Should I use static initializer or super class

I have a interface named Parser . Two classes ParserA, ParserB implements Parser . public interface Parser{ public void initialize(); public int Parse(byte[] data); } I have confusion with initialization. ParserA initializes two Maps . ParserB initializes two Maps . But differentData. Maps are initialized with constant data. Means not from runtime. So Should I use approach1 or

我应该使用静态初始化程序还是超类

我有一个名为Parser的接口。 两个类ParserA, ParserB实现Parser 。 public interface Parser{ public void initialize(); public int Parse(byte[] data); } 我对初始化有困惑。 ParserA初始化两个Maps 。 ParserB初始化两个Maps 。 但不同的数据。 Maps使用常量数据进行初始化。 意味着不从运行时。 那么我应该使用approach1还是2? Approach1: class Initializer{ //have two maps as member } Clas

What is the best way to approximate class.getSimpleName() without loading class?

Given a fully qualified class name that can be loaded with Class.forName(), is there a way to transform the name into what would be the result of loading the class and invoking getSimpleName() without actually attempting to load the class? I need this capability for reflection purposes. I'm going to say that you can't do it simply based on the name. You can try to split on . and $ ,

在不加载类的情况下近似class.getSimpleName()的最佳方式是什么?

给定一个可以用Class.forName()加载的完全限定的类名,是否有一种方法可以将名称转换为加载类并调用getSimpleName()而不实际尝试加载类的结果? 我需要这个功能来进行反射。 我要说的是,你不能仅仅根据名字来做它。 你可以尝试拆分. 和$ ,但这个示例代码表明,在简单名称开始的地方并不总是显而易见的: class Ideone { private static class Bar {}; public static void main (String[] args) throws java

What exactly is a Context in Java?

This question already has an answer here: What is 'Context' on Android? 29 answers In programming terms, it's the larger surrounding part which can have any influence on the behaviour of the current unit of work. Eg the running environment used, the environment variables, instance variables, local variables, state of other classes, state of the current environment, etcetera. I

Java中的上下文究竟是什么?

这个问题在这里已经有了答案: Android上的“上下文”是什么? 29个答案 在编程方面,它是较大的周边部分,可以对当前工作单元的行为产生任何影响。 例如使用的运行环境,环境变量,实例变量,局部变量,其他类的状态,当前环境的状态等等。 在某些API中,你可以在界面/类中看到该名称,例如Servlet的ServletContext ,JSF的FacesContext ,Spring的ApplicationContext ,Android的Context ,JNDI的InitialContext等。它们

How to find ~/.android/debug.keystore in Mac OS X for Android?

I am very new to Android development. Now am facing this problem in Java Eclipse, Error generating final archive: Debug Certificate expired on 1/11/12 12:52 PM Unknown Android Packaging Problem I searched in google and found the answer for my problem from this link "Debug certificate expired" error in Eclipse Android plugins. They gave the answer for my question. I am using E

如何在Mac OS X for Android中查找〜/ .android / debug.keystore?

我对Android开发非常陌生。 现在我在Java Eclipse中面临这个问题, Error generating final archive: Debug Certificate expired on 1/11/12 12:52 PM Unknown Android Packaging Problem 我在谷歌搜索,并找到了我的问题的答案从这个链接“调试证书过期”错误在Eclipse Android插件。 他们给我的问题提供了答案。 我在Mac OS X使用Eclipse。 他们给出的解决方案是从Preferences - Android - Build - Default debug ke

bad version in class file

When I use certain jars in one of the connector projects i write for lombardi in TeamWorks eclipse i get a bad class version exception... any ideas how this might be resolved.. Regards, Adhir You will get this error if you are using (say) Java 1.5 and you are using a JAR compiled with Java 1.6. The easiest way to resolve is to upgrade your version of Java to the one used by the JAR. Try

类文件中的错误版本

当我在TeamWorks eclipse中为lombardi编写的某个连接器项目中使用某些JAR时,我得到一个错误的类版本异常... 任何想法如何解决.. 问候,Adhir 如果您使用(比如说)Java 1.5并且您正在使用与Java 1.6一起编译的JAR,则会出现此错误。 最简单的解决方法是将您的Java版本升级到JAR使用的版本。 尝试使用相同的编译器编译/重新编译所有东西。 通常情况下,这发生在你编译一个更高版本的东西时,并且你试图用一个较旧的版

Android Google Maps Failed to find style 'mapViewStyle' in current theme

When adding a google map view (I extended a MapView, used the xml editor to add it to the Activity, and added my google maps api key to the layout xml file manually) My permissions allow Internet in the manifest file What i'm wondering, is in the xml editor i get the error "Failed to find style 'mapViewStyle' in current theme" but i seem to have everything set up correct

Android Google Maps无法在当前主题中查找样式“mapViewStyle”

当添加谷歌地图视图(我扩展了MapView,使用XML编辑器将其添加到活动,并手动添加我的谷歌地图api键到布局xml文件) 我的权限允许清单文件中的Internet 我想知道的是,在xml编辑器中,我得到错误“无法在当前主题中找到样式'mapViewStyle'”,但我似乎已经正确设置了一切。 当我尝试按照Android MapView教程构建一个简单的应用程序时,我遇到了同样的问题。 该应用程序在AVD中为文件文件main.xml显示了此异常:

Default keystore file does not exist?

I'm getting this error. C:Program FilesJavajre7bin>keytool -list -v -keystore "C:UsersSuresh.androiddebug.keystore" -alias androiddebugkey -storepass android -keypass android keytool error: java.lang.Exception: Keystore file does not exist: C:UsersSuresh.androiddebug.keystore java.lang.Exception: Keystore file does not exist: C:UsersSuresh.androiddebug.keystore at sun.security.tools.Ke

默认密钥库文件不存在?

我收到这个错误。 C:Program FilesJavajre7bin>keytool -list -v -keystore "C:UsersSuresh.androiddebug.keystore" -alias androiddebugkey -storepass android -keypass android keytool error: java.lang.Exception: Keystore file does not exist: C:UsersSuresh.androiddebug.keystore java.lang.Exception: Keystore file does not exist: C:UsersSuresh.androiddebug.keystore at sun.security.tools.KeyTool.doCom

Error: Unable to open class file R.java

This question already has an answer here: Developing for Android in Eclipse: R.java not regenerating 63 answers I have had same issue, all what I needed to do, was create project and restart eclipse. //Edit: Complete collapsing of "Package" tree works as well. This is a mighty annoying error. It happens 100% of the time when I create a new android project. What seems to work

错误:无法打开类文件R.java

这个问题在这里已经有了答案: 在Eclipse中为Android开发:R.java不重新生成63个答案 我有同样的问题,所有我需要做的是创建项目并重新启动eclipse。 //编辑:完成“包”树的折叠工作。 这是一个强大的恼人的错误。 它发生在我创建一个新的android项目时的100%。 什么似乎对我来说就是删除文件(哪些文件存在并可供我的用户访问),然后点击构建,它会重新生成并停止呻吟。 这显然是一个错误,因为有太多的人通过填

RxJava Observable with last state

I'm starting with RxJava, and I would like to create an observable that can save the last state… In RxSwift, that would be Variable (https://github.com/ReactiveX/RxSwift/blob/master/Documentation/GettingStarted.md#variables), but I can't found an equivalente in RxJava… I found a work around but it's a lot of boiler plate code private boolean isGettingCompanies = false; public bo

RxJava可观察到最后一个状态

我从RxJava开始,并且我想创建一个可以保存最后状态的observable ... 在RxSwift中,这将是变量(https://github.com/ReactiveX/RxSwift/blob/master/Documentation/GettingStarted.md#variables),但我无法在RxJava中找到等值的... 我发现了一个工作,但它是很多的锅炉代码 private boolean isGettingCompanies = false; public boolean isGettingCompanies() { return isGettingCompanies; } private void setIsGett

RESTEasy Guice Provider

I'm having a small problem when trying to use Guice with ContainerRequestFilter, it throws a NullPointerException. I did a little digging into RESTEasy and it would appear that it can't find a constructor for MyFilter due to the @Context annotation not being present, the NullPointerException is thrown when trying to instantiate a null constructor. My filter: @Provider @PreMatching pub

RESTEasy Guice Provider

在试图将Guice和ContainerRequestFilter一起使用时,我遇到了一个小问题,它引发了一个NullPointerException异常。 我对RESTEasy进行了一些探索,由于@Context注释不存在,它似乎找不到MyFilter的构造函数,尝试实例化一个空构造函数时抛出NullPointerException。 我的过滤器: @Provider @PreMatching public class MyFilter implements ContainerRequestFilter { private Dependency d; @Inject public MyFilt