Possible Duplicate: Size of character ('a') in C/C++ The following program #include <stdio.h> int main() { printf("%dn", sizeof('')); printf("%dn", sizeof(0)); } compiled with gcc outputs 4 4 and with g++ 1 4 Why is this happening? I know this it's not a compiler thing but a difference between C and C++ but what's the reason? In C, character constants h
可能重复： C / C ++中字符的大小（'a'） 以下程序 #include <stdio.h> int main() { printf("%dn", sizeof('')); printf("%dn", sizeof(0)); } 用gcc输出编译 4 4 和g ++ 1 4 这是为什么发生？ 我知道这不是编译器，而是C和C ++之间的区别，但是原因是什么？ 在C中，字符常数具有类型int标准的每6.4.4.4（10）， 整数字符常量的类型为int。 包含映射到单字节执行字符的单个字符的整数字
I have an unmanaged C++ project, which produces runtime errors when the linker libraries (Properties->Linker->Input->Additional Dependencies) are listed in a specific order but runs fine when I change the order of libraries. I understand why the order could cause Link errors (Why does the order in which libraries are linked sometimes cause errors in GCC?) but how could it possibly cause
我有一个非托管C ++项目，当链接程序库（Properties-> Linker-> Input-> Additional Dependencies）按特定顺序列出，但在更改库的顺序时运行良好时，会产生运行时错误。 我明白为什么命令可能导致链接错误（为什么链接库的顺序有时会导致GCC错误？），但它怎么会导致运行时错误呢？ 我在VS2005,2008和2010年观察到了这一点。 什么样的运行时错误？ 你不说，所以我们必须猜测。 以下是运行时错误发生的一种方式：
today i encountered a problem with linking my compiled cuda stuff. i have a uptodate debian testing w/ 2.6.32-3-amd64. i worked all day on my code. compiling from time to time. had no problem. but then after a minor code change i got following error: gcc -o pa CUDA.o histogram256.o histogram64.o main.o -lrt -lm -lcudart -I. -I/data/cuda/include -I/data/cuda/C/common/inc -L/data/cuda
今天我遇到了连接我编译的cuda的问题。 我有一个uptodate debian测试w / 2.6.32-3-amd64。 我整天在我的代码上工作。 不时编译。 没有问题。 但后来一个小的代码更改后，我得到以下错误： gcc -o pa CUDA.o histogram256.o histogram64.o main.o -lrt -lm -lcudart -I. -I/data/cuda/include -I/data/cuda/C/common/inc -L/data/cuda/lib64 /usr/bin/ld: main.o: undefined reference to symbol 'std::basic_ifstre
Hi iam begginer at c++ i have class with static methods and i cant access them it throws me an error 1>------ Build started: Project: CPractice, Configuration: Debug Win32 ------ 1> Source.cpp 1>Source.obj : error LNK2001: unresolved external symbol "private: static class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> > CPractice::
您好iam begginer在c + +我有静态方法的类，我不能访问它，它会引发一个错误 1>------ Build started: Project: CPractice, Configuration: Debug Win32 ------ 1> Source.cpp 1>Source.obj : error LNK2001: unresolved external symbol "private: static class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> > CPractice::name" (?name@CPractice@@0V?$b
I'm new to c++ and i want to compile my testprogram . i have now 3 files "main.cpp" "parse.cpp" "parse.h" how can i compile it with one command? Compile them both at the same time and place result in a.out $ g++ file.cpp other.cpp Compile them both at the same time and place results in prog2 $ g++ file.cpp other.cpp -o prog2 Compile each separately and
我是新来的C ++，我想编译我的测试程序。 我现在有3个文件“main.cpp”“parse.cpp”“parse.h” 我怎样才能用一个命令编译它？ 在同一时间编译它们并将结果放入a.out $ g++ file.cpp other.cpp 同时编译它们并将结果放在prog2中 $ g++ file.cpp other.cpp -o prog2 分别进行编译，然后将它们链接到a.out中 $ g++ -c file.cpp $ g++ -c other.cpp $ g++ file.o other.o 分别进行编译，然后将它们链接到prog2 $ g++ -c file
I was looking at the output from my build in Eclipse. I'm cross compiling for a ColdFire processor. The compilation line looks like this: m68k-elf-g++ -O2 -falign-functions=4 -IC:nburninclude -IC:nburnMOD52... followed by more include file, obvious "compiler" flags and finally the one source file I changed. The next line invokes the same tool again: m68k-elf-g++ srcmain.o srcT
我正在查看Eclipse中构建的输出。 我正在交叉编译ColdFire处理器。 编译线如下所示： m68k-elf-g++ -O2 -falign-functions=4 -IC:nburninclude -IC:nburnMOD52... 其次是更多的包含文件，明显的“编译器”标志，最后是我更改的源文件。 下一行再次调用相同的工具： m68k-elf-g++ srcmain.o srcTouchPanelMediator.o srcStartup.o.... 其次是更多.o文件一些.ld文件和一些.a文件。 这似乎将所有不同类型的目标文件链接在一起
I made a file hi.cpp and I wrote the command given below: #include <iostream> using namespace std; int main () { cout << "Hello World! "; cout << "I'm a C++ program"; return 0; } then I ran it in my RHEL 6 machine with the following command gcc hi.cpp and I got some errors which are as follows: [chankey@localhost ~]$ gcc hi.cpp /tmp/cc32bnmR.o: In function `main': hi.
我创建了一个hi.cpp文件，并且我写了下面给出的命令： #include <iostream> using namespace std; int main () { cout << "Hello World! "; cout << "I'm a C++ program"; return 0; } 然后使用以下命令将它运行在RHEL 6机器中 gcc hi.cpp 我得到了一些错误，如下所示： [chankey@localhost ~]$ gcc hi.cpp /tmp/cc32bnmR.o: In function `main': hi.cpp:(.text+0xa): undefined reference to `std:
I just found on my Ubuntu, there are two different C++ compiler: /usr/bin/g++ and /usr/bin/c++. I am not familiar with the latter, but man c++ just jumps to the manpage of gcc. I wonder what is their difference as C++ compilers? Thanks and regards! This is typical Ubuntu symlink mayhem. If you ls -l /usr/bin/c++ , you will see it is actually a symbolic link. to: /etc/alternatives/c++ W
我在我的Ubuntu上发现，有两种不同的C ++编译器：/ usr / bin / g ++和/ usr / bin / c ++。 我不熟悉后者，但man c ++只是跳转到gcc的manpage。 我不知道它们与C ++编译器有什么不同？ 感谢致敬！ 这是典型的Ubuntu符号链接混乱。 如果你使用ls -l /usr/bin/c++ ，你会发现它实际上是一个符号链接。 至： /etc/alternatives/c++ 而这又是一个符号链接： /usr/bin/g++ 所以，在Ubuntu系统上，c ++是g ++。 链接间
Question: How to compile a C++ program with gcc compiler? info.c: #include<iostream> using std::cout; using std::endl; int main() { #ifdef __cplusplus cout << "C++ compiler in use and version is " << __cplusplus << endl; #endif cout <<"Version is " << __STDC_VERSION__ << endl; cout << "Hi" << __FILE__ << __LINE__ <&l
问题：如何用gcc编译器编译C ++程序？ info.c： #include<iostream> using std::cout; using std::endl; int main() { #ifdef __cplusplus cout << "C++ compiler in use and version is " << __cplusplus << endl; #endif cout <<"Version is " << __STDC_VERSION__ << endl; cout << "Hi" << __FILE__ << __LINE__ << endl; } 当我尝试
This question already has an answer here: What is the difference between g++ and gcc? 10 answers GCC 4.5.2 Linker gots Problem while using Exceptions (C++) 2 answers
这个问题在这里已经有了答案： g ++和gcc有什么区别？ 10个答案 GCC 4.5.2链接器问题使用异常（C ++）时出现问题2个答案