How to Trim special Character \r in php

Can anybody tell me here how to trim the special character rn or n in php? I know there is already trim function in php but that is not working. While copying the email address from some other place and copying it into the excel field and during uploading i am getting the invalid email address error. But the email id is correct just due to the special character r the error is showing. Any he

如何在PHP中修改特殊字符\ r

任何人都可以告诉我如何在PHP中修改特殊字符rn或 n? 我知道在PHP中已经有修剪功能,但那是行不通的。 当从其他地方复制电子邮件地址并将其复制到excel字段,并在上传过程中,我收到无效的电子邮件地址错误。 但是,电子邮件ID是正确只是由于特殊字符r错误被显示。 任何帮助将不胜感激。 提前致谢 来自PHP文档trim() : 这个函数返回一个字符串,其中str的开头和结尾都是空白的。 如果没有第二个参数,trim()会去

invalid validators in Symfony

public function configure() { parent::configure(); $email = $this->getWidget('email'); $class = get_class($email); $this->setWidget('email2', new $class( array(), array('maxlength' => $email->getAttribute('maxlength') ) ) ); $this->widgetSchema->moveField( 'email2', sfWidgetFormSch

Symfony中的验证器无效

public function configure() { parent::configure(); $email = $this->getWidget('email'); $class = get_class($email); $this->setWidget('email2', new $class( array(), array('maxlength' => $ email-> getAttribute('maxlength')))); $ this-> widgetSchema-> moveField('email2',sfWidge

Form fields stability php

How can I make fields still in the form fields after submitting the form and return with invalid input data? <form action="" method="post"> <label for="cellPhoneNo">البريد الالكتروني</label> <input type="text" name="emailAddress" class="textField"/> <span>*</span> <span><?php

表单字段稳定性php

在提交表单并返回无效输入数据后,如何让字段仍然在表单域中? <form action="" method="post"> <label for="cellPhoneNo">البريد الالكتروني</label> <input type="text" name="emailAddress" class="textField"/> <span>*</span> <span><?php if($emailValidator != CORRECT_VALUE)

Display uploaded file name below Button in PHP

I am trying to display the name of the uploaded file below the input button. The default text should say "No File Uploaded", once the file is selected and added to the server "file_name.ext was uploaded". Here is my code at the moment: <label for='upload' class='upload-button'></label><input type='file' name="fileAttach" class='upload-button' id='upload'/>

在PHP中显示按钮下方的上传文件名

我正试图在输入按钮下方显示上传文件的名称。 一旦文件被选择并添加到服务器“file_name.ext被上传”,默认文本应该说“没有文件上传”。 这是我目前的代码: <label for='upload' class='upload-button'></label><input type='file' name="fileAttach" class='upload-button' id='upload'/><br>Upload Site List <?php if (isset($_FILES['fileAttach']['name'])) { echo "File is attached."; }

FILES array empty in php when uploading .zip, while .jpg works fine

I am running php 5.3, and have bumped into a problem I've not encountered before. I have an upload form (yes, enctype is set to multipart/form-data), that posts stuff to a php page. The php installation has uploads enabled, and upload_max_filesize is set to .5GB. Uploading pictures (I've tried up to 50 at a time) works fine. Uploading .zip files, however, does not. Uploading a .zip

上传.zip时,php中的FILES数组为空,而.jpg正常工作

我正在运行php 5.3,并遇到了一个我从未遇到过的问题。 我有一个上传表单(是的,enctype被设置为multipart / form-data),它将内容发布到一个php页面。 php安装已启用上传,upload_max_filesize设置为.5GB。 上传图片(我一次尝试多达50个)可以正常工作。 上传.zip文件,但是,不。 上传.zip将使大多数全局输入数组($ _POST,$ _ GET,$ _ FILES和$ _REQUEST)完全空白。 网络嗅探显示发送的POST数据,以及上传的zip

PHP Syntax Error... unexpected T

Full error: Parse error: syntax error, unexpected T_VARIABLE in /home/u572186424/public_html/safe.php on line 56 I have been staring at line 56 and cannot figure it out... exit(); The whole file follows: <?php include_once("connect.php"); ?> <? $sql = "SELECT * FROM users WHERE id='".mysql_real_escape_string($_SESSION['user_id'])."'"; $query = mysql_query($sql) or die(mysql_err

PHP语法错误...意外的T

完整的错误:解析错误:语法错误,第56行/home/u572186424/public_html/safe.php中意外的T_VARIABLE 我一直盯着第56行,无法弄清楚... exit(); 整个文件如下: <?php include_once("connect.php"); ?> <? $sql = "SELECT * FROM users WHERE id='".mysql_real_escape_string($_SESSION['user_id'])."'"; $query = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_object($query); $id = htmlspe

how to get Data from MySQL using PHP ? Getting error with my code

I am trying to get some data from MySQL and echo it using PHP. Following is the code which I used. Please check the code and tell me what's wrong in it. <?php // Get a connection for the database require_once('mysqli_connect.php'); // Create a query for the database $query = "SELECT first_name, last_name, email, street, city, state, zip, phone, birth_date FROM testable

如何使用PHP从MySQL获取数据? 获取我的代码错误

我试图从MySQL获取一些数据并使用PHP回显它。 以下是我使用的代码。 请检查代码并告诉我它有什么问题。 <?php // Get a connection for the database require_once('mysqli_connect.php'); // Create a query for the database $query = "SELECT first_name, last_name, email, street, city, state, zip, phone, birth_date FROM testable"; // Get a response from the database by sending the c

Yii widgets not working

i am new in yii2 i am learning about widget but it's not working on me so guys could you help me to find what mistake i have done? This is the widget which i am using => yii datepicker widget and MY code <?php use yiihelpersHtml; use yiiwidgetsActiveForm; use mrlcodatepickerDatepicker; /* @var $this yiiwebView */ /* @var $model backendmodulessettingsmodelsCom

Yii小部件不工作

我是yii2的新手,我正在学习小部件,但它不适用于我,所以你们可以帮我找到我犯的错误吗? 这是我正在使用的小部件=> yii datepicker小部件 和我的代码 <?php use yiihelpersHtml; use yiiwidgetsActiveForm; use mrlcodatepickerDatepicker; /* @var $this yiiwebView */ /* @var $model backendmodulessettingsmodelsCompanies */ /* @var $form yiiwidgetsActiveForm */ ?> <

Custom Widget in Yii

I create new widget like this: class MyMenu extends CWidget { public function init() { } public function run() { $Items = array( array('label'=>'Home', 'url'=>array('/site/index')), array('label'=>'Add User', 'url'=>array('/user/register')), array('label'=>'View Users', 'url'=>array('/user

Yii中的自定义小部件

我创建这样的新小部件: class MyMenu extends CWidget { public function init() { } public function run() { $Items = array( array('label'=>'Home', 'url'=>array('/site/index')), array('label'=>'Add User', 'url'=>array('/user/register')), array('label'=>'View Users', 'url'=>array('/user/index')

how to make widget in Yii

I want to create a widget, here is the steps I made: created folder widgets in folder protected . created folder views in folder widgets . added this in config/main.php : 'application.widgets.*' this is the code of widgets/Alert.php : class AlertWidget extends CWidget { public $alert = null; private $_data = null; public function init() { $s = Yii::app()

如何在Yii中制作小部件

我想创建一个小部件,下面是我所做的步骤: 在protected文件夹中创建文件夹widgets 在文件夹widgets创建文件夹views 。 在config/main.php添加了这个: 'application.widgets.*' 这是widgets/Alert.php的代码: class AlertWidget extends CWidget { public $alert = null; private $_data = null; public function init() { $s = Yii::app()->session['userId']; $r = Re