"","style" => "height:450px;width:350px;margin-left:10px;background-color:white;"));?> Edit Property "> Description:"> Department >English Department >Mathematics Dept. >Filipino Dept. >Science Dept. >Social Studies Dept. >MAPEH Dept. >Computer Dept. >Home Economics Dept. >Values Dept. Life Years:"> Cost:&
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$comment= mysql_real_escape_string($comment); I use this.. But it doesnt help. I use TinyMCE to insert strings to my database, but on selection I get weird characters... × ×›×ª×‘ על ידי \r\n rn rn Is thre to parse/enode the string before it goes to the database?!? without this happening? UPDATE: This is how the text that goes into the database looks like: t;div class="
$comment= mysql_real_escape_string($comment); 我用这个..但它没有帮助。 我使用TinyMCE将字符串插入到我的数据库中，但在选择时我得到了奇怪的字符...... × ×›×ª×‘ על ידי \r\n r n r n 是否在字符串进入数据库之前解析/编码字符串？！？ 没有这发生？ 更新： 这就是进入数据库的文本的样子： t;div class="entry" style="padding-top: 20px; padding-right: 20px; paddin
I tried to parse a JSON file using PHP. But I am stuck now. This is the content of my JSON file: { "John": { "status":"Wait" }, "Jennifer": { "status":"Active" }, "James": { "status":"Active", "age":56, "count":10, "progress":0.0029857, "bad":0 } } And this is what I have tried so far: <?php $string = file_g
我试图用PHP解析一个JSON文件。 但我现在卡住了。 这是我的JSON文件的内容： { "John": { "status":"Wait" }, "Jennifer": { "status":"Active" }, "James": { "status":"Active", "age":56, "count":10, "progress":0.0029857, "bad":0 } } 这就是我迄今为止所尝试的： <?php $string = file_get_contents("/home/michael/test.json
I have been having trouble with my code, and I keep getting this error. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '[table_name]" at line 1 My code for this is as follows: <? //indicate the database you want $db_name="test"; //connect to database $connection = @mysql_connect("localhost","
我的代码一直有问题，而且我一直在收到这个错误。 你的SQL语法有错误; 请检查与您的MySQL服务器版本相对应的手册，以找到在第1行的[[table_name]]附近使用的正确语法 我的代码如下： <? //indicate the database you want $db_name="test"; //connect to database $connection = @mysql_connect("localhost","root","") or die (mysql_error()); $db = @mysql_select_db($db_name,$connection) or die (mysql_error());
Hey... so I attempted to run the query below and it just won't do it. I've checked: The number of fields in the form matches the number of fields in the table. The number of session variables matches those numbers too. That the actual query contains the data to be input with an echo. That the table name is correct. That queries work with other tables in the same database (they
嘿...所以我试图运行下面的查询，它不会这样做。 我检查过： 表格中的字段数量与表格中的字段数量相匹配。 会话变量的数量也与这些数字相匹配。 实际查询包含要用回声输入的数据。 表名是正确的。 该查询与同一数据库中的其他表（他们的工作）。 使用或死亡（mysql_error（）;获取“不正确的语法”错误。 重建桌子几次。 这里显然是语法上有问题的一条线，如果你看到它有什么问题或者指向正确的方向，我会非常棒
I got an Error While i submit the Ad if i can not check the mandatory field in form, The Error Is Warning: Invalid argument supplied for foreach() in /home/*******/public_html/wp-content/themes/classipress/includes/views-checkout.php on line 1358 - Warning: Invalid argument supplied for foreach() in /home/*******/public_html/wp-content/themes/classipress/includes/views-checkout.php on lin
我收到了一个错误当我提交广告时，如果我无法检查表单中的必填字段， 错误是 警告：在1358行的/home/*******/public_html/wp-content/themes/classipress/includes/views-checkout.php中为foreach（）提供的无效参数 - 警告：提供给foreach（）的无效参数在954行的/home/*******/public_html/wp-content/themes/classipress/includes/views-checkout.php中 检查一次foreach（）只能接受数组或对象的代码。 注意 在
This question already has an answer here: PHP parse/syntax errors; and how to solve them? 13 answers ; after $email : $email= $_POST['txtEmail']; $email= $_POST['txtEmail'] That line is missing an ; at the end of it
这个问题在这里已经有了答案： PHP解析/语法错误; 以及如何解决它们？ 13个答案 ; $email : $email= $_POST['txtEmail']; $email= $_POST['txtEmail'] 该行缺少一个; 在它的结尾
I have a form that takes in a few fields. Upon entering all fields, email will be sent to me with the details. If any fields are missing, the form will redirect to fail.html file. If I select at least one of the select values, I get redirected to the fail.html page. However, the issue is that if I don't select any of the select multiple dropdown list, I get this error. Warning: impl
我有一个表格，需要在几个领域。 在输入所有字段后，电子邮件会发送给我详细信息。 如果缺少任何字段，表单将重定向到fail.html文件。 如果我至少选择了其中一个选择值，我将重定向到fail.html页面。 但是，问题是，如果我不选择任何选择多个下拉列表，我得到这个错误。 警告：implode（）[function.implode]：第6行传递给/home/mydomain/public_html/iComm/contact.php的参数无效 警告：无法修改标头信息 - 已在第1
I was trying to have my form validate an email address onblur or onkeyup, to check to see if the email address already exists in my database. Not sure if I'm almost there with this code, something isn't working though. Right now, as soon as I start typing in the field, the input box for email is flagged based on how I would want it flagged if an email address was entered if it was alre
我试图让我的表单验证电子邮件地址onblur或onkeyup，以检查电子邮件地址是否已经存在于我的数据库中。 不知道如果我几乎在这个代码，有些东西虽然不工作。 现在，只要我开始在该字段中输入内容，电子邮件的输入框会根据我希望如果输入的电子邮件地址被标记为已标记，如果它已经在我的数据库中。 AJAX中的else语句不起作用，并且如果我无论如何都提交表单，我会从我创建的提示语法错误的错误框中收到页面上的消息。 此外，
I was trying to have my form validate an email address onblur or onkeyup, to check to see if the email address already exists in my database. Not sure if I'm almost there with this code, something isn't working though. Right now, as soon as I start typing in the field, the input box for email is flagged based on how I would want it flagged if an email address was entered if it was alre
我试图让我的表单验证电子邮件地址onblur或onkeyup，以检查电子邮件地址是否已经存在于我的数据库中。 不知道如果我几乎在这个代码，有些东西虽然不工作。 现在，只要我开始在该字段中输入内容，电子邮件的输入框会根据我希望如果输入的电子邮件地址被标记为已标记，如果它已经在我的数据库中。 AJAX中的else语句不起作用，并且如果我无论如何都提交表单，我会从我创建的提示语法错误的错误框中收到页面上的消息。 此外，