How would one convert an inclinometers (Pitch, Yaw and Roll) into the gravitational pull expected on the system in [X,Y,Z] ? A system at rest in a certain Pitch, Yaw and Roll angle should be pulled to earth at a certain [X*g,Y*g,Z*g] , lets say this is for simulation purposes. I want to make a function whoose input is Pitch, Yaw and Roll and the output is a Vector3(X,Y,Z) of the downard moment
在[X,Y,Z]如何将倾角计（俯仰角，偏航角和俯仰角）转换为系统期望的引力？ 一个静止在特定俯仰角，偏航角和滚转角的系统应该以某个[X*g,Y*g,Z*g]角度拉到地球，假设这是为了模拟目的。 我想创建一个函数，输入是Pitch，Yaw和Roll，输出是向下时刻的Vector3(X,Y,Z) 。 意思是一个物体在静止时向下返回，会从加速度计输出[0,-1,0]和[pitch,yaw,roll]->[0,-1,0] ，其中[0,-1,0]减去[0,-1,0]导致[0,0,0] 。 或者如果我们以1
I have a simulation with multiple circles moving in 2D space, with elastic collisions between them. I'd like to add an attraction force between particles, so that particles move towards other particles depending on mass, etc. How would I go about this? My collision management function looks like this: void manageCollision(Particle particleA, Particle particleB) { float distanceX = pa
我有一个在二维空间中移动多个圆的模拟，它们之间有弹性碰撞。 我想在粒子之间添加吸引力，以便粒子根据质量等向其他粒子移动。我该如何去做这件事？ 我的碰撞管理功能如下所示： void manageCollision(Particle particleA, Particle particleB) { float distanceX = particleA.Position.X - particleB.Position.X; float distanceY = particleA.Position.Y - particleB.Position.Y; double collisionAngle = Ma
In my web.config I have: <system.diagnostics> <switches> <add name="logLevelSwitch" value="1" /> </switches> </system.diagnostics> Is there a way that I could call, for example: System.Diagnostics.TraceSwitch["logLevelSwitch"] to get the current value? Once you've defined the switch value in your web.config file, it's easy to get this
在我的web.config有： <system.diagnostics> <switches> <add name="logLevelSwitch" value="1" /> </switches> </system.diagnostics> 有没有我可以打电话的方式，例如： System.Diagnostics.TraceSwitch["logLevelSwitch"]获取当前值？ 一旦在web.config文件中定义了开关值，通过创建具有相同名称的TraceSwitch很容易从应用程序获取该值： private static TraceSwitch
I know that attributes are extremely useful. There are some predefined ones such as [Browsable(false)] which allows you to hide properties in the properties tab. Here is a good question explaining attributes: What are attributes in .NET? What are the predefined attributes (and their namespace) you actually use in your projects? [DebuggerDisplay] can be really helpful to quickly see customiz
我知道属性非常有用。 有一些预定义的例如[Browsable(false)] ，它允许您隐藏属性选项卡中的属性。 这是一个很好的解释属性的问题：什么是.NET中的属性？ 什么是您在项目中实际使用的预定义属性（及其名称空间）？ [DebuggerDisplay]对于在调试过程中将鼠标悬停在类型实例上时可以快速查看Type的自定义输出。 例： [DebuggerDisplay("FirstName={FirstName}, LastName={LastName}")] class Customer { public string
This question already has an answer here: XML Serialization - Disable rendering root element of array 3 answers Deserializing into a List without a container element in XML 1 answer You do not need to use serialize. Instead use xml linq : using System.Linq; using System.Text; using System.Xml; using System.Xml.Linq; using System.IO; using System.Net; namespace ConsoleApplication73 {
这个问题在这里已经有了答案： XML序列化 - 禁用数组3的根元素 反序列化到XML 1中没有容器元素的List中的答案 你不需要使用序列化。 而是使用xml linq： using System.Linq; using System.Text; using System.Xml; using System.Xml.Linq; using System.IO; using System.Net; namespace ConsoleApplication73 { class Program { const string FILENAME = @"c:temptest.xml"; static void Main
When serializing a flat List (ie with XmlElement-Attribute) and IsNullable=true, the output doesn't have the xsi:nil="true" entry if the List is null. [System.Xml.Serialization.XmlElement(IsNullable = true)] public List<OrdinanceValueType> ordinance { get { return this.ordinanceField; } set { this.ordinanceField = value; } } With XmlA
在序列化扁平List（即使用XmlElement-Attribute）和IsNullable = true时，如果List为null，则输出不具有xsi：nil =“true”条目。 [System.Xml.Serialization.XmlElement(IsNullable = true)] public List<OrdinanceValueType> ordinance { get { return this.ordinanceField; } set { this.ordinanceField = value; } } 使用XmlArray-Attribute，它可以工作，但列表不再平坦。
I'm trying to create a class that can be serialized into XML via the XMLSerializer. Destination XML should look something like this <subject_datas type="array"> <subject_data> ... </subject_data> <subject_data> ... </subject_data> </subject_datas> The problem is the type attribute for the subject_datas tag. What i
我试图创建一个可以通过XMLSerializer序列化为XML的类。 目标XML应该看起来像这样 <subject_datas type="array"> <subject_data> ... </subject_data> <subject_data> ... </subject_data> </subject_datas> 问题是subject_datas标签的type属性。 我所尝试的是将其设计为派生List，并使用这样的XMLAttribute属性附加属性 [XmlRoot(ElementName
How to extend XmlAttribute class? Using the below code, I've made my nullable property to be serializable and gets excluded from serialization if there is no value: [XmlIgnore] public DateTime? LastUpdated { get; set; } [XmlAttribute("lastUpdated")] public DateTime LastUpdatedSerializable { get { return this.LastUpdated.Value; } set
如何扩展XmlAttribute类？ 使用下面的代码，我已将可空属性设置为可序列化，并在没有值的情况下从序列化中排除： [XmlIgnore] public DateTime? LastUpdated { get; set; } [XmlAttribute("lastUpdated")] public DateTime LastUpdatedSerializable { get { return this.LastUpdated.Value; } set { this.LastUpdated = value; } } public bool S
I have a class with numerous Nullable<T> properties which I want to be serializable to XML as attributes. This is apparently a no-no as they are considered 'complex types'. So, instead I implement the *Specified pattern, where I create an addition *Value and *Specified property as follows: [XmlIgnore] public int? Age { get { return this.age; } set { this.age = value; } }
我有一个有很多Nullable <T>属性的类，我想将它们序列化为XML作为属性。 这显然是一个“不”，因为它们被认为是“复杂类型”。 所以，相反，我实现了* Specified模式，在这里我创建了一个* Value和* Specified属性，如下所示： [XmlIgnore] public int? Age { get { return this.age; } set { this.age = value; } } [XmlAttribute("Age")] public int AgeValue { get { return this.age.Value; } set { t
This is one i struggled with for ages so thought I'd document somewhere. (Apologies for asking and answering a question.) (C# .net 2.0) I had a class that was being serialized by XmlSerializer, I added a new public property however it wasn't being included in the output XML. It's not mentioned in the docs anywhere I could find, but public properties must have a set as well as a g
这是我奋斗了一段时间，所以认为我会记录在某个地方。 （请求和回答问题的道歉。） （C＃.net 2.0）我有一个正在被XmlSerializer序列化的类，我添加了一个新的公共属性，但它没有被包含在输出XML中。 在我能找到的任何文档中都没有提到它，但公共属性必须有一个集合以及一个可序列化的集合！ 我想这是因为它假设如果你要序列化，那么你会想从同一个文件反序列化，所以只能序列化具有set和get的属性。 如前所述，大多数房