I have an Order class that has a list of OrderTransactions and I mapped it with a one-to-many Hibernate mapping like so: @OneToMany(targetEntity = OrderTransaction.class, cascade = CascadeType.ALL) public List<OrderTransaction> getOrderTransactions() { return orderTransactions; } These Order s also have a field orderStatus , which is used for filtering with the following Criteria: pu
我有一个Order类，它有一个OrderTransactions列表，我用一对多的Hibernate映射映射它，如下所示： @OneToMany(targetEntity = OrderTransaction.class, cascade = CascadeType.ALL) public List<OrderTransaction> getOrderTransactions() { return orderTransactions; } 这些Order也有一个字段orderStatus ，用于按以下标准进行过滤： public List<Order> getOrderForProduct(OrderFilter orderFilter) {
Updated Question I have 3 tables like Section (id, title, url)//id is Primary key Category (id, title)//id is Primary key SubCategory (id, title)//id is Primary key Here, I want to join these table as in simple query like Select * From Category cat, Section se, SubCategory subCat WHERE subCat.id=23456 AND subCat.category=cat.id AND subCat.section = se.id How can I achieve the above quer
更新问题 我有3个表 Section (id, title, url)//id is Primary key Category (id, title)//id is Primary key SubCategory (id, title)//id is Primary key 在这里，我想加入这些表格，就像在简单的查询中一样 Select * From Category cat, Section se, SubCategory subCat WHERE subCat.id=23456 AND subCat.category=cat.id AND subCat.section = se.id 我如何使用Hibernate中的Criteria实现上述查询？ 谁可以帮我
I'd like to use Hibernate's criteria api to formulate a particular query that joins two entities. Let's say I have two entities, Pet and Owner with a owner having many pets, but crucially that association is not mapped in the Java annotations or xml. With hql, I could select owners that have a pet called 'fido' by specifying the join in the query (rather than adding a set o
我想使用Hibernate的标准api来制定一个连接两个实体的特定查询。 假设我有两个实体，Pet和Owner拥有拥有许多宠物的所有者，但关键的是该关联未映射到Java注释或xml中。 通过hql，我可以通过在查询中指定连接（而不是将一组宠物添加到所有者类）来选择拥有称为'fido'的宠物的所有者。 同样可以使用休眠条件来完成吗？ 如果是这样如何？ 谢谢，J 我的理解是，如果您使用HQL执行此操作，则您将使用过滤器创建笛卡
I have a parent table ie audit_log(parent) which contains a single column id. For a given id in audit_log, I have a list of vendor ID's. I am storing them in separate table audit_log_vendorid(child table). I want the child table to get the id from the parent table as one of the columns(parent_id). Here's the table schema. audit_log +-------+------------+------+-----+---------+-----
我有一个父表，即包含一个列ID的audit_log（父）。 对于audit_log中的给定ID，我有一个供应商ID列表。 我将它们存储在单独的表audit_log_vendorid（子表）中。 我希望子表作为其中一列（parent_id）从父表中获取id。 这是表格模式。 AUDIT_LOG +-------+------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+------------+------+-----+---------+-------+ | id
Lets say that class 'X' is mapped to table 'X' class 'A' is mapped to Table 'A' and Class 'B is mapped to table 'B'. Table X Structure:(X_ID, some other columns Table A Structure:(A_Id,X_Id, some other columns) Table B Structure:(A_Id, some other columns)...Table B also has A_Id Class 'B' extends class 'A'. We have the mapping files
可以说类'X'被映射到表'X'类'A'被映射到表'A'并且类'B'被映射到表'B'。 表X结构:( X_ID，其他一些列表结构：（A_Id，X_Id，其他一些列）表B结构：（A_Id，其他一些列）...表B还有A_Id 'B'类扩展了'A'类。 我们有这两个映射文件为： 类'A'父映射文件： @Entity @Table(name = 'A') @Inheritance(stratergy=InheritanceType.Joined) public abstr
I have a table with 3 columns as primary key. Code and mapping is as follows: class for the composite key public class CIDResultCurrentState implements Serializable { private static final long serialVersionUID = -4346801004559840730L; private String mID = ""; private String sNo = ""; private String date = ""; // getters, setters, equals(), hashCode() omitted for brevity
我有一个3列作为主键的表。 代码和映射如下： 组合键的类 public class CIDResultCurrentState implements Serializable { private static final long serialVersionUID = -4346801004559840730L; private String mID = ""; private String sNo = ""; private String date = ""; // getters, setters, equals(), hashCode() omitted for brevity } 班级 public class ResultCurrentState implements
I tried to implement simple one-to-many association. after inspecting the item object with debugging mode, I found that List<Bid> bids already loaded. But List<Bid> bids property is annotated with FetchType.LAZY. some books and web pages claim that FetchType.LAZY is a hint JPA providers accept or reject. But I wonder on what condition JPA providers ignore FetchType.LAZY. Thank yo
我试图实现简单的一对多关联。 在用调试模式检查项目对象之后，我发现List <Bid>出价已经加载。 但List <Bid> bids属性由FetchType.LAZY注解。 一些书籍和网页声称FetchType.LAZY是JPA提供商接受或拒绝的提示。 但是我想知道JPA提供者忽略FetchType.LAZY的条件。 先谢谢你。 @Entity @Table(name = "ITEM") public class Item implements Serializable { @Id private Long id = null; private S
I have two tables with OneToMany relation class ServiceProvider { ... @OneToMany(fetch=FetchType.EAGER,mappedBy="serviceProvider", cascade={CascadeType.ALL,CascadeType.REMOVE},orphanRemoval = true) @OnDelete(action=OnDeleteAction.CASCADE) private List serviceCenters; ... } class ServiceCenterDetails { ... //bi-directional many-to-one association to ServiceProviderDomainMap
我有两个OneToMany关系表 class ServiceProvider { ... @OneToMany（fetch = FetchType.EAGER，mappedBy =“serviceProvider”，cascade = {CascadeType.ALL，CascadeType.REMOVE}，orphanRemoval = true）@OnDelete（action = OnDeleteAction.CASCADE）private List serviceCenters; ... } class ServiceCenterDetails { ... //双向多对一关联到ServiceProviderDomainMap @ManyToOne @JoinColumn（name =“SERVICE_PR
I am trying to figure out how to use hibernate criterion to get a specific set of child elements when I retrieve the parent. I have created the following example entities: Parent Class @Entity public class Parent { @Id @Column(name="PARENT_ID") private long parentId; @Column(name="NAME") private String name; @OneToMany(mappedBy="parent") private Set<Child>
我想弄清楚如何使用hibernate标准来获取一组特定的子元素时，我检索父。 我创建了以下示例实体： 父类 @Entity public class Parent { @Id @Column(name="PARENT_ID") private long parentId; @Column(name="NAME") private String name; @OneToMany(mappedBy="parent") private Set<Child> children } 儿童班 @Entity public class Child { @Id @Column(name="CHILD_ID")
Table SUBCOURSE references COURSE COURSE(id, name) SUBCOURSE(id, course_id, name) So, 1:M. Hibernate generates for Course: @OneToMany(fetch = FetchType.LAZY, mappedBy = "course", cascade = CascadeType.ALL) public Set getSubCourses() { return this.subCourses; } for Subcourse it generates @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "course_id", nullabl
表SUBCOURSE引用课程课程（id，name）SUBCOURSE（id，course_id，name） 所以，1：M。 Hibernate为课程生成： @OneToMany(fetch = FetchType.LAZY, mappedBy = "course", cascade = CascadeType.ALL) public Set getSubCourses() { return this.subCourses; } 为它生成的子课程 @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "course_id", nullable = false) public Course g