How to overload functions in javascript?

Classical (non-js) approach to overloading: function myFunc(){ //code } function myFunc(overloaded){ //other code } Javascript wont let more than one function be defined with the same name. As such, things like this show up: function myFunc(options){ if(options["overloaded"]){ //code } } Is there a better workaround for function overloading in javascript other than passing an object w

如何在javascript中重载函数?

古典(非js)重载方法: function myFunc(){ //code } function myFunc(overloaded){ //other code } JavaScript不会让多个函数被定义为相同的名称。 因此,这样的事情显示出来: function myFunc(options){ if(options["overloaded"]){ //code } } 是否有一个更好的解决方法,在JavaScript中的函数重载,而不是传递一个超载的对象? 传入重载可以很快导致函数变得过于冗长,因为每个可能的重载都需要一个条件语句

Function Overloading on prototype Javascript?

This question already has an answer here: Function overloading in Javascript - Best practices 29 answers How to overload functions in javascript? 13 answers

函数在Javascript原型上重载?

这个问题在这里已经有了答案: JavaScript中的函数重载 - 最佳实践29个答案 如何在javascript中重载函数? 13个答案

Make same function have different inputs

This question already has an answer here: Function overloading in Javascript - Best practices 29 answers 您可以使用arguments变量来检查参数的数量,如下所示: function F(x, y) { if (arguments.length == 1) { say(x); } else if (arguments.length == 2) { run(x, y) } }

使相同的功能有不同的输入

这个问题在这里已经有了答案: JavaScript中的函数重载 - 最佳实践29个答案 您可以使用arguments变量来检查参数的数量,如下所示: function F(x, y) { if (arguments.length == 1) { say(x); } else if (arguments.length == 2) { run(x, y) } }

Javascript calls wrong function

This question already has an answer here: Function overloading in Javascript - Best practices 29 answers What you are trying to do is called function overloading . Unfortunately, it's not available in JavaScript. But you can always try to kind of simulate it if you need. Please check this link where there's a discussion about the best way to do it: Function overloading in Javas

Javascript调用错误的函数

这个问题在这里已经有了答案: JavaScript中的函数重载 - 最佳实践29个答案 你所要做的就是调用function overloading 。 不幸的是,它在JavaScript中不可用。 但是,如果你需要,你总是可以尝试模拟它。 请查看此链接,其中讨论了最佳方式: Javascript中的函数重载 - 最佳实践 JavaScript中没有函数重载。 你可以使用arguments 。 function call(){ console.log("call param - " + arguments.length); } ca

how to do overloading in javascript?

This question already has an answer here: Function overloading in Javascript - Best practices 29 answers 在调用函数时,JavaScript不要求传递所有参数,因此可以像这样实现重载: function foo(a, b, c) { if (c === undefined) { if (b === undefined) { if (a === undefined) console.log("zero argument pass"); else console.log("one argument pass"); } els

如何在JavaScript中重载?

这个问题在这里已经有了答案: JavaScript中的函数重载 - 最佳实践29个答案 在调用函数时,JavaScript不要求传递所有参数,因此可以像这样实现重载: function foo(a, b, c) { if (c === undefined) { if (b === undefined) { if (a === undefined) console.log("zero argument pass"); else console.log("one argument pass"); } else console.log('two argument pass')

Return value from last AJAX request in AJAX chain that is inside a for loop

I have a for loop, and in one iteration (of something) I need to make four AJAX requests, then wait until result from the last request. jQuery Deferred - getting result of chained ajax calls chaining jquery .when().then() in a loop with fixed end of chain call How to make for loop wait until Async call was successful before to continue Now I've got only how to pass data from previous

返回for循环中AJAX链中最后一次AJAX请求的值

我有一个for循环,在一次迭代中(某事),我需要做四个AJAX请求,然后等待最后一个请求的结果。 jQuery Deferred - 获得链接ajax调用的结果 链接jquery.when()。然后()在一个固定的链调用结束的循环 如何使循环等待,直到异步调用成功之后才能继续 现在我只知道如何将数据从先前的承诺传递给另一个,就像在这个很酷的答案中一样,但我需要将最后一次AJAX调用的值返回给外部数组(并等待最后一次AJAX调用完成)以及

Errors with event.preventdefault

This doesn't work JS: var currentPath = window.location.pathname; var currentPage = currentPath.substring(currentPath.lastIndexOf('/') + 1); $(function() { $("#shoutBox").submit(function(event) { event.preventDefault(); var values = $('#shoutBox').serialize(); $.post("shoutbox.php", values)

event.preventdefault发生错误

这不起作用 JS: var currentPath = window.location.pathname; var currentPage = currentPath.substring(currentPath.lastIndexOf('/') + 1); $(function() { $("#shoutBox").submit(function(event) { event.preventDefault(); var values = $('#shoutBox').serialize(); $.post("shoutbox.php", values) .done(func

Download a file by jQuery.Ajax

I have a Struts2 action in the server side for file downloading. <action name="download" class="com.xxx.DownAction"> <result name="success" type="stream"> <param name="contentType">text/plain</param> <param name="inputName">imageStream</param> <param name="contentDisposition">attachment;filename={fileName}</param>

通过jQuery.Ajax下载文件

我在服务器端有一个用于文件下载的Struts2动作。 <action name="download" class="com.xxx.DownAction"> <result name="success" type="stream"> <param name="contentType">text/plain</param> <param name="inputName">imageStream</param> <param name="contentDisposition">attachment;filename={fileName}</param> <param name="b

Return link for another (same) XMLHttpRequest

I have one link that makes an ajax request and it prints by XHR request another link same at this one before cliked so it's like a loop: starting XHR from <a href="javascript:void(0)" class="doXHR">do XHR</a> than into Ajax success function i repeat into my html this link: <a href="javascript:void(0)" class="doXHR">do XHR</a> but when i output the same link to

返回另一个(相同)XMLHttpRequest的链接

我有一个链接可以创建一个ajax请求,并通过XHR请求打印另一个链接,然后在这个链接上绑定 所以它就像一个循环: 从XHR开始 <a href="javascript:void(0)" class="doXHR">do XHR</a> 比成Ajax成功函数我重复进入我的html这个链接: <a href="javascript:void(0)" class="doXHR">do XHR</a> 但是当我通过以前的doHXR调用的成功函数输出相同的链接到html时,它不允许我做另一个(doXHR ajax调用)

addEventListener firing twice

I'm creating a simple phonebook, that adds person name, last name and phone into a div and into the DOM, with option to delete this div with click event. I have a class called Phonebook which contain these 2 functions: //add an event button to all divs inside the DOM this.deleteBtnEvent = function(){ var _this = this; //get all the divs that currently on the DOM var deleteBtn =

addEventListener触发两次

我正在创建一个简单的电话簿,它将个人姓名,姓氏和电话添加到一个div中,并添加到DOM中,并可以通过点击事件删除该div。 我有一个名为Phonebook的类,它包含这两个函数: //add an event button to all divs inside the DOM this.deleteBtnEvent = function(){ var _this = this; //get all the divs that currently on the DOM var deleteBtn = document.getElementsByClassName('delete'); for (var i = 0;