Class definitions deriving from object

Possible Duplicate: Old style and new style classes in Python python class inherits object What's the difference between class foo: and class foo(object): Can anyone explain why we are using object in class definition? In Python 2.x the first declaration is an old-style class and the second version is a new-style class. You should always use new-style classes for new code. In

从对象派生的类定义

可能重复: Python中的旧式和新式样类 python类继承对象 有什么区别 class foo: 和 class foo(object): 任何人都可以解释为什么我们在类定义中使用对象吗? 在Python 2.x中,第一个声明是旧式类,第二个是新式类。 你应该总是为新代码使用新风格的类。 在Python 3中,所有类都是新式的,所以没有区别。

Python class definition with (object)

This question already has an answer here: What is the difference between old style and new style classes in Python? 9 answers Python class inherits object 7 answers

Python类定义(对象)

这个问题在这里已经有了答案: Python中的旧风格和新风格类有什么区别? 9个答案 Python类继承对象7的答案

Class definition parameter vs. Normal class definition

This question already has an answer here: What is the difference between old style and new style classes in Python? 9 answers In Python 2, the former is a "new-style class" and the latter is an "old-style class" that only exists for backwards compatibility. You should never use the latter for anything new. In Python 3, I believe there is no difference at all. You can

类定义参数与普通类定义

这个问题在这里已经有了答案: Python中的旧风格和新风格类有什么区别? 9个答案 在Python 2中,前者是一种“新式类”,后者则是只存在于后向兼容性中的“旧式类”。 你不应该使用后者来获得新的东西。 在Python 3中,我相信完全没有区别。 你甚至可以完全舍弃括号。 用两个词: # new style class Car(object): pass “新建类”是在现代Python中创建类的推荐方式。 # classic style class Car(): pass “Classi

Where is

This question already has an answer here: What is the difference between old style and new style classes in Python? 9 answers Python class inherits object 7 answers In Python 3, if you create a class without adding a parent class it automatically inherits from object. You can't create old style classes anymore like Python 2. Example: class A: # gets defaulted to class A(object):

哪里

这个问题在这里已经有了答案: Python中的旧风格和新风格类有什么区别? 9个答案 Python类继承对象7的答案 在Python 3中,如果您创建的类没有添加父类,它会自动从对象继承。 你不能再像Python 2那样创建旧的风格类。 例: class A: # gets defaulted to class A(object): pass 您可以从mro中看到,Python3中的所有类都是object子类: >>> class A: pass ... >>> A.__mro__ (<class '__ma

style and new

Possible Duplicate: Old style and new style classes in Python What is the current state of affairs with new-style and old-style classes in Python 2.7? I don't work with Python often but I vaguely remember the issue. The documentation doesn't seem to mention the issue at all: The Python Tutorial: Classes. Do I still need to worry about this? In general should I declare my classes l

风格和新

可能重复: Python中的旧式和新式样类 Python 2.7中的新式和旧式类的当前状况如何? 我经常不使用Python,但我依稀记得这个问题。 文档似乎没有提到这个问题:Python教程:类。 我仍然需要担心这个吗? 一般来说,我应该宣布我的课程如下: class MyClass: pass 要么? class MyClass(object): pass 始终子类“对象”。 那些是新式的课程。 你已经准备好了python 3。 像.super()这样的.super()正常工作,

Python: Decorated staticmethod receives non

I'm having a little problem decorating a static method in Python. I think the following code best represents my problem: def decorator(func): print callable(func) return func class Foo(): @decorator @staticmethod def bar(): return # outputs False print callable(Foo.bar) # outputs True This seems to be a bug. I imagine it arises because when the method Foo.b

Python:装饰的静态方法接收非

我在Python中修饰静态方法时遇到了一些问题。 我认为以下代码最能代表我的问题: def decorator(func): print callable(func) return func class Foo(): @decorator @staticmethod def bar(): return # outputs False print callable(Foo.bar) # outputs True 这似乎是一个错误。 我想它的出现是因为当方法Foo.bar传递给装饰器时,它是一个函数,而不是一个方法。 这是我看到它不可调用的

How was the syntax chosen for static methods in Python?

I've been working with Python for a while and I find the syntax for declaring methods as static to be peculiar. A regular method would be declared: def mymethod(self, params) ... return A static method is declared: def mystaticethod(params) ... return mystaticmethod = staticmethod(mystaticmethod) If you don't add the static method line, the compiler complains about self

在Python中为静态方法选择的语法如何?

我一直在使用Python一段时间,我发现将方法声明为静态的语法是特殊的。 将会声明一个常规方法: def mymethod(self, params) ... return 声明了一个静态方法: def mystaticethod(params) ... return mystaticmethod = staticmethod(mystaticmethod) 如果你不添加静态方法行,编译器会抱怨自己失踪。 这是一种非常简单的非常复杂的方式,在其他语言中只需使用关键字和声明语法即可。 任何人都可以告诉我这

How to find the most common words using spacy?

I'm using spacy with python and its working fine for tagging each word but I was wondering if it was possible to find the most common words in a string. Also is it possible to get the most common nouns, verbs, adverbs and so on? There's a count_by function included but I cant seem to get it to run in any meaningful way. This should look basically the same as counting anything else in

如何使用spacy找到最常用的单词?

我使用Python的spacy和它的工作正常标记每个单词,但我想知道是否有可能找到一个字符串中最常见的单词。 还有可能获得最常见的名词,动词,副词等吗? 有一个count_by函数,但我似乎无法让它以任何有意义的方式运行。 这看起来应该和Python中的其他任何东西一样。 spaCy允许您迭代文档,并返回一系列令牌对象。 这些可用于访问注释。 from __future__ import print_function, unicode_literals import spacy from collect

Something like django signals in Odoo

Am looking for some mechanism that allows me to hook a python function to the triggering of a database event (insert, update, delete) of ANY model in Odoo. I have worked with Django signals and am wondering if Odoo has something like that. Thanks in advance. EDITED What i want to do is to execute a python code when a database event occurs. In django it would be from django.db.models.signa

像Odoo中的django信号

我正在寻找一些机制,允许我将一个python函数挂钩到触发Odoo中任何模型的数据库事件(插入,更新,删除)。 我曾与Django的信号,我想知道如果Odoo有这样的事情。 提前致谢。 EDITED 我想要做的是在数据库事件发生时执行python代码。 在Django中,它会是 from django.db.models.signals import post_save from django.dispatch import receiver @receiver(post_save) def post_save_receiver(sender, instance, created,

Saving django model instance into another model

I have 2 models that inherit from an abstract model. I am using one for relevant data and the other one for archived data. They have the same fields and methods. I would like to create a post_save signal on model A so an instance will be created in model B whenever a new record is created, so far the options out there are not very elegant: a = A.objects.get(id=1) b = B() model_dict = a.__dict

将django模型实例保存到另一个模型中

我有2个模型从一个抽象模型继承。 我使用一个用于相关数据,另一个用于存档数据。 他们有相同的领域和方法。 我想在模型A上创建post_save信号,因此无论何时创建新记录,都会在模型B中创建一个实例,到目前为止,选项并不十分优雅: a = A.objects.get(id=1) b = B() model_dict = a.__dict__ model_dict.pop('id') b.__dict__ = model_dict b.save() 有没有更好的方法来实现这一目标? 注:这些模型包含外键,因此,djan