This question already has an answer here: In what JS engines, specifically, are toLowerCase & toUpperCase locale-sensitive? 2 answers Unlike toLowerCase , toLocaleLowerCase takes localization into account. In most cases, with most languages, they will produce similar output, however certain languages will behave differently. Check out the description on MDN: The toLocaleLowerCase()
这个问题在这里已经有了答案： 在JS引擎中，具体来说，就是对LowCase＆toUpperCase区域设置敏感吗？ 2个答案 与toLowerCase不同， toLocaleLowerCase将本地化考虑在内。 在大多数情况下，对于大多数语言，他们会产生类似的输出，但某些语言的行为会有所不同。 查看MDN上的说明： toLocaleLowerCase（）方法根据任何特定于语言环境的大小写映射返回转换为小写字母的字符串的值。 toLocaleLowerCase（）不影响字符串本
I want to convert good bunch of url text. from CUSTOMER FAQS HOW wE can HELP PLANNING YOUR BUDGET CUSTOMER CASE STUDIES TENANT DISPUTES EXIT STRATEGIES USEFUL dOCUMENTS USEFUL lINKS to customer-faqs how-we-can-help planning-your-budget customer-case-studies tenant-disputes exit-strategies useful-documents useful-links Is there any online or offline tool which can do this? I want to do bot
我想转换好的一堆url文本。 从 CUSTOMER FAQS HOW wE can HELP PLANNING YOUR BUDGET CUSTOMER CASE STUDIES TENANT DISPUTES EXIT STRATEGIES USEFUL dOCUMENTS USEFUL lINKS 至 customer-faqs how-we-can-help planning-your-budget customer-case-studies tenant-disputes exit-strategies useful-documents useful-links 有没有可以做到这一点的在线或离线工具？ 我想一次做两件事。 value = value.toLowerCase().re
I'm trying to check that the first character of a username is capital, the following can be letters or numbers and at most 20 characters long. Can someone explain why my syntax is wrong? /^[A-z][a-z0-9_-]{3,19}$/ 你的第一个Z不是大写Z. /^[A-Z][a-z0-9_-]{3,19}$/ Your first character needs to be AZ , not Az So /^[Az][a-z0-9_-]{3,19}$/ Should be /^[AZ][a-z0-9_-]{3,19}$/ 我会这样做： va
我试图检查用户名的第一个字符是大写字母，下面可以是字母或数字，最多20个字符。 有人可以解释为什么我的语法错了吗？ /^[A-z][a-z0-9_-]{3,19}$/ 你的第一个Z不是大写Z. /^[A-Z][a-z0-9_-]{3,19}$/ 你的第一个角色需要是AZ ，而不是Az 所以 /^[Az][a-z0-9_-]{3,19}$/ 应该 /^[AZ][a-z0-9_-]{3,19}$/ 我会这样做： var firstChar = strToCheck.substring(0, 1); if (firstChar == firstChar.toUpperCase()) { //
This is something related to my this question. In IE, I resolved issue using iframe in dialog. So it works fine. But in safari I am still facing problem though I have taken iframe into dialog. Safari browser version is 5.1.7(7534.57.2) . Here is the code I have tried: <div> <iframe allowtransparency="true" style="width :100%;height:68em" id="FaxPdf" src='@Url.Action("GetPDF",
这与我的这个问题有关。 在IE中，我解决了在对话框中使用iframe的问题。 所以它工作正常。 但在safari中，我仍然面临问题，虽然我已将iframe带入对话框。 Safari浏览器版本是5.1.7（7534.57.2） 。 这是我尝试过的代码： <div> <iframe allowtransparency="true" style="width :100%;height:68em" id="FaxPdf" src='@Url.Action("GetPDF", "Base", new { pdfPath = @Model.PDFPath })'></iframe> &l
This question already has an answer here: Is JavaScript a pass-by-reference or pass-by-value language? 29 answers Javascript by reference vs. by value [duplicate] 4 answers It almost works as you wrote it. If you return str from the function, you can set newstr that way. //empty string var newStr =''; var myArr = ['it','was', 'the', 'best', 'of', 'times']; var rejoiner = function (arr)
这个问题在这里已经有了答案： JavaScript是传递引用还是传值语言？ 29个答案 Javascript的参考与价值[复制] 4个答案 它几乎和你写的一样。 如果你从函数返回str，你可以这样设置newstr。 //empty string var newStr =''; var myArr = ['it','was', 'the', 'best', 'of', 'times']; var rejoiner = function (arr) { var str = arr.join(' '); //checking that the function is working console.log(str);
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers Your testing code is just wrong. In the occations you see you are "passing by reference", that doesn't mean you are "passing by reference", it means you are changing the contents of the object/array, not the object reference itself. Where you see you are "passin
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 你的测试代码是错误的。 在看到你是“通过引用传递”的情况下，这并不意味着你是“通过引用传递”，这意味着你正在改变对象/数组的内容 ，而不是对象引用本身。 如果你看到你是“按价值传递”，那是因为你设置的价值没有改变。 当你分配 str ，或者obj2或者arr2 （你的代码所说的那些是“按值”）时，你在内部作用域参数变量上设置一个新的引用。 你没有改
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers Change your someMethod to the following: $scope.someMethod = function(model) { model.magic = 321; } // Or accepting a new value $scope.anotherMethod = function(model, value) { model.magic = value; } HTML: <input type="text" data-ng-model="model.magic"> <button type="button
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 改变你的someMethod为以下内容： $scope.someMethod = function(model) { model.magic = 321; } // Or accepting a new value $scope.anotherMethod = function(model, value) { model.magic = value; } HTML： <input type="text" data-ng-model="model.magic"> <button type="button" data-ng-click="someMethod(model)">Do So
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers When you do something like array2 = array1; you are just setting array2 as a reference to array1 . To make a copy of array1 you need to do array2 = array1.slice(); Furthermore, you can not set Array elements with array1.value1 ='1'; . What you have done there is convert your arra
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 当你做一些像array2 = array1; 你只是将array2设置为对array1的引用。 要创建array1的副本，你需要做array2 = array1.slice(); 此外，您不能使用array1.value1 ='1';设置数组元素array1.value1 ='1'; 。 你在那里做的是将你的数组转换成一个对象。 所以你应该做的是： var array1 = []; var array2 = []; array1[0] = 1; array2
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers No , it can't be done. From the TypeScript specification: TypeScript is a syntactic sugar for JavaScript. TypeScript syntax is a superset of ECMAScript 2015 (ES2015) syntax. Every JavaScript program is also a TypeScript program. TypeScript is a superset of JavaScript and in JavaScr
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 不 ，它不能完成。 从TypeScript规范： TypeScript是JavaScript的语法糖。 TypeScript语法是ECMAScript 2015（ES2015）语法的超集。 每个JavaScript程序也是一个TypeScript程序。 TypeScript是JavaScript的超集，在JavaScript中，参数不能通过引用传递（除了对象外）。
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers So the reason this happens is because you are assigning the local variable the new array, whereas prior to the assignment, the local variable held the value of the passed in array. The parameter holds a reference to the value passed in. However, the parameter is still a local variable. Writ
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 所以发生这种情况的原因是因为您将局部变量赋值给新数组，而在赋值之前，局部变量保存了传入数组的值。 该参数保存对传入的值的引用。但是，该参数仍然是局部变量。 写入该变量只会修改局部变量，并且会丢失保持的引用。 从被称为扩展： init(array);//call function init with value array 接下来，上下文环境在实例化时创建，它包含一个局部变