This question already has an answer here: How to display a dynamically allocated array in the Visual Studio debugger? 9 answers You can try this nice little trick for C++. Take the expression which gives you the array and then append a comma and the number of elements you want to see. Expanding that value will show you elements 0-(N-1) where N is the number you add after the comma. For e
这个问题在这里已经有了答案： 如何在Visual Studio调试器中显示动态分配的数组？ 9个答案 你可以尝试一下C ++的这个不错的小技巧。 采用给出数组的表达式，然后附加一个逗号和您想要查看的元素数量。 展开该值将显示元素0-（N-1），其中N是您在逗号后添加的数字。 例如，如果pArray是数组，则在监视窗口中键入pArray,10 。 如果你有一个大数组，并且只想看到数组的一个子部分，你可以在监视窗口中输入这个数组; ptr+
I wrote the following heap debugger in order to demonstrate memory leaks, double deletes and wrong forms of deletes (ie trying to delete an array with delete p instead of delete[] p) to beginning programmers. I would love to get some feedback on that from strong C++ programmers because I have never done this before and I'm sure I've done some stupid mistakes. Thanks! #include <cstd
我写了下面的堆调试器来演示内存泄漏，双重删除和错误形式的删除（即试图删除一个delete p而不是delete[] p）到开始的程序员。 我很想从强大的C ++程序员那里得到一些反馈，因为我从来没有这样做过，我确信我犯了一些愚蠢的错误。 谢谢！ #include <cstdlib> #include <iostream> #include <new> namespace { const int ALIGNMENT = 16; const char* const ERR = "*** ERROR: "; int counter
How should I write ISO C++ standard conformant custom new and delete operators? This is in continuation of Overloading new and delete in the immensely illuminating C++ FAQ, Operator overloading, and its follow-up, Why should one replace default new and delete operators? Section 1: Writing a standard-conformant new operator Part 1: Understanding the requirements for writing a custom new oper
我应该如何编写符合ISO C ++标准的自定义new和delete操作符？ 这是继续重载新的和删除的巨大照亮的C ++常见问题，运算符重载，及其后续，为什么要替换默认的新的和删除操作符？ 第1部分：编写一个符合标准的new操作符 第1部分：了解编写自定义new操作符的要求 第2部分：了解new_handler要求 第3部分：了解特定场景要求 第2部分：编写符合标准的delete操作符 实现自定义删除操作符 （注意：这是一个Stack Overflo
According to the draft of the standard N4713 (7.11/1): A null pointer constant is an integer literal (5.13.2) with value zero or a prvalue of type std::nullptr_t . and 21.2.3/2: The macro NULL is an implementation-defined null pointer constant. follow that NULL can be defined as nullptr . Same is mentioned on cppreference: #define NULL 0 //since C++11 #define NULL nullptr At the same t
根据标准N4713（7.11 / 1）的草案： 空指针常量是一个整型文字（5.13.2），其值为零或类型为std::nullptr_t 。 和21.2.3 / 2： 宏NULL是一个实现定义的空指针常量。 遵循NULL可以定义为nullptr 。 在cppreference中也提到了这一点： #define NULL 0 //since C++11 #define NULL nullptr 同时“添加剂操作员”条款（8.5.6 / 7）说： 如果将值0添加到空指针值或从空指针值中减去，则结果为空指针值。 如果减去两个空指
In the C++11 standard, I don't understand the reason why taking the address of nullptr is disallowed whereas one is allowed to take the address of their own std::nullptr_t instances. Aside from the fact that nullptr is a reserved keyword, is there any designated reasoning for this decision? Simply because it amuses me, I attempted to circumnavigate this restriction with the following funct
在C ++ 11标准，为什么服用nullptr是不允许的，而一个地址被允许拿自己的std :: nullptr_t实例的地址，我不明白其中的道理。 除了nullptr是一个保留关键字的事实之外，这个决定是否有任何指定的推理？ 仅仅因为它让我感到厌烦，我试图用下面的函数来绕过这个限制： decltype(nullptr)* func(const decltype(nullptr) &nref) noexcept { return const_cast<decltype(nullptr)*>(reinterpret_cast<const declt
I just found myself not fully understanding the logic of std::move() . At first, I googled it but seems like there are only documents about how to use std::move() , not how its structure works. I mean, I know what the template member function is but when I look into std::move() definition in VS2010, it is still confusing. the definition of std::move() goes below. template<class _Ty>
我发现自己不完全理解std::move()的逻辑。 起初，我对它进行了搜索，但似乎只有关于如何使用std::move()文档，而不是它的结构如何工作。 我的意思是，我知道模板成员函数是什么，但是当我查看VS2010中的std::move()定义时，它仍然令人困惑。 std :: move（）的定义如下。 template<class _Ty> inline typename tr1::_Remove_reference<_Ty>::_Type&& move(_Ty&& _Arg) { // forward
The C++11 std::move(x) function doesn't really move anything at all. It is just a cast to r-value. Why was this done? Isn't this misleading? It is correct that std::move(x) is just a cast to rvalue - more specifically to an xvalue, as opposed to a prvalue. And it is also true that having a cast named move sometimes confuses people. However the intent of this naming is not to confus
C ++ 11 std::move(x)函数根本不会移动任何东西。 这只是一个演员r值。 为什么这样做？ 这不是误导？ std::move(x)只是对右值的强制转换是正确的 - 更具体地说，是一个xvalue，而不是一个prvalue。 而且有一个名为move的演员有时会混淆人们，这也是事实。 然而，这个命名的目的不是混淆，而是让你的代码更具可读性。 move的历史可以追溯到2002年的原始移动提议。本文首先介绍了右值引用，然后展示了如何编写更高效的std
Is it better in C++ to pass by value or pass by constant reference? I am wondering which is better practice. I realize that pass by constant reference should provide for better performance in the program because you are not making a copy of the variable. It used to be generally recommended best practice1 to use pass by const ref for all types, except for builtin types ( char , int , double ,
在C ++中传递值或传递常量引用会更好吗？ 我想知道哪种更好的做法。 我意识到通过常量引用应该提供更好的性能，因为你没有制作变量的副本。 对于迭代器和函数对象 （lambdas，派生自std::*_function类），除了内建类型（ char ， int ， double等）之外，对于所有类型使用const ref，通常建议使用最佳做法1 ）。 在移动语义存在之前尤其如此。 原因很简单：如果按值传递，必须创建一个对象的副本，除了非常小的对象外，
Possible Duplicate: What are rvalues, lvalues, xvalues, glvalues, and prvalues? The standard states: 3.2 The this pointer 1 In the body of a non-static (9.3) member function, the keyword this is a non-lvalue expression whose value is the address of the object for which the function is called. What is the difference between rvalue,lvalue, non-rvalue, non-lvalue? How many types of such *va
可能重复： 什么是右值，左值，xvalues，glvalues和prvalues？ The standard states: 3.2 The this pointer 1 In the body of a non-static (9.3) member function, the keyword this is a non-lvalue expression whose value is the address of the object for which the function is called. 右值，左值，非右值，非左值有什么区别？ 这些*值有多少种？ 我的意思是我也听说过xvalues。 需要了解这一点。 这些与临
This question already has an answer here: What are rvalues, lvalues, xvalues, glvalues, and prvalues? 11 answers There is no cyclic definition in that sentence. The following expressions are xvalue expressions: a function call or an overloaded operator expression, whose return type is rvalue reference to object, such as std::move(x); ... Here std::move is merely an example, the essen
这个问题在这里已经有了答案： 什么是右值，左值，xvalues，glvalues和prvalues？ 11个答案 该句子中没有循环定义。 以下表达式是xvalue表达式： 函数调用或重载运算符表达式，其返回类型是右值引用对象，如std :: move（x）; ... 这里std::move 仅仅是一个例子，其实质是“谁的返回类型是右值引用”。 由于返回右值引用的函数不是很常见，而std::move的目的是这样做，因此它是一个很好的例子。 这是std::move的签