Well I know other people are having the same problem, and I did see a similar question already on Stack Overflow, but I'm still having problems. I updated the latest JRE (prompted to as soon as I opened Aptana) and now when I run Aptana, the menu bar is gone and replaced with the menu bar of the last application window I had open (Right now, Chrome). The solution I found was to install the
那么我知道其他人也有同样的问题，并且我已经看到Stack Overflow上的类似问题，但是我仍然遇到问题。 我更新了最新的JRE（当我打开Aptana时提示），现在当我运行Aptana时，菜单栏消失了，并替换为我打开的最后一个应用程序窗口（现在，Chrome）的菜单栏。 我找到的解决方案是安装Aptana的最新修补程序，但指示说要通过浏览未出现的菜单栏来更新它。 谈论拉我的头发。 很明显，我可以做一个完整的应用程序重新安装，但我想避
hi guys i have a little problem here to solve. I have created an equals() method which is only based on the class of the object so that if two obj are of the same class the obj1.equals(obj2) return true. now my question is, How do i implement a hashcode() based only on the obj Class ?? @Override public boolean equals(Object obj){ if(obj.getClass() == this.getClass()){ return true;
嗨，大家好我有一个小问题在这里解决。 我创建了一个仅基于对象的类的equals（）方法，因此如果两个obj具有相同的类，则obj1.equals（obj2）返回true。 现在我的问题是，我如何实现一个基于obj类的hashcode（）？ @Override public boolean equals(Object obj){ if(obj.getClass() == this.getClass()){ return true; }else{ return false; } } 你可以返回Class实例的hashCode ： public int h
Say I have my own class public class MyObj { /* ... */ } It has some attributes and methods. It DOES NOT implement equals, DOES NOT implement hashCode. Once we call equals and hashCode, what are the default implementations? From Object class? And what are they? How the default equals will work? How the default hashCode will work and what will return? == will just check if they reference
说我有我自己的班级 public class MyObj { /* ... */ } 它有一些属性和方法。 它不实现equals，不实现hashCode。 一旦我们调用equals和hashCode，什么是默认实现？ 从Object类？ 它们是什么？ 默认等于如何工作？ 默认的hashCode将如何工作，返回什么？ ==会检查它们是否引用同一个对象，所以它很容易，但equals（）和hashCode（）方法呢？ 是的，默认实现是Object（一般来说，如果您从重新定义equals和/或hashCode
When a class in Java doesn't override hashCode() , printing an instance of this class gives a nice unique number. The Javadoc of Object says about hashCode() : As much as is reasonably practical, the hashCode method defined by class Object does return distinct integers for distinct objects. But when the class overrides hashCode() , how can I get it's unique number? System.identity
当Java中的类不覆盖hashCode（）时 ，打印此类的实例将提供一个很好的唯一编号。 Object的Javadoc说关于hashCode（） ： 尽可能合理实际，由Object类定义的hashCode方法确实为不同的对象返回不同的整数。 但是当类重写hashCode（）时 ，我怎样才能得到它的唯一编号？ System.identityHashCode（yourObject）将把yourObject的'original'哈希码作为整数。 唯一性不一定得到保证。 Sun JVM实现将为您提供一个与此
When overriding the equals() function of java.lang.Object, the javadocs suggest that, it is generally necessary to override the hashCode method whenever this method is overridden, so as to maintain the general contract for the hashCode method, which states that equal objects must have equal hash codes. The hashCode() method must return a unique integer for each object (this is easy to do when
当重写java.lang.Object的equals（）函数时，javadoc提示， 通常需要在重写此方法时重写hashCode方法，以便维护hashCode方法的一般约定，该方法声明相等对象必须具有相同的哈希代码。 hashCode（）方法必须为每个对象返回一个唯一的整数（当根据内存位置比较对象时，这很容易做到，只需返回对象的唯一整数地址） hashCode（）方法应该如何重写，以便它仅基于该对象的特性为每个对象返回唯一的整数？ public class People{
This a follow-up to chrert's question Generic classes with Collection getter of other types. If you can come up with a better title to my question, feel free to edit it: Following code contains a generic class GenericClass<T> with a method of return type T and another method with return type Collection<String> , which is obviously independent of T . Now, if I instantiate a ra
这是chrert的问题的后续跟其他类型的Collection getter的泛型类。 如果您能为我的问题想出更好的标题，请随时编辑它： 下面的代码包含一个带有返回类型T的方法的泛型类GenericClass<T> ，以及返回类型为Collection<String>另一个方法，这显然与T无关。 现在，如果我实例化一个原始GenericClass （我永远不会这样做，所以这个问题更多的是一个理论问题，以帮助理解发生了什么），那么在增强for循环中调用该方法
I am fetching the data from webservice, which I am parsing to JSON string. While parsing I am this exception: "org.json.JSONException: Unterminated string at character 1834" my code is, String jsonstring=getJSONString(response); JSONObject json = new JSONObject(jsonstring); The string is, [{"LotDescription":"David Weekley homes Traditional Collection in Baxter Village offers floo
我从Web服务中获取数据，我将其解析为JSON字符串。 解析时，我是这个异常：“org.json.JSONException：在字符1834未终止的字符串” 我的代码是， String jsonstring=getJSONString(response); JSONObject json = new JSONObject(jsonstring); 字符串是， [{"LotDescription":"David Weekley homes Traditional Collection in Baxter Village offers floor plans featuring innovative design and unsurpassed quality. This
I have created a shared library with some jar files in weblogic server, now I have an EAR application and I want to use the class files from shared library in my web applications present in EAR application. So I have created weblogic-application.xml file inside my ear-app/META-INF/ directory and gave reference to shared library using below tags: <library-ref> <library-name>ebs_e
我已经在weblogic服务器上创建了一个包含一些jar文件的共享库，现在我有一个EAR应用程序，并且想要在EAR应用程序中的Web应用程序中使用共享库中的类文件。 所以我在我的ear-app/META-INF/目录下创建了weblogic-application.xml文件，并使用下面的标签给共享库引用： <library-ref> <library-name>ebs_endeca_artifacts</library-name> </library-ref> 但是当我尝试访问我的应用程序中的类文件时
I have decompiled a class with javap and I'm seeing some duplicates in the Constant Pool section, like this: #19 = Class #350 // java/lang/StringBuilder ... Some other class constants here #318 = Class #350 // java/lang/StringBuilder Methodrefs refer to only one of them: #20 = Methodref #19.#351 // java/lang/StringBuilder."<
我用javap反编译了一个类，我在常量池部分看到了一些重复内容，如下所示： #19 = Class #350 // java/lang/StringBuilder ... Some other class constants here #318 = Class #350 // java/lang/StringBuilder Methodrefs仅涉及其中的一个： #20 = Methodref #19.#351 // java/lang/StringBuilder."<init>":()V #22 = Methodref #19.#353
I am developing one application in which i have draw the polygon on map and map that I have used is not google,Its Mapsforge opensource offline map library.i have easily draw polygon on map by converting geopoint into pixcel point.but here i want to find are of that irregular polygon,and for that i have make lots of try but its getting me unsuccess.. I have tried with calculate area with basic Ma
我正在开发一个应用程序，在该应用程序中，我在地图和地图上绘制了多边形，我使用的不是Google，它的Mapsforge开放源代码离线地图库。通过将地理点转换为像素点，可以轻松地在地图上绘制多边形。但是，此处我想发现是不规则的多边形，为此，我做了很多尝试，但它让我不成功..我已经尝试用基本数学计算面积，但它不工作在这种情况下，情况下pixcel是改变accodingly而改变缩放级别。 这里是数学逻辑：数学计算 for(int miAreainc