I'm creating a php calculator that needs to use the following classes, then print off the users name and the average score they achieved. This is the code I have so far, but it's not displaying correctly, it's saying there are missing arguments and undefined variables but i'm not sure where i've gone wrong! <?php class person { public $name; } class student extends pe
我正在创建一个需要使用以下类的php计算器，然后打印出用户名和他们获得的平均分数。 这是我到目前为止的代码，但它不能正确显示，它是说缺少参数和未定义的变量，但我不知道我错了哪里！ <?php class person { public $name; } class student extends person { function student ($name, $grade1, $grade2) { if(is_numeric($grade1) && is_numeric($grade2)){ $grades = array($grade1, $grade2)
hoping for some help here... currently i am trying to figure out what's wrong with these codes, i am stuck here for 2 days, really appreciate any kind of help. i can't seem to detect my mistake, hope for sharp eyes here. am passing variables from android apps to php, in return the php script should return "success" or "fail".. but i got the above error on line 6,
希望在这里得到一些帮助......目前我想弄清楚这些代码有什么问题，我在这里呆了两天，非常感谢任何帮助。 我似乎无法检测到我的错误，希望在这里睁大眼睛。 我将变量从Android应用程序传递给PHP，作为回报，PHP脚本应该返回“成功”或“失败”.. 但我在第6行得到了上述错误，我不明白为什么。 希望有人指出我的错误。 谢谢万亿... <?php define('HOST','myserver.mysql'); define('USER','myserver_user'); define('PASS',
Parse error: syntax error, unexpected 'if' (T_IF) in StatusIG.php on line 25 I really dont see any problem in my code, why this is happening, please help. Im a beginner in PHP my LINE 25 is >> if($status == 0) $accountdb_ip = "ip"; //Accountserver-IP $accountdb_login = "acc"; //Accountserver-Loginname $accountdb_pw = "psw"; //Accountserver-Passwort $db_ip = "
解析错误：语法错误，第25行的StatusIG.php中出现意外的'if'（T_IF） 我真的没有看到我的代码有任何问题，为什么发生这种情况，请帮助。 我是一名PHP初学者 我的LINE 25是>> if（$ status == 0） $accountdb_ip = "ip"; //Accountserver-IP $accountdb_login = "acc"; //Accountserver-Loginname $accountdb_pw = "psw"; //Accountserver-Passwort $db_ip = "ip"; //DB-Server-IP $db_
Can I get data from three different servers on my php application? Actually I have my data on three different servers and I want to generate a report with having data from all three servers. Can you please suggest me a code for this? function dbcon(ipaddress,servername,serverpassword,databasename) { $con = mysql_connect(ipaddress,servername,serverpassword); if (!$con) { d
我可以从我的php应用程序中的三个不同服务器获取数据吗？ 实际上，我在三台不同的服务器上有我的数据，我想用三台服务器的数据生成一份报告。 你能给我推荐一个这样的代码吗？ function dbcon(ipaddress,servername,serverpassword,databasename) { $con = mysql_connect(ipaddress,servername,serverpassword); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db(
I have a problem, i try to update a mysql database with my php script but i become the message: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'mod = 3, drehtage = 4, schnitttage = 5, dreh = 0, schnitt = 0, off = 0, leiter =' at line 1 i hope you can help me, here is my code to update the database (i just edit
我有一个问题，我尝试更新一个MySQL数据库与我的PHP脚本，但我成为消息： You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'mod = 3, drehtage = 4, schnitttage = 5, dreh = 0, schnitt = 0, off = 0, leiter =' at line 1 我希望你能帮助我，这里是我的代码来更新数据库（我只是编辑用户+传递;）） $con = mysql_connect('lo
This question already has an answer here: PHP parse/syntax errors; and how to solve them? 13 answers @if(Session::has('cart)) 这里有一个错字。 You missed a ' in the view @if(Session::has('cart)) You need to correct it @if(Session::has('cart')) You left to put a ' at the first line of your View. it must be: @if(Session::has('cart'))
这个问题在这里已经有了答案： PHP解析/语法错误; 以及如何解决它们？ 13个答案 @if(Session::has('cart)) 这里有一个错字。 你错过了'在视图中 @if(Session::has('cart)) 你需要纠正它 @if(Session::has('cart')) 你在视图的第一行放置了' 。 一定是： @if(Session::has('cart'))
I developed a laravel application back in August this year, and it was working fine then. I am trying to run that application now, and it returns this error: parse error: syntax error, unexpected T_CLASS, expecting T_STRING or T_VARIABLE or '{' or '$' in D:bkonmeartisan line 31 And line 31 is like this: $kernel = $app->make(IlluminateContractsConsoleKernel::class); My PH
我在今年August开发了一个laravel应用程序，当时它工作的很好。 我试图现在运行该应用程序，并返回此错误： 解析错误：语法错误，意外的T_CLASS，期望T_STRING或T_VARIABLE或D： bkonme artisan第31行中的'{'或'$' 第31行是这样的： $kernel = $app->make(IlluminateContractsConsoleKernel::class); 我的PHP版本是5.6.14 ，我在windows平台上使用XAMPP 。 由于laravel和PHP之间的某些版本冲突，我
I am currently trying to use GuzzleHttp with Laravel to access an API based on the user's input. My set-up so far: $client = new GuzzleHttpClient(); $response = $client ->get('https://api.postcodes.io/postcodes/'Input::get('postcode')); dd($response->getBody()); but the error being returned is: FatalErrorException in ClinicController.php line 129: syntax error, unexpected
我目前正尝试使用GuzzleHttp的GuzzleHttp来根据用户的输入访问API。 到目前为止我的设置： $client = new GuzzleHttpClient(); $response = $client ->get('https://api.postcodes.io/postcodes/'Input::get('postcode')); dd($response->getBody()); 但返回的错误是： ClinicController.php中的FatalErrorException第129行：语法错误，意外的'输入'（T_STRING） 129行是https://api.postcodes.io
This question already has an answer here: PHP parse/syntax errors; and how to solve them? 13 answers Your problem is that you are trying to define an static variable with self static function. Since you have never instantiated the class (static) and you are calling an static variable, you cannot call a self static function. If I copy paste your code and run it with PHP 7 it gives other e
这个问题在这里已经有了答案： PHP解析/语法错误; 以及如何解决它们？ 13个答案 你的问题是你正试图用静态函数定义一个静态变量。 既然你从来没有实例化类（静态），而你正在调用一个静态变量，你不能调用一个自我静态函数。 如果我复制粘贴代码并使用PHP 7运行，则会出现其他错误： 致命错误：常量表达式在第4行的C： inetpub wwwroot test.php中包含无效操作 要解决您的问题，请使用以下命令： <?php class
This question already has an answer here: PHP parse/syntax errors; and how to solve them? 13 answers See alternative PHP syntax. You cannot use it like this <?php foreach ($fixtures as $fixture) { ?> <?php } ?> rather <?php foreach ($fixtures as $fixture): ?> <?php endforeach; ?> <?php foreach ($fixtures as $fixture): ?> <?php endforeach; ?> You should
这个问题在这里已经有了答案： PHP解析/语法错误; 以及如何解决它们？ 13个答案 请参阅其他PHP语法。 你不能像这样使用它<?php foreach ($fixtures as $fixture) { ?> <?php } ?>而不是<?php foreach ($fixtures as $fixture): ?> <?php endforeach; ?> <?php foreach ($fixtures as $fixture): ?> <?php endforeach; ?> 你应该避免这个{?>和这个： <?php} 你不应该把括号