What techniques can be used to speed up C++ compilation times? This question came up in some comments to Stack Overflow question C++ programming style, and I'm interested to hear what ideas there are. I've seen a related question, Why does C++ compilation take so long?, but that doesn't provide many solutions. Vote here have Visual Studio support sharing precompiled headers betw
可以使用哪些技术来加速C ++编译时间？ 这个问题出现在Stack Overflow问题的C ++编程风格的一些评论中，我很想听听有什么想法。 我见过一个相关的问题，为什么C ++编译需要这么长时间？但是这并没有提供很多解决方案。 这里投票有Visual Studio支持共享项目之间的预编译头 语言技巧 皮姆普成语 看看这里的Pimpl成语，这里也称为不透明指针或句柄类。 它不仅加快了编译速度，而且与非抛出交换功能结合在一起时也增加
Possible Duplicate: Why does C++ compilation take so long? Visual studio 2012 slow compile time I'm using visual studio 2012 and the time it takes to compile is way to long. About 20 seconds just for a measly 50 lines of code. I thought it was my computers fault but c# compiles fine on it just not c++. I know that c++ takes longer to compile but 20 seconds is ridiculous. Here's
可能重复： 为什么C ++编译需要这么长时间？ Visual Studio 2012编译时间很慢 我正在使用visual studio 2012，编译所需的时间太长了。 大约20秒只需要50行代码。 我认为这是我的电脑故障，但C＃编译罚款只是不是C + +。 我知道c ++编译需要更长的时间，但20秒很荒谬。 这是我正在编译的代码，需要大约20秒才能编译。 #include<iostream> using namespace std; class Entity { protected: int health; pu
I'm running this code, compiled on 64 bits vc++ 2005, on Windows Server 2008 R2 with 32GB. There is an access violation inside the for loop. #include <iostream> using namespace std; int main(int argc, char* argv[]) { double *x = new double[536870912]; cout << "memory allocated" << endl; for(long int i = 0; i < 536870912; i++) { cout <
我正在运行这个代码，使用32位Windows Server 2008 R2在64位vc ++ 2005上编译。 for循环中存在访问冲突。 #include <iostream> using namespace std; int main(int argc, char* argv[]) { double *x = new double[536870912]; cout << "memory allocated" << endl; for(long int i = 0; i < 536870912; i++) { cout << i << endl; x[i] = 0; }
I have created a simple window using the Win32 API with C++. The window shows up fine, however, there is no styling to it and thus all the buttons and such on the window appear in the Windows 95/Me Style as oppose to the modern windows 7 look. So, how can I get this modern look? I have tried using the xml ways stated in this (http://msdn.microsoft.com/en-us/library/windows/desktop/bb773175%28
我用C ++创建了一个使用Win32 API的简单窗口。 该窗口显示正常，但是，它没有样式，因此窗口上的所有按钮等都出现在Windows 95 / Me Style中，与现代Windows 7外观相反。 那么，我怎样才能获得这种现代感？ 我曾尝试使用此（http://msdn.microsoft.com/en-us/library/windows/desktop/bb773175%28v=vs.85%29.aspx）microsoft文档中所述的xml方法，但该程序没有编译。 我相信这是因为我使用MinGW编译器来反对VC ++编译器，但
When the chessboard is stored in a variety of bitboards, how do modern chess engines recognise what type/side piece is situated on a particular cell? I'm having problems with this, since to find out what type/side piece a particular bit is, I have to always do: if((bit_check & occupied) == 0ULL) ... // empty else if((bit_check & white) != 0ULL) // white if((bit_check & white
当棋盘存放在各种棋盘上时，现代象棋引擎如何识别哪种类型/侧面棋子位于特定的单元上？ 我在这方面遇到了问题，因为要找出某个特定位置是什么类型/边框，我必须始终这样做： if((bit_check & occupied) == 0ULL) ... // empty else if((bit_check & white) != 0ULL) // white if((bit_check & white_pawns) != 0ULL) ... // white pawns else if((bit_check & white_rooks) != 0ULL) ... // white rook
If we want to have a switch statement where for each case we need to run some instructions then break we would so something like this: switch (condition) { case (opt1): // do stuff break; case (opt2): // do stuff break; case (opt3): // do stuff break; // ... default: // do stuff } Is it possible to have an exclusive switch, without fall
如果我们想要在每种情况下都有一个switch语句，那么我们需要运行一些指令，然后打破，我们会这样做： switch (condition) { case (opt1): // do stuff break; case (opt2): // do stuff break; case (opt3): // do stuff break; // ... default: // do stuff } 是否可以有一个独占开关，没有经过，在默认情况下，每个选项都应该中断，而不必明确声明break指令？
This question already has an answer here: Why can't variables be declared in a switch statement? 23 answers Try adding {} : default: { int32 x = 1; doSomething(x); break; } According to the standard: It is possible to transfer into a block, but not in a way that bypasses declarations with initialization. A program that jumps 91 from a point where a variable with automati
这个问题在这里已经有了答案： 为什么不能在switch语句中声明变量？ 23个答案 尝试添加{} ： default: { int32 x = 1; doSomething(x); break; } 根据标准： 可以将其转换为块，但不能绕过具有初始化的声明。 从自动存储持续时间不在范围的变量点到其范围内的点跳转91的程序不合格，除非.... void f() { // ... goto lx; // ill-formed: jump into scope of a // ... ly: X a
This question already has an answer here: Why can't variables be declared in a switch statement? 23 answers Yes, there is. Enclose the body of the case statement in brackets, like this: case {statement}: { sometype & handle = getbar(); ... }
这个问题在这里已经有了答案： 为什么不能在switch语句中声明变量？ 23个答案 就在这里。 将括号内的case语句的正文括起来，如下所示： case {statement}: { sometype & handle = getbar(); ... }
This question already has an answer here: Why can't variables be declared in a switch statement? 23 answers C++ does not allow switches (or other similar code, such as goto ) to jump over initialisations . In the switch, both the Queue and the Stack are at the same scope, and it would be possible for the switch code not to initialise one (or both) of them in that scope, depending on the
这个问题在这里已经有了答案： 为什么不能在switch语句中声明变量？ 23个答案 C ++不允许开关（或其他类似的代码，如goto ）跳过初始化。 在交换机中， Queue和Stack都处于相同的范围，并且交换机代码可能不会在该范围内初始化它们中的一个（或两者），这取决于所打开的值。 对于if / else，这并非如此，因为他们处于不同的范围。
Possible Duplicate: Why can't variables be declared in a switch statement? switch (i){ case 'i': int i; break; } //it works switch (i){ case 'i': int i;i=0; break; } //it also works switch (i){ case 'i': int i=0; break; } //it ain't Dunno the error, but this also works for me in Objective-C (strict superset of C, although I don't believe that 1) and I do this always , even when
可能重复： 为什么不能在switch语句中声明变量？ switch (i){ case 'i': int i; break; } //it works switch (i){ case 'i': int i;i=0; break; } //it also works switch (i){ case 'i': int i=0; break; } //it ain't 不要错误，但这也适用于Objective-C（严格的C超集，尽管我不相信1），并且我总是这样做，即使我只是简单地返回一些东西： switch (i) { case 'i': { // <- curly brackets int i = 0; br