My web page is fine on my server, but my local copy gives a parser error

This question already has an answer here: PHP parse/syntax errors; and how to solve them? 13 answers Most probably the combined use of normal and short open tag at the end of your document. Specifically this line: <?php if(isset($_COOKIE['emailadd'])){ ?> This line is opened with a normal tag. But the end of the if statement is not: <? }?> This causes PHP to conclude the

我的网页在我的服务器上没问题,但是我的本地副本给出了解析器错误

这个问题在这里已经有了答案: PHP解析/语法错误; 以及如何解决它们? 13个答案 最可能的是在文档结尾使用正常和短的开放标签。 具体来说这一行: <?php if(isset($_COOKIE['emailadd'])){ ?> 这条线用一个普通的标签打开。 但if语句的结尾不是: <? }?> 这会导致PHP在最后一行结束文档不完整,因为它仍然期望从该标签关闭标签。 在新安装中默认禁用短打开标签。 据推测,一个安装启用了,另一个没

row()[0], works fine on local server

I have a pagination function implemented in php(with the help tutorials). It works fine on local server. But when uploaded to web server it shows syntax error. Error: Parse error: syntax error, unexpected '[' on line 46 Line 46 is: ')->fetch_row()[0]; Here is my full code: <?php if(isset($_POST['delete'])) { $id = $_POST['delete'];

row()[0],在本地服务器上正常工作

我有一个在php中实现的分页函数(带有帮助教程)。 它在本地服务器上正常工作。 但是当上传到Web服务器时,它显示语法错误。 错误:解析错误:语法错误,第46行出现意外的'['' 第46行是: ')->fetch_row()[0]; 这是我的完整代码: <?php if(isset($_POST['delete'])) { $id = $_POST['delete']; // Connect to the database $dbc = mysqli_connect('x

Unexpected '[' error

This question already has an answer here: PHP Difference between array() and [] 1 answer Your PHP version doesn't support the [] notation, this kind of notation is available from PHP 5.4, use $a = array('f','a','b'); instead.

意外的错误

这个问题在这里已经有了答案: 数组()和[]之间的差异1个答案 您的PHP版本不支持[]符号,这种符号可从PHP 5.4获得,使用$a = array('f','a','b'); 代替。

Parse error on server, works on localhost

I got a few lines of code that run well on my localhost with PHP Version 5.4.19 but doesn't seem to work on a server that runs 5.3.3. On my server I get the following error: Parse error: syntax error, unexpected '[', expecting ',' or ';' in /var/www/html/newpage.php on line 147 The code that seems to be giving the error is: 146. <a href=faq.php?id=<

解析服务器错误,在localhost上运行

我有几行代码可以在PHP Version 5.4.19的本地主机上正常运行,但似乎无法在运行5.3.3的服务器上运行。 在我的服务器上出现以下错误: 解析错误:语法错误,意外的'[',期待','或';' 在147行/var/www/html/newpage.php 似乎给出错误的代码是: 146. <a href=faq.php?id=<?php echo $systemId ?> class="menuitem">FAQ</a> 147. <a href="<?php echo getLin

How to fix syntax error, unexpected T

Parse error: syntax error, unexpected T_IF in view.php on line 27 I really dont see any problem in my code, why this is happening, please help. Im a beginner in PHP Where my LINE 21 is >> if(isset($_GET['page']) && is_numeric($_GET['page'])) if ($result = $mysqli->query("SELECT * FROM players ORDER BY id")) { if ($result->num_rows > 0) {

如何解决语法错误,意外的T

解析错误:语法错误,第27行的view.php中出现意外的T_IF 我真的没有看到我的代码有任何问题,为什么发生这种情况,请帮助。 我是一名PHP初学者 我的LINE 21是>> if(isset($ _ GET ['page'])&& is_numeric($ _ GET ['page'])) if ($result = $mysqli->query("SELECT * FROM players ORDER BY id")) { if ($result->num_rows > 0) { $total_result = $result-&

PHP mail function doesn't complete sending of e

<?php $name = $_POST['name']; $email = $_POST['email']; $message = $_POST['message']; $from = 'From: yoursite.com'; $to = 'contact@yoursite.com'; $subject = 'Customer Inquiry'; $body = "From: $namen E-Mail: $emailn Message:n $message"; if ($_POST['submit']) { if (mail ($to, $subject, $body, $from)) { echo '<p>Your message has been se

PHP邮件功能没有完成e的发送

<?php $name = $_POST['name']; $email = $_POST['email']; $message = $_POST['message']; $from = 'From: yoursite.com'; $to = 'contact@yoursite.com'; $subject = 'Customer Inquiry'; $body = "From: $namen E-Mail: $emailn Message:n $message"; if ($_POST['submit']) { if (mail ($to, $subject, $body, $from)) { echo '<p>Your message has been se

PHP/HTML form processing

The assignment is to create an html form where the user enters the required information, and process the form data via PHP to display the output using $_post method. I can't seem to get the output right, it just basically displays the php code that I wrote. any insight is greatly appreciated Note: The html code is lengthy, but I'm sure it's correct. My problem is with the PHP(next)

PHP / HTML表单处理

该任务是创建一个HTML表单,用户输入所需的信息,并通过PHP处理表单数据以使用$ _post方法显示输出。 我似乎无法得到正确的输出,它只是显示我写的php代码。 任何洞察力都将不胜感激注:html代码冗长,但我确信它是正确的。 我的问题是PHP(下一个)代码。 以下是输出: 0){ $Name = trim($_POST['name']); $adr = trim($_POST['address']); $City = trim($_POST['city']); $state = trim($_POST['state']); $zip = trim($_P

Parse error: syntax error, unexpected '[', expecting

This question already has an answer here: PHP parse/syntax errors; and how to solve them? 13 answers Reference - What does this error mean in PHP? 30 answers

解析错误:语法错误,意外的'[',期待

这个问题在这里已经有了答案: PHP解析/语法错误; 以及如何解决它们? 13个答案 参考 - 这个错误在PHP中意味着什么? 30个答案

PHP cannot redeclare function

I am making a contact form for my site, and it uses a database to store messages sent. I have written a function which adds the message, and the users email, however when I call it in addcontactmessage.php it tells me that I cannot redeclare the function. Fatal error: Cannot redeclare add_message() (previously declared in C:Program Files (x86)EasyPHP-DevServer-14.1VC11datalocalwebprojectsPortf

PHP无法重新声明函数

我正在为我的网站制作联系表单,并使用数据库存储发送的邮件。 我写了一个函数,它添加了消息和用户的电子邮件,但是当我在addcontactmessage.php调用它时,它告诉我不能重新声明该函数。 致命错误:无法在C: Program Files(x86) EasyPHP-DevServer-14.1VC11 data localweb projects Portfolio - Website asset functions.php:3)中重新声明add_message() Program Files(x86) EasyPHP-DevServer-14.1VC11 d

result not working converting mysql to mysqli

i am converting my old mysql to mysqli but ran into this problem mysqli result does not work.looked on the internet and i founded out that it function had been change,for mysqli result is there a equivalent out here? thank here my error Fatal error: Call to undefined function mysqli_result() in C:xampphtdocsbear_mysqlifunctionsusers.php on line 153 function user_exists($con,$username)

结果不能将mysql转换为mysqli

我正在转换我的旧mysql到mysqli,但遇到这个问题mysqli结果不起作用。在互联网上看到,我发现它的功能已经改变,对于mysqli的结果是有没有相当于这里? 谢谢 这里是我的错误 Fatal error: Call to undefined function mysqli_result() in C:xampphtdocsbear_mysqlifunctionsusers.php on line 153 function user_exists($con,$username) { $username = sanitize($con,$username); $query = mysqli_query(