I'm want to use a Regex to split long string for seperated lines. Line can include any possible unicode character. Line is "ending" on dot ("." - one or more) or on new line ("n"). Example: This string will be the input: "line1. line2.. line3... line4.... line5..... line6 n line7" The output: "line1." "line2.." "line3...&quo
我想用正则表达式来分隔长字符串的分隔线。 行可以包含任何可能的unicode字符。 线在点（“。” - 一个或多个）或换行（“ n”）上“结束”。 例： 这个字符串将是输入： "line1. line2.. line3... line4.... line5..... line6 n line7" 输出： “一号线”。 “2号线。” “3号线......” “4号线......” “LINE5 .....” “LINE6” “line7” 如果我明白你的要求，你可以尝试一下这样的模式： (?<=.)(?!.)|n 这会将字
im just going to dive straight in and give you a little background on what im trying to do, what i've tried, and the obstacles in my way. so here goes.. MY GOAL To post to a facebook profile or wall from a desktop application. The desktop application will be used by individual users who have their own facebook account. The aim is to create each user their own facebook app and get the
即时通讯只是直接介入，给你一些关于我试图做什么，试过了什么，以及我的方式的障碍的背景知识。 所以在这里.. 我的目标 从桌面应用程序发布到Facebook个人资料或墙上。 桌面应用程序将由拥有自己的Facebook帐户的个人用户使用。 目标是为每个用户创建他们自己的Facebook应用程序，并获取应用程序ID和应用程序秘密。 然后在桌面应用程序中使用应用程序ID和应用程序密码（保存在数据库或配置中的某个位置），以允许桌
Is there a way in Java to get a method to lock (mutex) the object which it is in? I know this sounds confusing but basically I wan't an equivelent to this snippet of C# but in Java. lock(this) { // Some code here... } I've been tasked with reimplementing an API written in .Net into Java, and I've been asked to keep the Java version as similar to the .Net version as humanly pos
Java中有没有办法让方法锁定（互斥）它所在的对象？ 我知道这听起来令人困惑，但基本上我不想与这个C＃代码片段相等，而是使用Java。 lock(this) { // Some code here... } 我的任务是将以.Net编写的API重新实现为Java，并且我被要求保持Java版本与.Net版本类似于人类可能的版本。 这并不是因为.Net版本看起来像是从我无法访问的C ++版本转录而来的。 无论如何，上面的行出现在C＃版本中，我需要一些在Java中做相同的
I have an image in a memory stream and I want to write this to an MS Excel document, the PIA only exposes the AddPicture method which takes a file path. Is there away to add a picture without having to write the image to disc? MSDN http://msdn.microsoft.com/en-us/library/microsoft.office.interop.excel.shapes.addpicture(v=office.14).aspx Well, a bit of blind flying but assuming a thing or
我有一个内存流中的图像，我想将它写入MS Excel文档，PIA只公开了带有文件路径的AddPicture方法。 是否需要添加图片而不必将图像写入光盘？ MSDN http://msdn.microsoft.com/en-us/library/microsoft.office.interop.excel.shapes.addpicture(v=office.14).aspx 好吧，盲目飞行，但假设你的代码有一两件事（例如你的流的来源，数据类型等），这可能是一个解决方案： 首先，您需要从流中创建位图图像数据（我假设它是一
I'm trying to upload an image through a multipart/form-data post and I'm using the code below. I'm only going to be uploading .jpg images. The problem is that the image that is saved is not a valid image and it can't be viewed. It's also 200 bytes larger than the file I'm uploading so I assume I'm missing something here? public class FileUploadController : ApiCont
我试图通过multipart/form-data文章上传图片，并使用下面的代码。 我只会上传.jpg图片。 问题是保存的图像不是有效的图像，无法查看。 它比我上传的文件大200字节，所以我假设我在这里错过了一些东西？ public class FileUploadController : ApiController { public Task<HttpResponseMessage> PostUploadFile() { return UploadFileAsync().ContinueWith<HttpResponseMessage>((tsk) =>
This question already has an answer here: Case insensitive 'Contains(string)' 22 answers There is no string.Contains() method that takes a StringComparison . Most people end up using an IndexOf() call for this purpose.
这个问题在这里已经有了答案： 不区分大小写'包含（字符串）'22个答案 没有string.Contains()方法需要StringComparison 。 大多数人最终会为此使用IndexOf()调用。
This question already has an answer here: Case insensitive 'Contains(string)' 22 answers Let's say there is a boolean property CaseSensitive identifying the search mode. Then you can use string.IndexOf to solve this by setting the StringComparison correctly: StringComparison comparison = CaseSensitive ? StringComparison.CurrentCulture : StringComparison.CurrentCultureIgnoreC
这个问题在这里已经有了答案： 不区分大小写'包含（字符串）'22个答案 假设有一个布尔属性CaseSensitive标识搜索模式。 然后你可以使用string.IndexOf来正确设置StringComparison来解决这个问题： StringComparison comparison = CaseSensitive ? StringComparison.CurrentCulture : StringComparison.CurrentCultureIgnoreCase; if (value.Value.IndexOf(txtFilterValue.Text, comparison) >= 0) { //R
This question already has an answer here: Case insensitive 'Contains(string)' 22 answers If your search is case-sensitive, you can use Contains : var name = "John Smith"; if(name.Contains("John")) { // Name contains John } Or, to get all the names that contain John: var names = new string[] {"John Smith", "Bob Smith", "Frank"}; var results = names.Where(n => n.Contains("John"
这个问题在这里已经有了答案： 不区分大小写'包含（字符串）'22个答案 如果您的搜索区分大小写，则可以使用Contains ： var name = "John Smith"; if(name.Contains("John")) { // Name contains John } 或者，要获取包含John的所有名称： var names = new string[] {"John Smith", "Bob Smith", "Frank"}; var results = names.Where(n => n.Contains("John")); 如果你想忽略大小写，你可以将这两个字符
This question already has an answer here: Case insensitive 'Contains(string)' 22 answers myList = myList.Where(m => m.Name.ToLowerInvariant().Contains("John".ToLowerInvariant())); You can convert all into lower case filter like IQueryable<MyModel> myList = GetListMyModel().AsQueryable(); myList = myList.Where(m => m.Name.ToLower().Contains("John".ToLower()); Or use IQue
这个问题在这里已经有了答案： 不区分大小写'包含（字符串）'22个答案 myList = myList.Where(m => m.Name.ToLowerInvariant().Contains("John".ToLowerInvariant())); 你可以将全部转换为小写过滤器 IQueryable<MyModel> myList = GetListMyModel().AsQueryable(); myList = myList.Where(m => m.Name.ToLower().Contains("John".ToLower()); 或者使用 IQueryable<MyModel> myList = GetListMy
This question already has an answer here: Case insensitive 'Contains(string)' 22 answers foods.Where(x => x.StartsWith("S", StringComparison.OrdinalIgnoreCase));如果您使用的是字符串对象的集合，则还可以使用StartsWith; food.StartsWith("s", StringComparison.OrdinalIgnoreCase);
这个问题在这里已经有了答案： 不区分大小写'包含（字符串）'22个答案 foods.Where(x => x.StartsWith("S", StringComparison.OrdinalIgnoreCase));如果您使用的是字符串对象的集合，则还可以使用StartsWith; food.StartsWith("s", StringComparison.OrdinalIgnoreCase);