How to pass Uri value to bundle value

This following code fetches multiple contacts and stores them in a bundle: Intent phonebookIntent = new Intent("intent.action.INTERACTION_TOPMENU"); phonebookIntent.putExtra("additional", "phone-multi"); phonebookIntent.putExtra("maxRecipientCount", MAX_PICK_CONTACT); phonebookIntent.putExtra("FromMMS", true); startActivityForResult(phonebookIntent, REQUEST_CODE_PICK_CONTACT);

如何通过Uri值来捆绑价值

以下代码提取多个联系人并将其存储在一个包中: Intent phonebookIntent = new Intent("intent.action.INTERACTION_TOPMENU"); phonebookIntent.putExtra("additional", "phone-multi"); phonebookIntent.putExtra("maxRecipientCount", MAX_PICK_CONTACT); phonebookIntent.putExtra("FromMMS", true); startActivityForResult(phonebookIntent, REQUEST_CODE_PICK_CONTACT); 下面的代码检索选定的数据:

get the source code from an APK file back

The notebook drive on my laptop just crashed and all the data are lost. Belive it or not: I have lost all the source-code for an app that I have been working on for several months. All I have is the APK file that i have mailed to a friend. In other words - i have stored the data in this apk - file. Well - it seems that i can start at the very beginning.Or is there any way to extract my sourc

从APK文件中获取源代码

我笔记本电脑上的笔记本硬盘崩溃,所有的数据都丢失了。 相信与否:我已经失去了我已经工作了几个月的应用程序的所有源代码。 我所拥有的是我邮寄给朋友的APK文件。 换句话说 - 我已经在这个apk文件中存储了数据。 那么 - 我似乎可以从一开始就开始。或者有什么方法可以再次从这个APK文件中提取我的源代码。 换句话说 - 我可以找到一个工作的起点。 我可以使用哪些工具来收集我可能丢失的数据。 您可以尝试使用Classy

Saving the state of an activity before pressing the back button

I am currently building an android app which requires saving the state of my variables and views when the back button is pressed. I know the onSaveInstanceState() would work for scenarios which involve change in orientation but how do I get it to save when I use the back button. You may override finish() method and do saving there. This method is called when the activity is finished — that me

在按下后退按钮之前保存活动的状态

我目前正在构建一个android应用程序,它需要在按下后退按钮时保存我的变量和视图的状态。 我知道onSaveInstanceState()适用于涉及方向改变的场景,但如何在使用后退按钮时保存方向。 你可以重写finish()方法并在那里保存。 当活动结束时调用此方法 - 这意味着它从活动堆栈中移除。 默认情况下,这种情况发生在你按下后退按钮时 你可以覆盖, @Override public void onBackPressed() { super.onBackPressed(); } 并在

ThreadGroup in Java

I am currently learning basics of Threads in Java and I am trying to write a simple Thread Group program. I wrote it same as tutorial website though i'm getting different type of output. Below is my code for which i'm getting different output. public class ThreadGroupDemo implements Runnable { @Override public void run() { System.out.println(Thread.currentThread().getN

Java中的ThreadGroup

我目前正在学习Java中的线程基础知识,并且正在尝试编写一个简单的线程组程序。 虽然我得到了不同类型的输出,但我和教程网站一样写了它。 下面是我的代码,我得到不同的输出。 public class ThreadGroupDemo implements Runnable { @Override public void run() { System.out.println(Thread.currentThread().getName()); // get the name of the current thread. } public static void ma

Why can't we use pointers in Java?

This question already has an answer here: Does Java have pointers? 12 answers Why can't we use pointers in Java? Because the language designers chose not to include pointers in the language. Why we are not using the pointer here. Because the designers of Java thought it was a tricky-to-use and error prone construct. Which concept is used instead of pointer in Java? References (

为什么我们不能在Java中使用指针?

这个问题在这里已经有了答案: Java有指针吗? 12个答案 为什么我们不能在Java中使用指针? 因为语言设计者选择不包含语言中的指针。 为什么我们不在这里使用指针。 因为Java的设计者认为这是一个棘手的,容易出错的构造。 在Java中使用哪个概念而不是指针? 引用(如果您不考虑指针算术,这些引用非常类似于指针)。 请记住,您创建的所有对象都是在堆上创建的(使用new关键字)。 这个事实以及没有“解除引用

Does java really have pointers or not?

I have looked on google for answers but I am not satisfied. My Logic: Java uses memory locations, it's just behind the scenes where you can't see or access it (to my knowledge, probably there are ways of accessing them that I don't know). My Confusion / Question : What is the purpose of not having pointers in a programming language like Java, designed specifically for the inte

java真的有指针吗?

我已经看过谷歌的答案,但我不满意。 我的逻辑: Java使用内存位置,它只是在幕后,你无法看到或访问它(据我所知,可能有访问它们的方式,我不知道)。 我的困惑/问题: 在像Java这样的编程语言中没有指针的目的是什么?专门为在任何系统上使用互联网而设计,而不是像c ++这样的使用指针的编程语言? 编辑 你们中许多人都在说“保持简单”。 如果是这种情况,那么为什么像c++这样的流行编程语言仍然使用指针? 简

SonarLint is super slow

I'm using the new eclipse plugin SonarLint in a large Eclipse RCP project. It is extremely slow. Analyzing all plugin projects (over 310) lasts several hours. SonarLint creates a log for every project build, that looks like this: Starting SonarLint ... Load global repositories (done from cache) | time=98ms ... Load plugins index (done from cache) | time=3ms ... Load project repositories

SonarLint超级慢

我在一个大的Eclipse RCP项目中使用了新的eclipse插件SonarLint。 这是非常缓慢的。 分析所有插件项目(超过310)持续几个小时。 SonarLint为每个项目构建创建一个日志,如下所示: Starting SonarLint ... Load global repositories (done from cache) | time=98ms ... Load plugins index (done from cache) | time=3ms ... Load project repositories (done) | time=3ms ... Load quality profiles (done from cache) | t

QuickSort vs MergeSort on arrays of primitives in Java

I know that Java's Arrays.sort method uses MergeSort for sorting arrays of objects (or collections of objects) since it is stable, and Java uses QuickSort for arrays of primitives because we don't need stability since two equal ints are indistinguishable, ie their identity doesn't matter. My question is, in the case of primitives, why doesn't Java use MergeSort's guaranteed

Java中基元数组的QuickSort vs MergeSort

我知道Java的Arrays.sort方法使用MergeSort对对象数组(或对象集合)进行排序,因为它是稳定的,而且Java使用QuickSort用于基元数组,因为我们不需要稳定性,因为两个相等的整数是不可区分的,即它们的身份无关紧要。 我的问题是,在基元的情况下,为什么Java不使用MergeSort保证的O(n log n)时间,而是使用QuickSort的平均O(n log n)时间? 在这里相关答案的最后一段中,解释说: 对于引用类型,通常引用的对象比引用

Why is my mergesort slower than my quicksort?

They're both the same time complexity but when I run my merge sort on a randomly generated linked list with 100,000 entries: public LinkedList<Integer> linkedListSort(LinkedList<Integer> list) { if (list.size() <= 1) return list; LinkedList<Integer> left = new LinkedList<Integer>(); LinkedList<Integer> right = new LinkedList<Integer>();

为什么我的mergesort比我的quicksort慢?

他们都是同样的时间复杂性,但是当我在具有100,000个条目的随机生成链表上运行合并排序时: public LinkedList<Integer> linkedListSort(LinkedList<Integer> list) { if (list.size() <= 1) return list; LinkedList<Integer> left = new LinkedList<Integer>(); LinkedList<Integer> right = new LinkedList<Integer>(); int middle = list.size()/2; for (int i

Multithreaded quicksort or mergesort

How can I implement a concurrent quicksort or mergesort algorithm for Java? We've had issues on a 16-(virtual)-cores Mac where only one core (!) was working using the default Java sorting algo and it was, well, not good to see that very fine machine be completely underused. So we wrote our own (I wrote it) and we did indeed gain good speedups (I wrote a multithreaded quicksort and due to i

多线程快速排序或合并排序

我怎样才能为Java实现一个并发的quicksort或mergesort算法? 我们在16位(虚拟)核心Mac上出现了问题,其中只有一个核心(!)正在使用默认的Java排序算法,而且很不好看到这台非常精细的机器被完全滥用。 所以我们写了自己的(我写了它),并且确实获得了很好的加速(我写了一个多线程的快速排序,并且由于它的分区性质,它很好地并行化,但我也可以写一个mergesort)但是我的实现只是扩展多达4个线程,它是专有代码,我宁愿