Note: this appears to have been fixed in Roslyn This question arose when writing my answer to this one, which talks about the associativity of the null-coalescing operator. Just as a reminder, the idea of the null-coalescing operator is that an expression of the form x ?? y first evaluates x , then: If the value of x is null, y is evaluated and that is the end result of the expression I
注意：这似乎已在Roslyn中修复 这个问题出现在我写这个答案的时候，它谈到了空合并算子的关联性。 需要提醒的是，空合并运算符的思想是表达式 x ?? y 首先评估x ，然后： 如果x值为空，则评估y ，这是表达式的最终结果 如果x的值非空，则不计算y ，并且在必要时将y转换为编译时类型之后， x的值是表达式的最终结果 现在通常不需要转换，或者它只是从可空类型转换为不可空的类型 - 通常类型是相同的，或者仅仅来自（
I have an application which uses SslStream to send and receive data with its own fixed-length framing. The stream is created by wrapping the NetworkStream returned from TcpClient.GetStream() like so: var client = new TcpClient(); client.Connect(host, port); var sslStream = new SslStream(client.GetStream(), false, callback, null); sslStream.AuthenticateAsClient(hostname); Because the protocol i
我有一个应用程序使用SslStream以自己的固定长度帧发送和接收数据。 该流是通过包装从TcpClient.GetStream()返回的NetworkStream创建的，如下所示： var client = new TcpClient(); client.Connect(host, port); var sslStream = new SslStream(client.GetStream(), false, callback, null); sslStream.AuthenticateAsClient(hostname); 由于该协议是完全异步的（框架“消息”在任意时间到达并且允许客户端在任意时间发送它们）
Is it possible to implement a class constrained to two unique generic parameters? If it is not, is that because it is unimplemented or because it would be impossible given the language structure (inheritance)? I would like something of the form: class BidirectionalMap<T1,T2> where T1 != T2 { ... } I am implementing a Bidirectional dictionary. This is mostly a question of curiosity,
是否可以实现一个受限于两个唯一通用参数的类？ 如果不是，那是因为它没有实现，或者因为语言结构（继承）而不可能？ 我想要一些形式： class BidirectionalMap<T1,T2> where T1 != T2 { ... } 我正在实现一个双向字典。 这主要是好奇心问题，而不是需要。 从评论中解释： 丹：“如果这个限制没有得到满足，会有什么负面影响？” 我：“然后用户可以使用map [t1]和map [t2]来索引，如果它们是相同的类型，那么
edit: My main question now is why these two operators need to be overloaded to use the && and || operators. Wouldn't the short-circuit operators take the true or false values of the objects and compare those? Where in the use of the && and || operators is | and & used? I'm reading C#, the complete reference, and I'm quite confused about the | and & oper
编辑：我现在的主要问题是为什么这两个运算符需要重载使用&&和|| 运营商。 短路操作人员不会采用这些物体的真值还是假值进行比较？ 在何处使用&&和|| 运营商是| 和＆使用？ 我正在阅读完整的参考文献C＃，对于|我很困惑 和＆运营商。 我习惯于他们是比较两个整数比特的按位运算符，但它们被解释为原始逻辑运算符，并且&&和|| 是当声明肯定会成为一定值时，停止测试值的短路版本。 这是否意
I understand that the single ampersand operator is normally used for a 'bitwise AND' operation. However, can anyone help explain the interesting results you get when you use it for comparison between two numbers? For example; (6 & 2) = 2 (10 & 5) = 0 (20 & 25) = 16 (123 & 20) = 16 There seems to be no logical link between these results - am I missing something? Onlin
我知道单个＆符号运算符通常用于“按位与”操作。 然而，任何人都可以帮助解释当你用它来比较两个数字时你得到的有趣结果吗？ 例如; (6 & 2) = 2 (10 & 5) = 0 (20 & 25) = 16 (123 & 20) = 16 这些结果似乎没有逻辑联系 - 我错过了什么？ 在线文档似乎只涉及布尔值或单个比特的比较。 比较每一个的二进制表示。 110 & 010 = 010 1010 & 0101 = 0000 10100 & 11001
I am attempting to determine if I can compute the sum of two 32 bit integers without overflow, while making use of only certain bitwise and other operators. So, if the integers x and y can be added without overflow, the following code should return 1, and 0 otherwise. (((((x >> 31) + (y >> 31)) & 2) >> 1)) However, it returns 0 when it should be 1 and vice versa. When I
我试图确定是否可以计算两个32位整数的总和而不会溢出，同时仅使用某些按位和其他运算符。 因此，如果可以添加整数x和y而不溢出，则以下代码应该返回1，否则返回0。 (((((x >> 31) + (y >> 31)) & 2) >> 1)) 但是，它应该是1时返回0，反之亦然。 当我使用逻辑NOT（！）运算符或与0x1按位异或（^）时，它不能解决问题。 !(((((x >> 31) + (y >> 31)) & 2) >> 1)) (((((x >&g
I have a web service project with several web services. Two of this web services share an enum that is defined in a BL class, like so: public class HumanResourcesService { public SomeLibrary.Employee GetEmployee(int employeeCode) { var employee = new SomeLibrary.Employee(); employee.Type= SomeLibrary.EmployeeType.SomeType; return employee ; } } public class Ban
我有一个Web服务项目与几个Web服务。 其中两个Web服务共享一个在BL类中定义的枚举，如下所示： public class HumanResourcesService { public SomeLibrary.Employee GetEmployee(int employeeCode) { var employee = new SomeLibrary.Employee(); employee.Type= SomeLibrary.EmployeeType.SomeType; return employee ; } } public class BankService { public bool ProcessPayment(int
I have some security built into a client side program that downloads a DLL from the web, and called a function inside that DLL. The DLL is strong-named, and the function in the DLL uses Assembly.GetCallingAssembly() to determine the calling assembly so that I can accurately get a path to the program who called it. From there we do a hash check of the assembly and verify that it is the correct o
我在客户端程序中内置了一些安全性，从网上下载DLL，并在该DLL内部调用一个函数。 DLL是强命名的，并且DLL中的函数使用Assembly.GetCallingAssembly()来确定调用程序集，以便我可以准确地获取调用它的程序的路径。 从那里我们对组件进行散列检查，并验证它是否正确。 我们有人以完全信任模式连接到自己，并且可以欺骗GetCallingAssembly调用以指向真正的可执行文件，同时它们运行修改后的版本。 有没有其他的GetCallingAsse
I am using AvalonDock in a project to take advantage of the tool windows. I don't have any need for Tabbed Documents and would like to disable the "Dock as Tabbed Document" context menu item when I right click on a tool window title bar. Is this possible? Thanks i think this is a simple property setting. i use the latest source from codeplex 76560. you can change the Docka
我在项目中使用AvalonDock以利用工具窗口。 我不需要任何选项卡式文档，并且希望在右键单击工具窗口标题栏时禁用“Dock as Tabbed Document”上下文菜单项。 这可能吗？ 谢谢 我认为这是一个简单的属性设置。 我使用codeplex 76560的最新源代码。 您可以将DockableStyle属性更改为所需的样式： <ad:SampleDockableContent DockableStyle="DockableToBorders" x:Name="DockingManagerPropertiesHo
I've a C# application that is targeted to .Net framework 3.5 version. The binary worked fine when .Net framework 3.5 is installed. But it is giving some incompatability isssues with .Net 4.0 I'm seeing the following exception: Caught exception at Method: InitializeComponent Line: 0 Column: 0 Exception: Could not load file or assembly 'WindowsFormsIntegration, Version=3.0.0.0, Cu
我有一个针对.Net framework 3.5版本的C＃应用程序。 当安装.Net framework 3.5时，二进制工作正常。 但它给.Net 4.0带来了一些不可兼容性问题 我看到以下例外情况： 捕获异常在方法：InitializeComponent行：0列：0例外：无法加载文件或程序集'WindowsFormsIntegration，版本= 3.0.0.0，文化=中立，PublicKeyToken = 31bf3856ad364e35'或其依赖项之一。 该系统找不到指定的文件。 我认为您需要解决的所有信