This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers Primitive data types (number, string and boolean) do not change if you change a reference of it, whereas composite data types do change. http://msdn.microsoft.com/en-us/library/ie/7wkd9z69(v=vs.94).aspx In javascript Arrays & Objects are passed by reference, so changing them one place
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 原始数据类型（数字，字符串和布尔）不改变，如果你改变它的引用，而复合数据类型确实改变。 http://msdn.microsoft.com/en-us/library/ie/7wkd9z69(v=vs.94).aspx 在JavaScript中， Arrays & Objects通过引用传递，所以将它们更改为一个地方会影响其他人。 像number ， string这样的原始number是通过值传递的，所以在一个地方改变它们不会影
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers In JS, all assignments are done by value. However, in the case of objects, that value is a reference. That is, if you use yellow = blue , both yellow and blue will contain the same object in memory. So you can't alter one without modifying the other one. In the first case: var blue
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 在JS中，所有的任务都是按价值完成的。 但是，在对象的情况下，该值是一个参考。 也就是说，如果您使用yellow = blue ， yellow和blue将在内存中包含相同的对象。 所以你不能修改另一个。 在第一种情况下： var blue = {a:1}; var yellow = blue; // yellow references blue... yellow = 3; // but not anymore. Now it's just a num
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers As alluded in the comments, JavaScript operates entirely on references, the only exception being that primitive values are kept on the stack and a program does not therefore require a reference to access them. In your example all variable declarations create new values - each an instance of A
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 正如评论中所暗示的，JavaScript完全依赖于引用，唯一的例外是原始值保存在堆栈中，因此程序不需要引用来访问它们。 在你的例子中，所有的变量声明都会创建新的值 - 每一个都是一个数组的实例 - 但是声明一个数组返回的内容是一个引用，而不是数组本身。 例如， [1, 2]是一个值（整数）数组，但[a, b]是一个引用数组。 所以...... 没有东西被复制 。
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers The real problem here is that you're not mutating anything; you're just reassigning the variable z in the function. It wouldn't make a difference if you passed an object or array. var x = ['test']; var y = function(z) { z=['foo']; return z; } y(x); x; // Still ['test']
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 这里真正的问题是你没有改变任何东西; 你只是重新分配函数中的变量z 。 如果你传递了一个对象或者数组，它就没有什么区别。 var x = ['test']; var y = function(z) { z=['foo']; return z; } y(x); x; // Still ['test'] 现在，别人所说的也是如此。 基元不能被突变 。 这实际上比听起来更有趣，因为下面的代码有效： > var x = 1; &g
This question already has an answer here: Javascript by reference vs. by value [duplicate] 4 answers Objects are passed by reference while primitives are passed by value. Note, that primitive values include the following: number String boolean undefined null You can find some more details at MDN on Functions. It uses an evaluation strategy named call by sharing actually. All
这个问题在这里已经有了答案： Javascript的参考与价值[复制] 4个答案 对象通过引用传递，而基元通过值传递。 请注意，该原始值包括以下内容： 数 串 布尔 undefined null 您可以在MDN上的函数中找到更多的细节。 它实际上使用了一个名为call的评估策略。 所有类型都按值传递。 没有引用传递，否则你可以修改在函数的调用位置声明的变量的内容。 通常人们会说在JS中通过引用传递对象。 它们实际上是通
I have written a website that utilizes a SHA-256 hash to validate a user's password. This is a relatively unsecure setup to start with, as most users will have the same username/password. To try and protect it at least a little bit, I do the following: The client requests a new salt from the server The client hashes the password with this salt The client sends the hashed password with
我写了一个网站，利用SHA-256哈希来验证用户的密码。 这是一个相对不安全的设置，因为大多数用户将拥有相同的用户名/密码。 为了尽量保护它，我做了以下工作： 客户端从服务器请求新的salt 客户端用这个盐散列密码 客户端将带有salt的散列密码发送回服务器 服务器散列实际密码并比较两者 这是我的代码： C＃ //Just for testing! private static Dictionary<string, string> users = new Dictionary<stri
Im display all the files in a div which is coming in an array upfiles . Using each in jquery displaying all the files with delete button, when i click on the delete button that respective file details should be deleted from an array. Here is the jquery code each loop which im tring to delete file details from array var int_loop = 1; var display_removebutton=""; $(upfiles).each(fu
即时显示，其中在一个阵列来一个div所有文件upfiles 。 使用每个在jquery中显示带删除按钮的所有文件时，当我点击删除按钮时，应该从数组中删除相应的文件细节。 这是每个循环的jQuery代码，它试图从数组中删除文件详细信息 var int_loop = 1; var display_removebutton=""; $(upfiles).each(function(index, file) { if(total_size > 1000) // size limit comparision
I've parsed the following RSS (http://timesofindia.indiatimes.com/rss.cms) in this way- My code- <!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>News Parser</title> <script src="http://code.jquery.com/jquery-1.11.0.min.js"></script> <link rel="stylesheet" href="css/jquery.mobile-1.4.2.min.css" /> <script src="js/j
我以这种方式解析了以下RSS（http://timesofindia.indiatimes.com/rss.cms） 我的代码 - <!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>News Parser</title> <script src="http://code.jquery.com/jquery-1.11.0.min.js"></script> <link rel="stylesheet" href="css/jquery.mobile-1.4.2.min.css" /> <script src="js/jquery-1.10.2.min.
Iam using a scroller in one of my website. When i click the down arrow to scroll the scroller to the end, 10:00 PM reached. Again if i clicked down arrow, the scroller again moves up and whole content disappears. I want to stop the down arrow's working if the end time [Here 10:00 PM] reached. Same problem occurs in case clicking of up arrow. We tried to solve this but didn't succeed
Iam在我的一个网站上使用滚动条。 当我点击向下箭头滚动滚动到最后， 10:00 PM到达。 再次，如果我点击箭头，滚动条再次上移，整个内容消失。 如果结束时间[Here 10:00 PM]到达，我想停止向下箭头的工作。 如果点击向上箭头，则会出现同样的问题。 我们试图解决这个问题，但没有成功。 Jsfiddle链接：http://jsfiddle.net/Xh59R/3/ 图片attatched。 提前致谢。 检查下面的jsfiddle链接... http://jsfiddle.net/Xh5
This question already has an answer here: Is JavaScript a pass-by-reference or pass-by-value language? 29 answers What am I missing? That your fun function is testing the variable f , which still is bound to the function you passed in, not the variable nullify (which has the value null indeed).
这个问题在这里已经有了答案： JavaScript是传递引用还是传值语言？ 29个答案 我错过了什么？ 你的fun函数正在测试变量f ，该变量仍然与你传入的函数绑定，而不是变量nullify （其值为null ）。