I am searching a way to draw a circle using Andengine. As I can see, I can only draw lines, rectangles, and place sprites, but I cannot find a way to draw circles. How can I do this? Indeed, you can't directly draw a circle. Alternatives are: Rendering a quad with a circle texture (see this link, for example) Rendering a circle that's actually a circle of connected triangles. Yo
我正在寻找一种使用Andengine绘制圆圈的方法。 正如我所看到的，我只能绘制线条，矩形和放置小精灵，但我找不到绘制圆的方法。 我怎样才能做到这一点？ 事实上，你不能直接画一个圆圈。 替代选择是： 使用圆形纹理渲染四边形（例如，请参阅此链接） 渲染实际上是连接三角形的圆的圆。 你必须程序化地生成几何来近似一个圆。 对于一个坚实的圈子来说，这并不难。 我猜想，一个空心的圆圈/圆圈轮廓，有点牵扯。 如果
I am very familiar with functional langauges such as Scheme, and Haskell. I'm trying to solve a problem in Java and struggling, possibly because I'm still in a functional mindset. I want to write: public void doQueryAndStoreData(String query, <? extends Collection> storeIn) { /* make a jdbc query, get ResultSet */ ResultSet rset = ...; ProcessResultSet proc = new Pro
我对Scheme，Haskell等功能语言非常熟悉。 我试图解决Java中的一个问题并且挣扎，可能是因为我仍然处于功能性思维模式。 我想写： public void doQueryAndStoreData(String query, <? extends Collection> storeIn) { /* make a jdbc query, get ResultSet */ ResultSet rset = ...; ProcessResultSet proc = new ProcessResultSet(); proc.process(rset, storeIn); /* clean up */ } 带有如下界
I am trying to create a table in MATLAB where I can change the scroll position programmatically. I created a uitable and extracted the handle of the Java UITablePeer object (designated here as htable ). I then got the handle for the UIScrollbarPane object using: hscroll = htable.getParent.getParent.getVerticalScrollBar At this point, the figure looks like this (my actual table is more compli
我试图在MATLAB中创建一个表格，我可以通过编程方式更改滚动位置。 我创建了一个uitable并提取了Java的手柄UITablePeer对象（这里命名为htable ）。 然后使用以下命令获得UIScrollbarPane对象的句柄： hscroll = htable.getParent.getParent.getVerticalScrollBar 在这一点上，这个图像看起来像这样（我的实际表格更复杂，这只是我作为一个例子）： 桌子左下角的盒子是一个pushbutton 。 当它的回调被触发时，它使用setV
I've got a Spring MVC, Spring Thymeleaf, Spring Security and Hibernate on MySQL application. My task is to notify to all currently logged in users if there is new data persisted for the page they are viewing so that the users can refresh and get a new set of data. I was guessing that I could store all the logged in users in an ApplicationScope session and then notify them somehow. But I&#
我在MySQL应用程序上有Spring MVC，Spring Thymeleaf，Spring Security和Hibernate。 我的任务是向所有当前登录的用户通知是否有新数据保留在他们正在查看的页面上，以便用户可以刷新并获取一组新数据。 我猜测我可以将所有登录的用户存储在ApplicationScope会话中，然后以某种方式通知他们。 但我从来没有这样做过，不确定它会是多么安全。 任何人都可以提出任何想法如何做到这一点？ 您需要推/拉架构（从服务器端发起
I'm trying to follow this tutorial https://developer.android.com/training/camera/photobasics.html#TaskPath for taking an image and saving the file. It opens the camera, I take a picture, click the check mark, then it crashes. I have found several articles on StackOverflow and have tried all of their solutions that I could understand (which were file.mkdirs() , file.getParentFile().mkdirs()
我试图按照此教程https://developer.android.com/training/camera/photobasics.html#TaskPath拍摄图像并保存文件。 它会打开相机，拍摄照片，单击复选标记，然后崩溃。 我在StackOverflow上发现了几篇文章，并尝试了我可以理解的所有解决方案（它们分别是file.mkdirs() ， file.getParentFile().mkdirs() ）。 看来，即使它是一个RuntimeException，根本问题是IOException（我捕获并打印该消息）。 我正在使用Genymotion，
im trying to create my Photo-app orientating on this example http://www.androidhive.info/2013/09/android-working-with-camera-api/ public void onClick(View view) { Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE); // create Intent to take a picture and return control to the calling application fileUri = getOutputMediaFileUri(MEDIA_TYPE_IMAGE); // create a
即时尝试创建我的照片应用程序定位在这个例子http://www.androidhive.info/2013/09/android-working-with-camera-api/ public void onClick(View view) { Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE); // create Intent to take a picture and return control to the calling application fileUri = getOutputMediaFileUri(MEDIA_TYPE_IMAGE); // create a file to save the i
I get such output error: Exception while loading the app : java.lang.IllegalStateException: ContainerBase.addChild: start: org.apache.catalina.LifecycleException: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'myDBAuthenticationService': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreatio
我得到这样的输出错误： 加载应用程序时出现异常：java.lang.IllegalStateException：ContainerBase.addChild：start：org.apache.catalina.LifecycleException：org.springframework.beans.factory.BeanCreationException：创建名为'myDBAuthenticationService'的Bean时出错：注入自动装配依赖项失败; 嵌套异常是org.springframework.beans.factory.BeanCreationException：无法自动装入字段：private org.o7plannin
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'mongoTemplate' defined in class com.socketcruiter.config.SpringMongoConfig: Instantiation of bean failed; nested exception is org.springframework.beans.factory.BeanDefinitionStoreException: Factory method [public org.springframework.data.mongodb.core.MongoTemplate org.springframework.data.mongodb.conf
org.springframework.beans.factory.BeanCreationException：在类com.socketcruiter.config.SpringMongoConfig中定义名称为'mongoTemplate'的bean时出错：Bean实例化失败; 嵌套异常是org.springframework.beans.factory.BeanDefinitionStoreException：工厂方法[public org.springframework.data.mongodb.core.MongoTemplate org.springframework.data.mongodb.config.AbstractMongoConfiguration.mongoTemplate（）thr
I use eclipse to develop. My spring project can run on Mac, but can't run on CentOS. I can't find out why. It seems like it can't create bean on CentOS. Please give me some directions. Here is some console: Caused by: org.springframework.beans.factory.BeanDefinitionStoreException: Factory method [public org.springframework.data.mongodb.gridfs.GridFsTemplate ... throws java.
我使用eclipse来开发。 我的春季项目可以在Mac上运行，但无法在CentOS上运行。 我找不到原因。 看来它不能在CentOS上创建bean。 请给我一些指导。 这是一些控制台： 原因：org.springframework.beans.factory.BeanDefinitionStoreException：工厂方法[public org.springframework.data.mongodb.gridfs.GridFsTemplate ...抛出java.lang.Exception]抛出异常; 导致：org.springframework.beans.factory.BeanCreationE
Hello this error i've been getting when i try to run a main test on my neo4j spring data project Unexpected exception parsing XML document from class path resource [neo4j.xml]; nested exception is org.springframework.beans.FatalBeanException: Invalid NamespaceHandler class [org.springframework.data.neo4j.config.Neo4jNamespaceHandler] for namespace [http://www.springframework.org/schema/dat
你好，当我尝试在我的neo4j spring数据项目上运行一个主测试时，我得到了这个错误 意外的异常解析来自类路径资源的XML文档[neo4j.xml]; 嵌套的异常是org.springframework.beans.FatalBeanException：命名空间[http://www.springframework.org/schema/data/neo4j]的无效NamespaceHandler类[org.springframework.data.neo4j.config.Neo4jNamespaceHandler]：处理程序问题类文件或依赖类; 嵌套异常是java.lang.NoClassDefFoundE