我如何使用automapper更新另一个对象的属性值而不创建新的对象? Use the overload that takes the existing destination: Mapper.Map<Source, Destination>(source, destination); Yes, it returns the destination object, but that's just for some other obscure scenarios. It's the same object. To make this work you have to CreateMap for types of source and destination even they are same type
我如何使用automapper更新另一个对象的属性值而不创建新的对象? 使用占用现有目标的过载: Mapper.Map<Source, Destination>(source, destination); 是的,它会返回目标对象,但这仅仅适用于其他一些模糊的场景。 这是同一个对象。 要做到这一点,即使它们是相同的类型,也必须使用CreateMap来处理源和目标类型。 这意味着如果你想Mapper.Map<User, User>(user1, user2); 你需要像这样创建地图Mapper.Create
I have a sequence of numbers to generate, and I want to generate it using some sort of algorithm (iterative or recursive, doesn't matter). Contextualizing: This numbers are indexes to iterative over a list of lists. I need to do a permutation (combination, i don't know exactly), but I need to generate all combinations of all positions of that list of lists. The sequence and the outpu
我有一串数字来生成,我想用某种算法来生成它(迭代或递归,无所谓)。 情境化:这些数字是在列表列表上迭代的索引。 我需要做一个排列(组合,我不知道确切),但我需要生成列表的所有位置的所有组合。 我试图得到的序列和输出是: 1 1 2 1 3 1 4 1 5 1 1 2 2 1 3 1 4 1 5 1 1 3 2 1 3 1 4 1 5 1 1 4 2 1 3 1 4 1 5 1 1 5 2 1 3 1 4 1 5 1 1 1 2 2 3 1 4 1 5 1 1 2 2 2 3 1 4 1 5 1 1 3 2 2 3 1 4 1 5 1 1 4 2 2 3
I'm trying to implement a tolerable-quality version of the rand_r interface, which has the unfortunate interface requirement that its entire state is stored in a single object of type unsigned , which for my purposes means exactly 32 bits. In addition, I need its output range to be [0,2³¹-1] . The standard solution is using a LCG and dropping the low bit (which has the shortest period), but
我试图实现rand_r接口的可容忍质量版本,它具有不幸的接口要求,它的整个状态存储在一个unsigned类型的单个对象中,这对我来说意味着正好是32位。 另外,我需要它的输出范围是[0,2³¹-1] 。 标准解决方案是使用LCG并丢弃低位(具有最短的周期),但是这对于接下来的几位仍然留下很差的周期。 我最初的想法是使用LCG的两到三次迭代来生成输出的高/低或高/中/低位。 但是,这种方法并不能保留非偏向分布; 而不是每个具有相同
I've just finished building these tables for dual marching cubes (by Nielson). VerticesNumberTable contains the length of the array of vertices to create for each Voxel (1 to 4 internal vertices), while EdgesTable is used to assign every one of these vertices to the right edges of the voxel, in order to use them to calculate internal vertex position and normal. Edgetable works a little like
我刚完成建造这些双重行军立方体的桌子(Nielson)。 VerticesNumberTable包含要为每个体素(1到4个内部顶点)创建的顶点数组的长度,而EdgesTable用于将这些顶点中的每个顶点分配给体素的右边缘,以便使用它们来计算内部顶点位置正常。 Edgetable的工作原理与triTable有些相似,适用于原始游行Cubes算法。 每一组边被下一个由-1分开。 该列表以-2结束,所以这个值可以用来打破一个循环。 #region EdgesTable public st
How would you divide a number by 3 without using * , / , + , - , % , operators? The number may be signed or unsigned. This is a simple function which performs the desired operation. But it requires the + operator, so all you have left to do is to add the values with bit-operators: // replaces the + operator int add(int x, int y) { while (x) { int t = (x & y) << 1;
如何将数字除以3而不使用* , / , + , - , % ,运算符? 该号码可以是有符号的或无符号的。 这是一个执行所需操作的简单功能。 但它需要+运算符,所以你只需要用位运算符来添加值: // replaces the + operator int add(int x, int y) { while (x) { int t = (x & y) << 1; y ^= x; x = t; } return y; } int divideby3 (int num) { int sum = 0; while (num &g
How to prepare a Silverlight or WPF application to change from a big resolution to a small resolution? I guess using dockpanel strategy only works for changing from a small to a big resolution. So, is there any default strategy? Thanks. Problem: I have a button the ends in the pixel 1024, 768. And I change the resolution to 800x600. Some time ago I had a similar issue. As a workaround I
如何准备Silverlight或WPF应用程序以从大分辨率更改为小分辨率? 我想使用dockpanel策略只适用于从小到大的分辨率。 那么,是否有任何默认策略? 谢谢。 问题:我在像素1024,768中有一个按钮,并将分辨率更改为800x600。 前段时间我有类似的问题。 作为解决方法,我将窗口内容包围在Viewbox中 。 使用1024x768而不是1280x1024的用户可以看到应用程序内容更小,但他们更喜欢这一点,而不是始终滚动。 (WPF) 我必
I am seeing some entries of the following exception in my logs and dont know why or where its occurring: Failed to Execute URL. at System.Web.Hosting.ISAPIWorkerRequestInProcForIIS6.BeginExecuteUrl(String url, String method, String childHeaders, Boolean sendHeaders, Boolean addUserIndo, IntPtr token, String name, String authType, Byte[] entity, AsyncCallback cb, Object state) at System.Web
我在日志中看到以下异常的一些条目,并且不知道其发生的原因或位置: Failed to Execute URL. at System.Web.Hosting.ISAPIWorkerRequestInProcForIIS6.BeginExecuteUrl(String url, String method, String childHeaders, Boolean sendHeaders, Boolean addUserIndo, IntPtr token, String name, String authType, Byte[] entity, AsyncCallback cb, Object state) at System.Web.HttpResponse.BeginExecuteUrlForEntireRe
Hey friends i need to export records of datagridview of winform to MSExcel. I want to do it without using any DLL ie, with the buid in properties of C#. So is there any good solution for my problem? Export the data as CSV file. Excel can read those fine. A common way to do this would be through MSOffice PIAs. Is that what you'd like to avoid? You can read the values from data grid u
嗨,我需要将winform的datagridview记录导出到MSExcel。 我想要做到这一点,而不使用任何DLL,即在C#的属性buid。 那么对于我的问题有什么好的解决方案吗? 将数据导出为CSV文件。 Excel可以读取那些罚款。 一个常见的做法是通过MSOffice PIA。 那是你想避免的吗? 您可以使用反射从数据网格读取值,也可以将绑定到数据网格的数据模型创建为csv文件。 MS Excel可以读取csv文件。
I see that this question has been answered for Java, JavaScript, and PHP, but not C#. So, how might one calculate the number of days between two dates in C#? 假设StartDate和EndDate的类型为DateTime : (EndDate - StartDate).TotalDays 使用日期减法结果的TimeSpan对象: DateTime d1; DateTime d2; return (d1 - d2).TotalDays; The top answer is correct, however if you would like only WHOLE days as an in
我发现这个问题已经为Java,JavaScript和PHP解决,但不是C#。 那么,如何计算C#中两个日期之间的天数呢? 假设StartDate和EndDate的类型为DateTime : (EndDate - StartDate).TotalDays 使用日期减法结果的TimeSpan对象: DateTime d1; DateTime d2; return (d1 - d2).TotalDays; 最重要的答案是正确的,但是如果您只想将整天作为整数并且乐于放弃日期的时间部分,那么请考虑: (EndDate.Date - StartDate.Date).Days 再
How often you use bitwise operation "hacks" to do some kind of optimization? In what kind of situations is it really useful? Example: instead of using if: if (data[c] >= 128) //in a loop sum += data[c]; you write: int t = (data[c] - 128) >> 31; sum += ~t & data[c]; Of course assuming it does the same intended result for this specific situation. Is it worth it?
你经常使用按位操作“黑客”来进行某种优化? 它在哪种情况下真的有用? 示例:而不是使用if: if (data[c] >= 128) //in a loop sum += data[c]; 你写: int t = (data[c] - 128) >> 31; sum += ~t & data[c]; 当然,假设它在这个特定的情况下有相同的预期结果。 这值得么? 我觉得它是不可读的。 你多久碰到一次? 注意:我在选择的答案中看到了下面的代码:为什么处理排序后的数组要比未排序的数