I am trying to write an applet that draws a main square and then uses a recursive method that draws smaller squares on the corners of the main square. I'm really confused on how to go about this. I have drawn the square with the others squares on its corners but i need to do this process recursively and thats where i get lost. I need to set a min side length so the recursive method knows w
我正在尝试编写一个绘制主要正方形的小程序，然后使用递归方法在主要正方形的角上绘制更小的正方形。 我真的很困惑如何去做这件事。 我已经绘制了与其他角落的广场，但我需要递归做这个过程，那就是我迷路了。 我需要设置最小边长，以便递归方法知道何时停止。 这是我的代码。 import javax.swing.JApplet; import java.awt.*; public class LabC extends JApplet { public void paint(Graphics g) { g.drawR
I'm trying to divide square into 4 smaller quadrants by randomly selecting a point in the square and drawing two lines through it, and then dividing each of those quadrants up into 4, and so on, until the width/height is 1, in a recursive way. My code is here: public static void draw(int x0, int y0, int xmax, int ymax) { if (Math.abs(xmax - x0) > 1 && Math.abs(ymax - y0) > 1)
我试图通过在正方形中随机选择一个点并通过它绘制两条线，然后将每个象限分成4个等等，直到宽度/高度为1，将广场分成4个小象限递归的方式。 我的代码在这里： public static void draw(int x0, int y0, int xmax, int ymax) { if (Math.abs(xmax - x0) > 1 && Math.abs(ymax - y0) > 1) { int rx = r.nextInt(xmax - 1) + 1; // line A int ry = r.nextInt(ymax - 1) + 1; // line B StdDraw
I am having a hard time with GSON. I have a simple JSON that I want to deserialize to a Map<String,Object> . It's really intuitive to me that 123 should be parsed as an int (or long), 123.4 as a float( or double). GSON on the other hand creates Doubles all the time. Can I tell GSON to not abuse double all the time? My actual code: Type mapType = new TypeToken<Map<String
我很难与GSON合作。 我有一个简单的JSON，我想反序列化为一个Map<String,Object> 。 我认为123应该被解析为int（或long），123.4被解析为float（或double）。 另一方面，GSON一直在创造双打。 我可以告诉GSON不要一直滥用双倍吗？ 我的实际代码： Type mapType = new TypeToken<Map<String, Object>>() {}.getType(); GSON gson = new Gson(); Map<String, Object> map = gson.fromJson(someS
[NB. This is related to How do I launch a completely independent process from a Java program? but different] I want to be able to spawn external processes (shell scripts) from a "manager" Java process that should keep running when the JVM is killed - but it seems that when I kill the parent Java program the child is killed too (note, the behaviour is different if the JVM exits natur
[NB。 这与我如何从Java程序启动完全独立的进程有关？ 但不同] 我希望能够从一个“管理器”Java进程中产生外部进程（shell脚本），当JVM被终止时它应该继续运行 - 但是当我杀死父Java程序时，孩子也被杀死了（注意，如果JVM自然退出，行为会有所不同）。 我拥有的最简单的测试程序是： public class Runit { public static void main(String args[]) throws IOException, InterruptedException { Runtime.getRun
I need to increment a String in java from "aaaaaaaa" to "aaaaaab" to "aaaaaac" up through the alphabet, then eventually to "aaaaaaba" to "aaaaaabb" etc. etc. Is there a trick for this? It's not much of a "trick", but this works for 4-char strings. Obviously it gets uglier for longer strings, but the idea is the same. char array
我需要通过字母表将Java中的字符串从“aaaaaaaa”增加到“aaaaaab”到“aaaaaac”，然后最终到“aaaaaaba”到“aaaaaabb”等。 这有什么窍门吗？ 这不是什么“窍门”，但这适用于4字符串。 显然它对于更长的字符串会变得更丑，但这个想法是一样的。 char array[] = new char[4]; for (char c0 = 'a'; c0 <= 'z'; c0++) { array[0] = c0; for (char c1 = 'a'; c1 <= 'z'; c1++) { array[1] = c1; for (char c2 = 'a';
I have an infinite recursive loop in java public void infiniteLoop(Long x){ System.out.println(""+x); infiniteLoop(x + 1); } public static void main(String[] args) { StackOverFlow st = new StackOverFlow(); st.infiniteLoop(0L); } In this piece of code it display an StackOverFlow error as expected, but if I look in the console output the error is displayed in multiple lines:
在java中我有一个无限的递归循环 public void infiniteLoop(Long x){ System.out.println(""+x); infiniteLoop(x + 1); } public static void main(String[] args) { StackOverFlow st = new StackOverFlow(); st.infiniteLoop(0L); } 在这段代码中，它按预期显示了一个StackOverFlow错误，但是如果我查看控制台输出，错误将以多行显示： 4806 4807 4808 at java.io.BufferedWriter.flushBuffer(Buff
This question already has an answer here: What is the maximum depth of the java call stack? 4 answers The depth depends on two things: 1: The size of the stack. 2: The amount of stack space used in each recursion. Function parameters, local variables and the return address are all allocated on the stack while objects are allocated on the heap. Recovery It is possible to recover. t
这个问题在这里已经有了答案： java调用堆栈的最大深度是多少？ 4个答案 深度取决于两件事情： 1：堆栈的大小。 2：每次递归中使用的堆栈空间量。 函数参数，局部变量和返回地址都分配在堆栈上，而对象则分配在堆上。 复苏 有可能恢复。 try { myDeepRecursion(); } catch (StackOverflowError e) { // We are back from deep recursion. Stack should be ok again. } 但是，请注意关于错误的以下内容（
I have a program in java, which runs infinite times. Program code: void asd() { try { //inside try block System.out.println("Inside try !!!"); asd(); } finally { //inside finally System.out.println("Inside finally !!!"); asd(); } } OUTPUT : this program runs infinitely, by constantly printing both the sysouts. My questi
我有一个java程序，运行时间无限。 程序代码： void asd() { try { //inside try block System.out.println("Inside try !!!"); asd(); } finally { //inside finally System.out.println("Inside finally !!!"); asd(); } } OUTPUT：通过不断打印两个系统，该程序无限运行。 我的问题：在某些时候，它开始从try块中抛出StackOverflowErrors，所
I was wondering what happens when you try to catch an StackOverflowError and came up with the following method: class RandomNumberGenerator { static int cnt = 0; public static void main(String[] args) { try { main(args); } catch (StackOverflowError ignore) { System.out.println(cnt++); } } } Now my question: Why does this method pri
我想知道当你试图捕捉一个StackOverflowError时会发生什么，并提出以下方法： class RandomNumberGenerator { static int cnt = 0; public static void main(String[] args) { try { main(args); } catch (StackOverflowError ignore) { System.out.println(cnt++); } } } 现在我的问题： 为什么这种方法打印'4'？ 我想也许是因为System.out.print
When observing a StackOverflowError how to retrieve the full call stack? Consider this simple example: public class Overflow { public Overflow() { new Overflow(); } public static void a() { new Overflow(); } public static void main(String[] argv) { a(); } } Now the error reported is: Exception in thread "main" java.lang.StackOverflowError
观察StackOverflowError时如何检索完整的调用堆栈？ 考虑这个简单的例子： public class Overflow { public Overflow() { new Overflow(); } public static void a() { new Overflow(); } public static void main(String[] argv) { a(); } } 现在报告的错误是： Exception in thread "main" java.lang.StackOverflowError at Overflow.<init>(Overflow.java:11