I'm currently trying to write a Java assignment that is supposed to, in order; Read each line of a prewritten text file Turn each line into a string Turn each part of each line into its own individual string/int/double Assign those variables in an object (Which is part of an array of objects) of a class which I have also created as part of this assignment Print each variable of the
我目前正在尝试编写一个应该按顺序排列的Java任务; 阅读预先编写的文本文件的每一行 将每一行变成一个字符串 将每一行的每个部分转换为它自己的字符串/ int / double 将这些变量分配给作为此作业的一部分而创建的类的对象（它是对象数组的一部分） 使用其中一个类的方法打印对象的每个变量 但是，我反复遇到一个运行时问题，我收到此错误消息; 在Lab2.main上的线程“main”java.util.NoSuchElementException在java.u
I'm doing some homework where we have to use the Scanner class. I was able to use it to read in a String, an int, and a float. When I moved to the next phase (the class below) I suddenly am not able to use scanner the way I had before. I did indeed close any other scanner object I created and opened. Thank you for any help. Why does this code: (nextLine() also does not work) import jav
我正在做一些家庭作业，我们必须使用Scanner类。 我能够使用它来读取一个字符串，一个int和一个浮点数。 当我进入下一阶段（下面的课程）时，我突然无法像以前那样使用扫描仪。 我确实关闭了我创建和打开的任何其他扫描仪对象。 感谢您的任何帮助。 为什么这个代码：（nextLine（）也不起作用） import java.io.*; import java.util.Scanner; public class Grades { private int len; private String [] gradeNames; priv
In class java.util.Scanner ,method public String next() finds and returns the next complete token from this Scanner ,I am confused,if I write a program like this: public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.println(in.next()); in.close(); } and run this program,then input a word and the word will be printed,it seems that method next() ret
在类java.util.Scanner ，方法public String next()发现并返回来自此Scanner的下一个完整标记，我很困惑，如果我编写如下程序： public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.println(in.next()); in.close(); } 并运行该程序，然后输入一个单词并打印该单词，似乎next()方法返回当前令牌，为什么API会说next()返回下一个完整的令牌？ 这是因为您将Scanner分配给
This seems be a common question (asked multiple times) yet I'm not able to find an explanation for this behaviour. Following code works in one compiler but throws Exception in thread "main" java.util.NoSuchElementException in another compiler Scanner s = new Scanner(System.in); System.out.println("Enter name: "); String name = s.next(); System.out.println("Name is " + name
这似乎是一个常见问题（问多次），但我无法找到这种行为的解释。 以下代码在一个编译器中工作，但在另一个编译器Exception in thread "main" java.util.NoSuchElementException中抛出Exception in thread "main" java.util.NoSuchElementException Scanner s = new Scanner(System.in); System.out.println("Enter name: "); String name = s.next(); System.out.println("Name is " + name); 测
Can you tell me what's the problem? I'm trying to read integers from the file named "tablica.txt" and it looks like that in a file: 8 3 2 1 4 3 2 package Operacje_na_plikach; import jdk.nashorn.internal.ir.WhileNode; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.util.Arrays; import java.util.Scanner; public class Za
你能告诉我有什么问题吗？ 我试图从名为“tablica.txt”的文件中读取整数，它看起来像在一个文件中：8 3 2 1 4 3 2 package Operacje_na_plikach; import jdk.nashorn.internal.ir.WhileNode; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.util.Arrays; import java.util.Scanner; public class Zad1 { /* Plik tekstowy ‘tablica.txt’ ma postać: 8 3
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */ package filesort; import java.io.File; import java.util.Scanner;`enter code here` import java.io.IOException; import java.util.Comparator; import java.util.Collections; import java.util.ArrayList; import java.io.Pri
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */ package filesort; import java.io.File; import java.util.Scanner;`enter code here` import java.io.IOException; import java.util.Comparator; import java.util.Collections; import java.util.ArrayList; import java.io.Pri
I run into an error when I'm running this function. It finds a word in a certain file using Scanner. Here it is: public static boolean VerifyExistWord(File FileToSearch, String WordToFind) { boolean result = false; try (Scanner ind = new Scanner(FileToSearch)) { while (ind.hasNextLine()) { String word = ind.next(); if (word.equalsIgnoreCase(WordToF
当我运行此功能时遇到错误。 它使用扫描仪在某个文件中找到一个字。 这里是： public static boolean VerifyExistWord(File FileToSearch, String WordToFind) { boolean result = false; try (Scanner ind = new Scanner(FileToSearch)) { while (ind.hasNextLine()) { String word = ind.next(); if (word.equalsIgnoreCase(WordToFind)) { result = true;
I followed a tutorial on how to read from a text file to a JTextField. It has been a few hours that I keep getting the same error when I run the program: ** Exception in thread "main" java.util.NoSuchElementException at java.util.Scanner.throwFor(Scanner.java:907) at java.util.Scanner.next(Scanner.java:1416) at demo.Demo.Read(Demo.java:26) at demo.DemoSwing.main(DemoSwing.java:42)
我遵循了关于如何从文本文件读取到JTextField的教程。 我在运行程序时经历了几个小时的错误：** 在线程中出现异常“main”java.util.NoSuchElementException在java.util.Scanner.throwFor（Scanner.java:907）at java.util.Scanner.next（Scanner.java:1416）at demo.Demo.Read（Demo。 java：26）在demo.DemoSwing.main（DemoSwing.java:42） ** 这是我目前使用的代码： package demo; import java.io.*; import java.ut
Okay so I've encountered an error and I'm not so sure why, any help would be appreciated. When I try run it, I'm met with the following. Exception in thread "main" java.util.NoSuchElementException at java.util.Scanner.throwFor(Scanner.java:907) at java.util.Scanner.next(Scanner.java:1530) at java.util.Scanner.nextInt(Scanner.java:2160) at java.util.Scanner.nextInt(Scanner
好吧，我遇到了一个错误，我不太确定为什么，任何帮助，将不胜感激。 当我尝试运行它时，遇到以下情况。 java.util.Scanner.nextInt java.util.Scanner.throwFor（Scanner.java:907）at java.util.Scanner.next（Scanner.java:1530）java.util.NoSuchElementException Scanner.java:2160）位于JonesInc.main处的java.util.Scanner.nextInt（Scanner.java:2119）（JonesInc.java:16） public class JonesInc { public stat
This question already has an answer here: Scanner is skipping nextLine() after using next() or nextFoo()? 15 answers You have to clear your Scanner so you can use reader.nextLine(); , like this : if (input % 2 == 0) { System.out.println("The input was even"); } else if (input % 2 == 1) { System.out.println("The input was odd"); } else { System.out.println("The input was not an
这个问题在这里已经有了答案： 扫描仪使用next（）或nextFoo（）后跳过nextLine（）？ 15个答案 您必须清除Scanner，以便使用reader.nextLine(); ， 喜欢这个 ： if (input % 2 == 0) { System.out.println("The input was even"); } else if (input % 2 == 1) { System.out.println("The input was odd"); } else { System.out.println("The input was not an integer"); } reader.nextLine();//<<--