I'm trying to implement file upload with Jersey so I followed this example : http://www.mkyong.com/webservices/jax-rs/file-upload-example-in-jersey/ which worked well with an HTML page. Now I adapted it to my application, here is code : public Response uploadFile( @FormDataParam("file") InputStream uploadedInputStream, @FormDataParam("file") FormDataContentDisposition fileDetail)
我试图用Jersey来实现文件上传，所以我按照这个例子：http：//www.mkyong.com/webservices/jax-rs/file-upload-example-in-jersey/，它可以很好地处理HTML页面。 现在我将它改编成我的应用程序，代码如下： public Response uploadFile( @FormDataParam("file") InputStream uploadedInputStream, @FormDataParam("file") FormDataContentDisposition fileDetail) throws IOException { Response.Status respSta
I have an application based on ExtJS and I want to upload a file, an image, via Restful with Jersey, but I can't do it, is that possible?. This is part of my code: View: . . . items: [{ xtype: 'filefield', name: 'iconBmp', fieldLabel: this.i18nColIconBmp, enforceMaxLength : true, labelWidth: 100, msgTarget: 'side', anchor: '100%', buttonText: 'Exam' }], buttons: [{ text:
我有一个基于ExtJS的应用程序，我想通过Rest的Jersey来上传一个文件，一张图片，但是我不能这么做，这有可能吗？ 这是我的代码的一部分： 视图： . . . items: [{ xtype: 'filefield', name: 'iconBmp', fieldLabel: this.i18nColIconBmp, enforceMaxLength : true, labelWidth: 100, msgTarget: 'side', anchor: '100%', buttonText: 'Exam' }], buttons: [{ text: 'Upload', handler: function() {
I have a HTML form that will upload a file (among other form fields) to my server. There, I am using Java and Jersey, and have created a filter which will throw an Exception if the file is to large (>10MB). But I can't seem to get the browser to stop the file upload as soon as I throw the exception. I can see that the reading from the InputStream stops after 10MB at the server side, but
我有一个HTML表单，它会将文件（包括其他表单域）上传到我的服务器。 在那里，我使用Java和Jersey，并创建了一个过滤器，如果文件大（> 10MB），将会抛出异常。 但我似乎无法让浏览器在我抛出异常时立即停止文件上传。 我可以看到，从服务器端读取InputStream后停止10MB，但浏览器仍然会继续上传文件直到完成。 只有这样才会显示错误。 HTTP和浏览器的工作方式有什么妨碍它的工作吗？ 如果用户在得到错误之前必须等待
I'm currently implementing functionality for uploading files using jersey rest. I would like to set a maximum allowed file size which to me seems like a pretty common requirement. My first approach was to use Jerseys FormDataContentDisposition which should hold all the information I could possibly need about the file. But all information except the file name seems to be missing, including
我目前正在实现使用球衣休息上传文件的功能。 我想设置一个最大允许的文件大小对我来说似乎是一个相当普遍的要求。 我的第一个方法是使用Jerseys FormDataContentDisposition，它应该包含我可能需要的关于该文件的所有信息。 但除文件名外的所有信息似乎都丢失了，包括文件大小。 这是我的休息方法： @POST @Path("uploadFile/") @Consumes("multipart/form-data") @Produces("text/html") public String handleDocumentUp
I'm new to AST (my first time writing a plugin). Expressions can be quite complex in real life. I wanted to know how to resolve the left and right side of an asignment, for instance. class Visitor extends ASTVisitor { @Override public boolean visit(Assignment node) { //here, how do I get the final name to each each side of the assignment resolves? } } I have also a
我是AST新手（我第一次写插件）。 表达在现实生活中可能相当复杂。 例如，我想知道如何解决排序的左侧和右侧。 class Visitor extends ASTVisitor { @Override public boolean visit(Assignment node) { //here, how do I get the final name to each each side of the assignment resolves? } } 我还有另一个疑问，我如何获得用于调用方法的实例？ public boolean visit(MethodInvocation node) {
I was under the impression that the UUID spec required a guaranteed, true, globally unique result, not unique 99.99999999999% of the time, but truly 100% of the time. From the spec: A UUID is 128 bits long, and can guarantee uniqueness across space and time. It looks like java only support V3 and V4 of the UUID spec. V4 isn't truly unique. With the V3 implementation using nameUUIDFromB
我的印象是，UUID规范要求保证的，真实的，全球唯一的结果，不是唯一的99.99999999999％的时间，而是100％的时间。 从规格： UUID的长度为128位，可以保证空间和时间的唯一性。 它看起来像Java只支持UUID规范的V3和V4。 V4并不是真正独特的。 使用nameUUIDFromBytes进行V3实现时，由于计算机速度太快（编辑：循环到10并调用new Date().getTime()会产生重复项，因为计算机循环比new Date().getTime()快new Date().getTime(
I've been wondering what's the correct practice for generating unique ids? The thing is in my web app I'll have a plugin system, when a user registers a plugin I want to generate a unique serial ID for it. I've been thinking about storing all numbers in a DB or a file on the server, generating a random number and checking whether it already exists in the DB/file, but that doesn&
我一直在想什么是生成唯一ID的正确做法？ 事情是在我的网络应用程序，我会有一个插件系统，当用户注册一个插件，我想为它生成一个唯一的序列号。 我一直在考虑将所有数字存储在服务器上的数据库或文件中，生成一个随机数并检查它是否已存在于数据库/文件中，但这看起来不太好。 还有其他方法可以做到吗？ 将使用UUID是首选的方式吗？ 如果这些ID是面向用户的，看起来它们是，那么你希望它们难以猜测。 使用内置的UUID类
Summary: I'm developing a persistent Java web application, and I need to make sure that all resources I persist have globally unique identifiers to prevent duplicates. The Fine Print: I'm not using an RDBMS, so I don't have any fancy sequence generators (such as the one provided by Oracle) I'd like it to be fast, preferably all in memory - I'd rather not have to open up
简介：我正在开发一个持久的Java Web应用程序，并且我需要确保所有我坚持的资源都具有全局唯一标识符以防止重复。 精美图片： 我没有使用RDBMS，所以我没有任何花哨的序列生成器（例如Oracle提供的序列生成器） 我希望它快速，最好是所有内存 - 我宁愿不必打开一个文件并增加一些价值 它需要是线程安全的（我预计一次只有一个JVM需要生成ID） 需要在JVM的实例化之间保持一致。 如果服务器关闭并启动，那么ID生成器不
How can I generate a Guid in Netbeans. I have used Visual Studio in the past, and used the Guid.CreateGuid(). Is there a Guid class in NetBeans?? Assuming that in NetBeans you are using java, you could use the randomUUID() method of the class java.util.UUID class as shown below import java.util.UUID; public class UUIDDemo { public static void main(String[] args) { System.out.pri
我如何在Netbeans中生成Guid。 我过去曾使用Visual Studio，并使用Guid.CreateGuid（）。 NetBeans中是否有Guid类？ 假设在NetBeans中使用的是Java，可以使用类java.util.UUID类的randomUUID（）方法，如下所示 import java.util.UUID; public class UUIDDemo { public static void main(String[] args) { System.out.println(UUID.randomUUID()); } } 有关更多详细信息，请访问：http://docs.oracle.com
I have an application I would like to run on both PostgreSQL and SQL Server. I would like to use java.util.UUID as the IDs. I have defined my columns in SQL Server as id UNIQUEIDENTIFIER ROWGUIDCOL NOT NULL UNIQUE I have defined my columns in PostgreSQL as id UUID NOT NULL The columns are defined in my JPA Entities as @Id @Column(name = "id") public UUID getId() { return id; } This
我有一个我想在PostgreSQL和SQL Server上运行的应用程序。 我想使用java.util.UUID作为ID。 我已经在SQL Server中将我的列定义为 id UNIQUEIDENTIFIER ROWGUIDCOL NOT NULL UNIQUE 我已经在PostgreSQL中定义了我的列 id UUID NOT NULL 这些列在我的JPA实体中定义为 @Id @Column(name = "id") public UUID getId() { return id; } 这适用于PostgreSQL，因为它将UUID传递给PostgreSQL JDBC驱动程序。 这种工作适用