I want to send send HashMap object to the applet that requested it. A servlet has that HashMap object. Is there a way I can do this ? Applet ------requests HashMap object---->Servlet listens to this request | | Servlet searches that HashMap Object
我想发送HashMap对象到请求它的小程序。 一个servlet具有该HashMap对象。 有什么办法可以做到这一点？ Applet ------requests HashMap object---->Servlet listens to this request | | Servlet searches that HashMap Object
I have been fiddling with this code fragment from past few hours but I am unable to understand how jQuery's autocomplete UI works. I followed this tutorial http://viralpatel.net/blogs/tutorial-create-autocomplete-feature-with-java-jsp-jquery/ I used same example but instead of sending request to a JSP, I used a servlet. The request reaches the servlet "Fetcher", it executes as wel
我一直在摆弄过去几个小时的代码片段，但我无法理解jQuery的自动完成UI如何工作。 我遵循本教程http://viralpatel.net/blogs/tutorial-create-autocomplete-feature-with-java-jsp-jquery/我使用了相同的示例，但不是向JSP发送请求，而是使用了一个servlet。 请求到达servlet“Fetcher”，它也会执行，但没有任何内容返回到页面。 这是代码。 public class Fetcher extends HttpServlet { [...] List<String> co
I am generating dynamic page using JSP, I want to save this dynamically generated complete page in file as archive. In JSP, everything is written to PrintWriter out = response.getWriter(); At the end of page, before sending response to client I want to save this page, either in file or in buffer as string for later treatment. How can I save Printwriter content or convert to String ? It wi
我正在使用JSP生成动态页面，我想将此动态生成的完整页面保存为文件文件。 在JSP中，所有内容都写入PrintWriter out = response.getWriter(); 在页面结尾处，在向客户端发送响应之前，我希望将此页面保存在文件或缓冲区中作为后续处理的字符串。 如何保存Printwriter内容或将其转换为String ？ 它将取决于：PrintWriter是如何构建和使用的。 如果PrintWriter构造为1st，然后传递给写入它的代码，则可以使用Decorator模
This question already has an answer here: How to use Servlets and Ajax? 7 answers How do you return a JSON object from a Java Servlet 10 answers
这个问题在这里已经有了答案： 如何使用Servlets和Ajax？ 7个答案 你如何从Java Servlet 10的答案中返回一个JSON对象
This question already has an answer here: How do you return a JSON object from a Java Servlet 10 answers its Very easy actually. Use Google gson.jar Either you download From Here Download Google GSON Jar OR add dependencies( if Your Project is Maven ) to your pom.xml <dependency> <groupId>com.google.code.gson</groupId> <artifactId>gson</artifactId>
这个问题在这里已经有了答案： 你如何从Java Servlet 10的答案中返回一个JSON对象 其实很简单。 使用谷歌gson.jar 要么你下载从这里下载谷歌GSON JAR 或添加依赖（ 如果你的项目是Maven的 ）添加到您pom.xml <dependency> <groupId>com.google.code.gson</groupId> <artifactId>gson</artifactId> <version>2.2.2</version> </dependency> 并尝试使用此链接
I would like to make a simple HTTP POST using JSON in Java. Let's say the URL is www.site.com and it takes in the value {"name":"myname","age":"20"} labeled as 'details' for example. How would I go about creating the syntax for the POST? I also can't seem to find a POST method in the JSON Javadocs. Here is what you need to do: Ge
我想在Java中使用JSON进行简单的HTTP POST。 假设网址是www.site.com 并且它取值为{"name":"myname","age":"20"} ，例如标记为'details' 。 我将如何去创建POST的语法？ 我似乎也无法在JSON Javadoc中找到POST方法。 这是你需要做的事情： 获取Apache HttpClient，这将使您能够提出所需的请求 用它创建一个HttpPost请求，并添加头“application / x-www-form-urle
I have to make a http Post request using a JSON string I already have generated. I tried different two different methods : 1.HttpURLConnection 2.HttpClient but I get the same "unwanted" result from both of them. My code so far with HttpURLConnection is: public static void SaveWorkflow() throws IOException { URL url = null; url = new URL(myURLgoeshere); HttpURLConnection
我必须使用已经生成的JSON字符串进行http Post请求。 我尝试了两种不同的方法： 1.HttpURLConnection 2.HttpClient 但是我得到了他们两个相同的“不想要的”结果。 到目前为止我的代码与HttpURLConnection是： public static void SaveWorkflow() throws IOException { URL url = null; url = new URL(myURLgoeshere); HttpURLConnection urlConn = null; urlConn = (HttpURLConnection) url.openConnection()
I need to send parameter in curl request but i don't about curl request. Request is: How to send it in java. curl --user xxx:xxxpass-H "Content-Type: application/json" -X POST -d '{"ImageId":"local", "ImageUrl":"http://www.gapcanada.ca/products/res/thumbimg/classic-fit-and-flare-dress-modern-red.jpg"}' http://000.00.00.00:8080/api Well, there are better ways of doing this, but if for s
我需要在curl request发送参数，但我不关于curl请求。 请求是：如何在java中发送它。 curl --user xxx:xxxpass-H "Content-Type: application/json" -X POST -d '{"ImageId":"local", "ImageUrl":"http://www.gapcanada.ca/products/res/thumbimg/classic-fit-and-flare-dress-modern-red.jpg"}' http://000.00.00.00:8080/api 那么，有更好的方法来做到这一点，但如果由于某种原因你真的想使用卷曲， Runtime.getRuntime
i'm looking for tutorial or quick example, how i can send POST data throw openStream. My code is: URL url = new URL("http://localhost:8080/test"); InputStream response = url.openStream(); BufferedReader reader = new BufferedReader(new InputStreamReader(response, "UTF-8")); Could you help me ? URL url = new URL(urlSpec); HttpURLConnection connection = (Http
我正在寻找教程或快速示例，我如何发送POST数据扔openStream。 我的代码是： URL url = new URL("http://localhost:8080/test"); InputStream response = url.openStream(); BufferedReader reader = new BufferedReader(new InputStreamReader(response, "UTF-8")); 你可以帮帮我吗 ？ URL url = new URL(urlSpec); HttpURLConnection connection = (HttpURLConnection) url.openConnectio
I'm trying to follow the answer to THAT question But it seems that classes are not included with the default Android package since for that code: File file = new File("FileToSend.txt"); HttpClient client = new HttpClient(); String url = "http://www.yourdomain.com/destination.php"; PostMethod postMethod = new PostMethod(url); Part[] parts = {new FilePart(file.getName(), file)}; postMethod
我试图按照这个问题的答案 但是，由于该代码，似乎这些类不包含在默认的Android包中： File file = new File("FileToSend.txt"); HttpClient client = new HttpClient(); String url = "http://www.yourdomain.com/destination.php"; PostMethod postMethod = new PostMethod(url); Part[] parts = {new FilePart(file.getName(), file)}; postMethod.setParameter("name", "value"); // set parameters like this instead i