This is my code for my Server class. void run() try{ //1. creating a server socket providerSocket = new ServerSocket(2004, 10); //2. Wait for connection System.out.println("Waiting for connection"); connection = providerSocket.accept(); //connections++; System.out.println("Connection received from " + connection.getInetAddress().getHo
这是我的服务器类的代码。 void run（） try{ //1. creating a server socket providerSocket = new ServerSocket(2004, 10); //2. Wait for connection System.out.println("Waiting for connection"); connection = providerSocket.accept(); //connections++; System.out.println("Connection received from " + connection.getInetAddress().getHostName());
Is the memory space consumed by one object with 100 attributes the same as that of 100 objects, with one attribute each? How much memory is allocated for an object? How much additional space is used when adding an attribute? Mindprod points out that this is not a straightforward question to answer: A JVM is free to store data any way it pleases internally, big or little endian, with any a
100个属性与100个对象相同的一个对象是否消耗了内存空间，每个属性都有一个属性？ 多少内存分配给一个对象？ 添加属性时需要多少额外空间？ Mindprod指出，这不是一个直截了当的回答问题： JVM可以自由地以任何方式存储数据，这些数据可以是内部的，大的或小的endian，任何数量的填充或开销，尽管基元必须表现得好像他们有官方的大小。 例如，JVM或本机编译器可能决定将一个boolean[]存储为像BitSet这样的64位长块。
I made a Java application with Eclipse (exported in *.jar ), and I want to export it for Windows ( .exe ), Linux ( .? ) and MAC ( .? ). I don't own any Linux or MAC machine, so I don't know what extension file is required for each one. So I have several questions : For Windows, I used Launch4j to create my *.exe file, but is there any equivalent for MAC and Linux ? My application sa
我用Eclipse制作了一个Java应用程序（导出为* .jar ），我想将它导出为Windows（ .exe ），Linux（ 。？ ）和MAC（ 。？ ）。 我没有任何Linux或MAC机器，所以我不知道每个机器需要什么扩展名文件。 所以我有几个问题： 对于Windows，我使用Launch4j来创建我的* .exe文件，但是对于MAC和Linux是否有任何等价物？ 我的应用程序将选项保存到Windows注册表中（我使用了“JavaRegisrtyWrapper”库）。 是否有与MAC和Linux相同的
I have a scrollpane where load an image. I wont this image with her natural size, and if this image is too big, I wont activated the scrollbar, but this instruction g.drawImage(immagine, 0, 0, getWidth(), getHeight(), this); scaled image for placing in scrollpane. What can I do? Class Gui: import java.awt.*; import java.awt.event.*; import java.io.File; import javax.swi
我有一个滚动窗格加载图像。 我用她自然的大小来处理这个图像，如果这个图像太大，我不会激活滚动条，但是这个指令 g.drawImage(immagine, 0, 0, getWidth(), getHeight(), this); 缩放图像放置在滚动窗格中。 我能做什么？ 桂贵班： import java.awt.*; import java.awt.event.*; import java.io.File; import javax.swing.*; public class Gui implements ActionListener { private J
I created a simple class to create an XML document. However, if I call the method more than once while creating a document of the same name the file does not overwrite. How could I make the class automatically overwrite existing files of the same name? import java.io.File; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.Parse
我创建了一个简单的类来创建一个XML文档。 但是，如果在创建具有相同名称的文档时多次调用该方法，则文件不会被覆盖。 我怎样才能让课程自动覆盖现有的同名文件？ import java.io.File; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.ParserConfigurationException; import javax.xml.transform.Transformer; import javax.xml.transform.Transform
I need some code sample which shows how I can validate a xml file against a schema. Below is my XML document: <birthdate> <month>January</month> <day>21</day> <year>1983</year> </birthdate> The schema against which I want to validate the above XML is: <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:import names
我需要一些代码示例，说明如何根据模式验证xml文件。 以下是我的XML文档： <birthdate> <month>January</month> <day>21</day> <year>1983</year> </birthdate> 我想验证上述XML的模式是： <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:import namespace="http://www.w3.org/XML/1998/namespace" schemaLocation="http://w
I am trying to understand what mistake I could have made but can't find the solution. public static Document getXMLFromString(String xml) { org.w3c.dom.Document doc = null; try { DocumentBuilderFactory factory = DocumentBuilderFactory .newInstance(); factory.setNamespaceAware(true); DocumentBuilder builder; b
我想了解我可以做出什么错误，但找不到解决方案。 public static Document getXMLFromString(String xml) { org.w3c.dom.Document doc = null; try { DocumentBuilderFactory factory = DocumentBuilderFactory .newInstance(); factory.setNamespaceAware(true); DocumentBuilder builder; builder = factory.newDocumentBuilder();
I'm modifying an app that loads data dynamically from an XML file that contains a quiz and displays questions and replies. The change consists in the fact that i want to load a single(hardcoded for now) file instead of using a JFileChooser. Here's the relevant code working before(undefined variables are class attributes but i won't post the whole class declaration): public ClassC
我正在修改一个应用程序，该应用程序从包含测验的XML文件动态加载数据并显示问题和答案。 这个改变在于我想加载一个（现在是硬编码的）文件，而不是使用JFileChooser。 这是以前工作的相关代码（未定义变量是类属性，但我不会发布整个类声明）： public ClassConstructor() { JMenuItem load = new JMenuItem("Load"); ... } load.addActionListener(new ActionListener() { public void actionPerform
I have a Java based web service client connected to Java web service (implemented on the Axis1 framework). I am getting following exception in my log file: Caused by: org.xml.sax.SAXParseException: Content is not allowed in prolog. at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source) at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Sourc
我有一个基于Java的Web服务客户端连接到Java Web服务（在Axis1框架中实现）。 我在我的日志文件中遇到以下异常： Caused by: org.xml.sax.SAXParseException: Content is not allowed in prolog. at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source) at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source) at org.apache.xerces.impl.XMLErrorReporter.
i work with jdom .this error was take place: org.jdom.input.JDOMParseException: Error on line 252 of document Articles.xml: Content is not allowed in trailing section. at org.jdom.input.SAXBuilder.build(SAXBuilder.java:530) at org.jdom.input.SAXBuilder.build(SAXBuilder.java:905) at org.jdom.input.SAXBuilder.build(SAXBuilder.java:884) how can solve this error ? thank yo
我和jdom一起工作，这个错误发生了： org.jdom.input.JDOMParseException: Error on line 252 of document Articles.xml: Content is not allowed in trailing section. at org.jdom.input.SAXBuilder.build(SAXBuilder.java:530) at org.jdom.input.SAXBuilder.build(SAXBuilder.java:905) at org.jdom.input.SAXBuilder.build(SAXBuilder.java:884) 如何解决这个错误？ 谢谢！ 检查您的XML是否有