Image recognition of well defined but changing angle image

PROBLEM I have a picture that is taken from a swinging vehicle. For simplicity I have converted it into a black and white image. An example is shown below: The image shows the high intensity returns and has a pattern in it that is found it all of the valid images is circled in red. This image can be taken from multiple angles depending on the rotation of the vehicle. Another example is he

图像识别良好定义但角度变化的图像

问题 我有一张从摇摆车拍摄的照片。 为了简单起见,我将它转换成黑白图像。 一个例子如下所示: 图像显示高强度的回报,并且有一个图案,发现所有有效图像都以红色圈出。 取决于车辆的旋转,可以从多个角度拍摄该图像。 另一个例子是在这里: 这里的意图是试图识别存在这种图案的图片单元。 目前的做法 到目前为止,我已经尝试了几种方法,我正在使用Matlab进行测试,但最终会在c ++中实现。 算法的时间效率是理

time Image Processing: Noise in HSV image (openCV)

I am doing a real-time shapes and colors classification system with very high accuracy. It seems like my preprocessing phase is not good enough so that the result is not as accurate as I expected. Here is what I'm doing: Take data from the Camera can crop it to receive ROI. Convert ROI Image from RGB to HSV space. Using a median filter to reduce noise in HSV image. Threshold the ima

实时图像处理:HSV图像中的噪声(openCV)

我正在做一个实时形状和颜色分类系统,具有非常高的准确性。 似乎我的预处理阶段不够好,以至于结果不如我预期的那么精确。 这是我正在做的事情: 从相机获取数据可以裁剪以获得投资回报率。 将ROI图像从RGB转换为HSV空间。 使用中值滤波器来减少HSV图像中的噪声。 阈值图像 在图像中使用扩张和侵蚀去除小孔和小物体 使用findContours和approxPolyDP来检测方形对象。 这是我的预处理阶段: image_cv = cv::cvarr

OpenCV detect image against a image set

I would like to know how I can use OpenCV to detect on my VideoCamera a Image. The Image can be one of 500 images. What I'm doing at the moment: - (void)viewDidLoad { [super viewDidLoad]; // Do any additional setup after loading the view. self.videoCamera = [[CvVideoCamera alloc] initWithParentView:imageView]; self.videoCamera.delegate = self; self.videoCamera.defaultA

OpenCV根据图像集检测图像

我想知道如何使用OpenCV在我的VideoCamera上检测图像。 该图像可以是500张图像之一。 我现在在做什么: - (void)viewDidLoad { [super viewDidLoad]; // Do any additional setup after loading the view. self.videoCamera = [[CvVideoCamera alloc] initWithParentView:imageView]; self.videoCamera.delegate = self; self.videoCamera.defaultAVCaptureDevicePosition = AVCaptureDevicePositionBack

Image Processing: Algorithm Improvement for 'Coca

One of the most interesting projects I've worked on in the past couple of years was a project about image processing. The goal was to develop a system to be able to recognize Coca-Cola 'cans' (note that I'm stressing the word 'cans', you'll see why in a minute). You can see a sample below, with the can recognized in the green rectangle with scale and rotation. Some

图像处理:对'古柯'的算法改进

过去几年中我最感兴趣的项目之一就是一个关于图像处理的项目。 我们的目标是开发一个能够识别可口可乐'罐'的系统 (请注意,我强调'罐'这个词,你会在一分钟内看到为什么。 您可以在下面看到一个示例,其中可以通过缩放和旋转在绿色矩形中识别。 项目的一些限制: 背景可能非常嘈杂。 该罐可以具有任何比例或旋转或甚至定向(在合理范围内)。 图像可能具有一定程度的模糊性(轮廓可能不完全是直的)

Why to license an application under GNU GPL?

I am extremely sorry if this is an incorrect question, but want to answer to this question very badly, hence asking. I am developing an application which I want to make open source. I believe there is appreciable amount of my own original work in it & would like to have some commercial interest in it. So I am choosing to dual license my project. One with GNU LGPL - to give back to the co

为什么要在GNU GPL下授权应用程序?

如果这是一个不正确的问题,我非常抱歉,但是要非常糟糕地回答这个问题,因此要求。 我正在开发一个我想开源的应用程序。 我相信我自己的原创作品有相当数量,并且希望对它有一定的商业兴趣。 所以我选择双重许可我的项目。 一个与GNU LGPL - 回报社区其他与商业 - 获得一些钱 我觉得LGPL给希望在应用程序中使用我的代码的应用程序开发人员提供了更好的自由,与GPL给出的相比。 然后我不明白为什么这么多流行的应用程序

c++

I know that you can change the color of a line edit, so long as all the text is the same color, but is it possible to assign different colors to characters? That is, some characters are red, and some are black, or simply every character has a different color. There is a similar question here - How can I change color of part of the text in QLineEdit?, but in my case there is an additional const

C ++

我知道你可以改变线条编辑的颜色,只要所有的文字都是相同的颜色,但是可以给字符分配不同的颜色? 也就是说,有些字符是红色的,有些是黑色的,或者简单地说每个字符都有不同的颜色。 这里还有一个类似的问题 - 我怎样才能改变QLineEdit中部分文本的颜色,但在我的情况下还有一个额外的约束 - QLineEdit在编辑时必须保留颜色位置,而输入的新文本假设一些默认颜色。 另一个问题没有这个限制。 它确实有一个有用的答案,

How to handle QSslSocket: cannot resolve TLSv1

I'm trying to develop a program that can connect to google map and get the map by using google map GPS parameters. so i have one problem , when i compile the code and click the run button i see these errors in the application output: QSslSocket: cannot resolve TLSv1_1_client_method QSslSocket: cannot resolve TLSv1_2_client_method QSslSocket: cannot resolve TLSv1_1_server_method QSslS

如何处理QSslSocket:无法解析TLSv1

我试图开发一个程序,可以连接到谷歌地图,并通过使用谷歌地图GPS参数获取地图。 所以我有一个问题,当我编译代码并单击运行按钮我在应用程序输出中看到这些错误: QSslSocket:无法解析TLSv1_1_client_method QSslSocket:无法解析TLSv1_2_client_method QSslSocket:无法解析TLSv1_1_server_method QSslSocket:无法解析TLSv1_2_server_method 我googled了很多,但不能找到任何答案,我也试图安装open-ssl v1.0.1和

Shallow copying a pointer. Why is this code working?

To my understanding of the subject: A shallow copy is when the non-pointer types of an object are copied to another object. Shallow copies can't be done when an object has pointers because, the object being copied will get the address of that pointer, and when either of the two objects are deleted, the other will be left dangling since they were pointing to the same location in memory. A de

浅拷贝指针。 为什么这个代码有效?

为了我的理解主题:浅拷贝是当一个对象的非指针类型被复制到另一个对象时。 当一个对象有指针时,浅拷贝是无法完成的,因为被拷贝的对象将得到该指针的地址,并且当两个对象中的任何一个被删除时,另一个将被留下,因为它们指向相同的位置在记忆中。 涉及指针时使用深层复制,因为它保留与原始对象空间分开的空间,并将内容从一个内存位置复制到另一个内存位置。 这样,当其中一个对象被删除时,其他对象不会悬空。 这就是说

C++ compiler 'shallow' copies and assignments

I'm taking a class on object oriented programming using C++. In our text it says, If we do not declare a copy constructor, the compiler inserts code that implements a shallow copy. If we do not declare an assignment operator, the compiler inserts code that implements a shallow assignment. What I want to know, is whether this is in fact true, what the alluded to compiler mechanism is ac

C ++编译器'浅'的副本和分配

我正在使用C ++进行面向对象编程的课程。 在我们的文字中说, 如果我们不声明复制构造函数,编译器将插入实现浅拷贝的代码。 如果我们不声明一个赋值操作符,编译器会插入实现浅赋值的代码。 我想知道的是,这是否实际上是真实的,实际调用的暗指编译器机制以及它是如何工作的。 这不是关于复制构造函数的问题,而是关于编译器行为。 编辑>更多的上下文 复制文本定义的构造函数: 复制构造函数的定义包含逻辑

Implementing Deep Copy

I'm trying to implement deep copy on an array of generic pointers. I've been fighting this for 2+ days and can't for the life of me figure it out! There is an associated test program provided by my professor but I don't think it's needed here. As for the implementations. See the option below in the code... Option 1: flat out fails the test, it's a shallow copy. Op

实施深度复制

我试图在通用指针数组上实现深层复制。 我一直在争取这2 +天,并不能为我的生活弄清楚! 有一个由我的教授提供的相关测试程序,但我不认为这是需要的。 至于实现。 在代码中查看下面的选项... 选项1:扁平测试失败,这是一个浅的副本。 选项2:产生段错误,我不明白为什么我只是取消引用指针。 选项3:再次通过测试。 它是一个浅拷贝? 选项4:我甚至无法编译,但我希望分配一个新的元素,只是从原来的位复制。