the best way to detect a mobile device in jQuery? 49 answers You can use the .width method in jquery to determine the width of the window and just change the object properties accordingly. You can use it like this: <script> if ($( window ).width() < 600) { $("#zoom_01").elevateZoom({ gallery:'gallery_01', zoomEnabled: false,
这个问题在这里已经有了答案： 在jQuery中检测移动设备的最佳方式是什么？ 49个答案 您可以使用jQuery中的.width方法来确定窗口的宽度，并相应地更改对象属性。 你可以像这样使用它： <script> if ($( window ).width() < 600) { $("#zoom_01").elevateZoom({ gallery:'gallery_01', zoomEnabled: false, cursor: 'pointer', galleryActiveClass: 'active' } else { $("#zoom_01").elevateZoom({