Count Key/Values in JSON

Possible Duplicate: Length of Javascript Associative Array I have a JSON that looks like this: Object: www.website1.com : "dogs" www.website2.com : "cats" >__proto__ : Object This prints when I do this: console.log(obj); I am trying to get the count of the items inside this JSON, obj.length returns "undefined" and obj[0].length returns Uncaught TypeError: Cannot re

在JSON中计数键/值

可能重复: Javascript关联数组的长度 我有一个如下所示的JSON: Object: www.website1.com : "dogs" www.website2.com : "cats" >__proto__ : Object 这样打印时,我这样做: console.log(obj); 我试图得到这个JSON内的项目的计数,obj.length返回“undefined”和obj [0] .length返回 Uncaught TypeError:无法读取未定义的属性“长度” 我希望在这种情况下返回“2”的长度。 我如何找到计数? 谢谢!

Object length in typescript?

This question already has an answer here: Length of a JavaScript object 32 answers 您可以尝试以下操作: Object.keys(customer).length Object.keys(this.customer).length

打字稿中的对象长度?

这个问题在这里已经有了答案: JavaScript对象32的长度应答 您可以尝试以下操作: Object.keys(customer).length Object.keys(this.customer).length

How to get JavaScript hash table count?

Possible Duplicate: Length of Javascript Associative Array hash_table = {a: 131, b: 222, c:313} The length method is not working of course since it will be confused with a key. So how do I do it? Object.keys will return all the keys in the object as a list, then use length to get the length. example: Object.keys(hash_table).length NOTE that this is ECMA 5 and may not be available in s

如何获得JavaScript哈希表计数?

可能重复: Javascript关联数组的长度 hash_table = {a: 131, b: 222, c:313} 长度方法当然不起作用,因为它会与密钥混淆。 那我该怎么做呢? Object.keys将返回对象中的所有键作为列表,然后使用长度来获取长度。 例: Object.keys(hash_table).length 请注意,这是ECMA 5,可能在某些浏览器中不可用。 有关完整文档,请参阅https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Object/keys。

Get total number of items on Json object?

Possible Duplicate: Length of Javascript Object (ie. Associative Array) I have an object similar to this one: var jsonArray = { '-1': { '-1': 'b', '2': 'a', '10': 'c' }, '2': { '-1': 'a', '2': 'b', '10': 'a' }, '5': { '-1': 'a', '2': 'a', '10': 'b' } }; I'm trying to get it's length, the problem is that jsonArray.length returns 5 inste

获取Json对象上的项目总数?

可能重复: Javascript对象的长度(即关联数组) 我有一个与此类似的对象: var jsonArray = { '-1': { '-1': 'b', '2': 'a', '10': 'c' }, '2': { '-1': 'a', '2': 'b', '10': 'a' }, '5': { '-1': 'a', '2': 'a', '10': 'b' } }; 我试图得到它的长度,问题是, jsonArray.length返回5而不是3(这是它的总项目)。 该阵列相对较长(具有1000x2000项目),并且这必须每

In JavaScript, Why doesn't for in return the contents of Object.prototype?

I get that using a for ... in loop will return all properties of an object, including those from its prototype chain, and using .keys() will give me an array of non-inher (basically for ... in combined with hasOwnProperty) but why doesn't a for ... in loop include things brought in from Object? ie why doesn't for .. in include the toString function from Object? Thanks! A property of a

在JavaScript中,为什么不返回Object.prototype的内容?

我得到,使用for ... in循环将返回一个对象的所有属性,包括它的原型链,并使用.keys()会给我一个非继承数组(基本上是...) hasOwnProperty),但为什么for ... in循环没有包含从Object引入的东西? 也就是说为什么不包含..在Object中包含toString函数? 谢谢! 对象的属性由其键,值定义,以及它是否可配置,可枚举,可写。 一个非枚举属性不会在循环中显示。 当这样创建一个对象属性时 var myObject = {}; myObject[

Augmenting Object.prototype breaks Dojo

I came across an issue which might be a bug, or it might just be the intended functionality. I'm using a thirdparty script that is built with Dojo. In my own app I augment the Function.prototype and the Object.prototype with (for my app) handy utility functions. Including the thirdparty script always resulted in an error. Uncaught TypeError: Cannot set property _scopeName' of undefined Un

增加Object.prototype打破了Dojo

我遇到了一个可能是bug的问题,或者它可能只是预期的功能。 我正在使用由Dojo构建的第三方脚本。 在我自己的应用程序中,我增加了Function.prototype和Object.prototype(对于我的应用程序)方便的实用函数。 包括第三方脚本总是导致错误。 Uncaught TypeError: Cannot set property _scopeName' of undefined Uncaught TypeError: Cannot read property 'toString' of undefined 过了一段时间,我意识到这可能在于我增强了

Is there a way to give all Objects a method without modifying Object.prototype?

I'd like to augment all Objects in my Node.js application with a logging function, such that each object can call this.log or have its log function referenced by thatObject.log . I see a number of advantages in doing this: I can modify each object's log function so it produces special output, and If no object specific log function is provided, it can find a log function up its protot

有没有办法给所有的对象一个方法而不修改Object.prototype?

我想用一个日志记录函数来扩充Node.js应用程序中的所有对象,以便每个对象都可以调用this.log或使其log函数由thatObject.log引用。 我在这方面看到了许多优势: 我可以修改每个对象的log功能,以便产生特殊的输出 如果没有提供对象特定的log功能,它可以在其原型链上找到log功能,并且 在全局上下文中, this.log引用Object.prototype.log ,在任何其他上下文中, this.log引用该对象的log 。 例如: Object.prototype.

Extending native JavaScript objects with Object.create

I've been reading Inheritance and the prototype chain on the Mozilla Developer Network and have been wondering about something it said. One mis-feature that is often used is to extend Object.prototype or one of the other built-in prototypes. I understand why adding a new function onto a native object's prototype would cause issues. Array.prototype.first = function() { return this[0];

用Object.create扩展本地JavaScript对象

我一直在阅读Mozilla开发者网络上的继承和原型链,并一直在想它所说的东西。 常常使用的一个错误特性是扩展Object.prototype或其他内置原型之一。 我明白为什么将一个新的函数添加到本地对象的原型会导致问题。 Array.prototype.first = function() { return this[0]; }; 但是假设有人创建了一个新的数组,并希望它通过其原型链拥有Array所有功能,并且他们做了这样的事情: function MyArray() { Array.apply(this, argum

.extend, not prototype for classes?

I've read an interesting article on DOM prototype extension, showing some good reasons to not always rely on prototypes of Element - I didn't know there were subclasses of elements, like HTMLParagraphElement.prototype <- HTMLElement.prototype <- Element.prototype <- Node.prototype <- Object.prototype In general, Object prototypes can be used for subclassing, but often I se

.extend,而不是类的原型?

我读过一篇关于DOM原型扩展的有趣文章,展示了一些很好的理由不总是依赖Element的原型 - 我不知道有元素的子类,比如 HTMLParagraphElement.prototype < - HTMLElement.prototype < - Element.prototype < - Node.prototype < - Object.prototype 一般来说,对象原型可以用于子类化,但通常我会看到_.extend用于创建mixin或基类,例如在骨干源代码中所见。 _.extend(Model.prototype, Events, {...stuff...}

Why Object.prototype.

In JavaScript non-standard property __ proto__ and function Object.getPrototypeOf (...) return the internal property [[Prototype]]. For all functions the property 'prototype' is an instance of Object.prototype, for example: Array.prototype instanceof Object//true But not so with Object.prototype: Object.prototype.__proto__ === null //true Object.getPrototypeOf( Object.prototype ) ===

为什么使用Object.prototype。

在JavaScript非标准属性__ proto__和函数Object.getPrototypeOf(...)中返回内部属性[[Prototype]]。 对于所有函数,属性'prototype'是Object.prototype的一个实例,例如: Array.prototype instanceof Object//true 但是Object.prototype不是这样的: Object.prototype.__proto__ === null //true Object.getPrototypeOf( Object.prototype ) === null //true mozilla开发者文档只说: 对象的proto属性引用与