This question already has an answer here: SOAP vs REST (differences) 12 answers REST is almost always going to be faster. The main advantage of SOAP is that it provides a mechanism for services to describe themselves to clients, and to advertise their existence. REST is much more lightweight and can be implemented using almost any tool, leading to lower bandwidth and shorter learning curve
这个问题在这里已经有了答案： SOAP与REST（差异）12个答案 REST几乎总是会更快。 SOAP的主要优点是它提供了一种服务机制来向客户描述自己，并宣传他们的存在。 REST更轻巧，可以使用几乎所有工具实现，从而带来更低的带宽和更短的学习曲线。 但是，客户必须知道要发送什么以及期望什么。 一般而言，当您向外部世界发布复杂或可能发生变化的API时，SOAP将更加有用。 除此之外，REST通常是更好的选择。 REST vs SOAP
I am having a lot of trouble finding good information on how to call a standard SOAP/WSDL web service with Android. All I've been able to find are either very convoluted documents and references to "kSoap2" and then some bit about parsing it all manually with SAX. OK, that's fine, but it's 2008, so I figured there should be some good library for calling standard web servic
我很难找到有关如何使用Android调用标准SOAP / WSDL Web服务的良好信息。 我所能找到的都是非常复杂的文档和对“kSoap2”的引用，然后关于用SAX手动解析它的一些内容。 好吧，没关系，但是它是2008年的，所以我认为应该有一些用于调用标准Web服务的好库。 Web服务基本上是在NetBeans中创建的。 我希望IDE支持生成管道类。 我只需要用最简单/最优雅的方式联系基于Android手机的基于WSDL的Web服务。 Android不提供任何类型的
I've some problem with LibGDX and tiled maps. I come from Corona SDK (Lua) and I've used Lime (third party lib to handle tmx maps), now I switched to LibGDX and followed this really recent feature: GraphicsTileMaps I was able to load an isometric map from assets using IsometricTiledMapRenderer as renderer and an OrthographicCamera to display the map (all works as described in the wiki
我在LibGDX和平铺地图上遇到了一些问题。 我来自Corona SDK（Lua），我用Lime（第三方库来处理tmx地图），现在我切换到LibGDX并遵循这个最新功能： GraphicsTileMaps 我能够使用IsometricTiledMapRenderer作为渲染器和OrthographicCamera从资源中加载等轴测图，以显示地图（所有工作均按照wiki页面中的描述）。 我还能够在地图图层上以编程方式填充某个图块，但是当我尝试使用AnimatedTiledMapTile时，我的问题开始了：
Here is a piece of C++ code that seems very peculiar. For some strange reason, sorting the data miraculously makes the code almost six times faster. #include <algorithm> #include <ctime> #include <iostream> int main() { // Generate data const unsigned arraySize = 32768; int data[arraySize]; for (unsigned c = 0; c < arraySize; ++c) data[c] = std::ra
这是一段C ++代码，看起来很奇特。 出于某种奇怪的原因，对数据进行奇迹排序使得代码几乎快了六倍。 #include <algorithm> #include <ctime> #include <iostream> int main() { // Generate data const unsigned arraySize = 32768; int data[arraySize]; for (unsigned c = 0; c < arraySize; ++c) data[c] = std::rand() % 256; // !!! With this, the next loop runs f
I have to make a Java program which finds all repeating sub-strings of length n in a given String. The input is string is extremely long and a brute-force approach takes too much time. I alread tried: Presently I am finding each sub-string separately and checking for repetitions of that sub-string using the KMP alogrithm. This too is taking too much time. What is a more efficient approach
我必须制作一个Java程序，它可以查找给定字符串中所有重复的长度为n的子字符串。 输入的字符串非常长，而暴力方法需要太多时间。 我试过了： 目前，我正在分别查找每个子字符串，并使用KMP算法检查该子字符串的重复。 这也需要太多时间。 什么是更有效的方法来解决这个问题？ 1）你应该看看使用后缀树数据结构。 后缀树 这个数据结构可以在O（N * log N）时间内建立 （即使在使用Ukkonen算法的O（N）时间，我也
I'm facing an issue, that i could not resolve for a long period of time. The simple problem is that, Internet Explorer 7-8-9 is not supporting placeholders. Although i have found many scripts that should resolve this issue, i could not just make it work. This kind of problem just differs from the others. Here's why: I'm using a script which simulates placeholders like this: This
我面临一个问题，我无法解决很长一段时间。 简单的问题是，Internet Explorer 7-8-9不支持占位符。 虽然我发现了许多脚本可以解决这个问题，但我不能仅仅使它工作。 这类问题与其他问题不同。 原因如下： 我正在使用一个模拟这样的占位符的脚本：这是正确的 然后，我在其中写入内容，删除文本并单击其他位置，如下所示：错误 如果我写了一些东西，删除并点击一个空的文本框，它再次运行良好... 如果我使用退格键并逐
Does someone have pretty_print function for print SQL query in java? given string like: SELECT person_table.name FROM person_table JOIN person_person ON person_table.name=person_person WHERE person_table.name=dan The function will print: SELECT person_table.name FROM person_table JOIN person_person ON person_table.name=person_person WHERE person_table.name=dan or better? Thank
有人在Java中有打印SQL查询的pretty_print函数吗？ 给定的字符串如： SELECT person_table.name FROM person_table JOIN person_person ON person_table.name = person_person WHERE person_table.name = dan 该功能将打印： SELECT person_table.name FROM person_table 加入person_person ON person_table.name = person_person 在哪里person_table.name =丹 或更好？ 提前致谢！ 你可以看看org.apache.op
I'm looking at a piece of Java code right now, and it takes a path as a String and gets its URL using URL resource = ClassLoader.getSystemClassLoader().getResource(pathAsString); , then calls String path = resource.getPath() and finally executes new File(path); . Oh, and there are also calls to URL url = resource.toURI(); and String file = resource.getFile() . I'm totally confused
我现在正在查看一段Java代码，它将一个路径作为String并使用URL resource = ClassLoader.getSystemClassLoader().getResource(pathAsString);获取其URL URL resource = ClassLoader.getSystemClassLoader().getResource(pathAsString); ，然后调用String path = resource.getPath()并最终执行new File(path); 。 哦，还有一些URL url = resource.toURI(); 和String file = resource.getFile() 。 我现在完全困惑 - 主要是
I noticed the following exception is thrown in my Play! application running on Tomcat: javax.servlet.ServletException: java.net.URISyntaxException: Illegal character in path at index 35: /K-NAAN/lyrics/Is-Anybody-Out-There[]-lyrics/3807088 play.server.ServletWrapper.service(ServletWrapper.java:157) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) root cause java.net.URISynt
我注意到我的Play中引发了以下异常！ 在Tomcat上运行的应用程序： javax.servlet.ServletException: java.net.URISyntaxException: Illegal character in path at index 35: /K-NAAN/lyrics/Is-Anybody-Out-There[]-lyrics/3807088 play.server.ServletWrapper.service(ServletWrapper.java:157) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) root cause java.net.URISyntaxException: Illegal char
I'm trying to make two side by side ListViews act like a GridView to an extent. The reason I'm not using GridView is because there's no support for a Staggered Look. Anyways, I have the following code so far: <- Old,now irrelevant code -> EDIT: I did as @Sam suggested and used the following code: lv1.setOnTouchListener(new OnTouchListener() { @Override
我试图让两个并排的ListView在一定程度上像GridView一样行事。 我没有使用GridView的原因是因为没有支持Staggered Look。 无论如何，我到目前为止有以下代码： < - 旧的，现在不相关的代码 - > 编辑： 我做了@Sam建议并使用以下代码： lv1.setOnTouchListener(new OnTouchListener() { @Override public boolean onTouch(View v, MotionEvent event) { if (touchSource =