Is there any difference between cpython and python

This question already has an answer here: Python vs Cpython 10 answers Python is a language. CPython is the default byte-code interpreter of Python, which is written in C. There is also other implementation of Python such as IronPython (for .NET), Jython (for Java), etc. CPython is Guido van Rossum 's reference version of the Python computing language. It's most often called si

cpython和python有什么区别吗?

这个问题在这里已经有了答案: Python与Cpython 10的答案 Python是一种语言。 CPython是Python的默认字节码解释器,用C语言编写。 还有其他的Python实现,比如IronPython(用于.NET),Jython(用于Java)等。 CPython是Guido van Rossum的Python计算语言的参考版本。 它通常被简称为“Python”; 演讲者说“CPython”通常将其与其他实现明确区分开来。

Python expose to scope

Let's consider we have a module called mod which has a function func . I want to import the module and run func, exposing a variable var to its scope. a.func() # and func can do stuff with var How can i do this? 您可以将var定义到的模块导入您的mod模块,或者将var作为参数传递给func() 。 Pass the variable to the function. Works the same across modules as it does in a single module. # modul

Python暴露于范围

让我们考虑一下我们有一个叫mod的模块,它有一个函数func 。 我想导入模块并运行func,将变量var暴露给它的作用域。 a.func() # and func can do stuff with var 我怎样才能做到这一点? 您可以将var定义到的模块导入您的mod模块,或者将var作为参数传递给func() 。 将变量传递给函数。 在模块中工作与在单个模块中一样。 # module a def func(v): print v # module b import a var=42 a.func(var) 如果您需要修改

Use return value of a function

I started programing recently, and I started with python. My question is: how can I use a result of a function in an another function ? def eklid(p, a, b,): x = [1, 0] y = [0, 1] r = [a, b] q = [0] n = 0 while r[n+1] != 0: q.append(r[n] // r[n+1]) r.append(r[n] % r[n+1]) x.append(x[n] - x[n+1] * q[n+1]) y.append(y[n] - y[n+1] * q[n+1])

使用函数的返回值

我最近开始编程,并开始使用python。 我的问题是:如何在另一个函数中使用函数的结果? def eklid(p, a, b,): x = [1, 0] y = [0, 1] r = [a, b] q = [0] n = 0 while r[n+1] != 0: q.append(r[n] // r[n+1]) r.append(r[n] % r[n+1]) x.append(x[n] - x[n+1] * q[n+1]) y.append(y[n] - y[n+1] * q[n+1]) if p == 0: print(r[n], "=", r[n+1],

Triangle in python

I have problems with my program that I have to do... here are the instructions: Write a program named triangle.py that uses a value-returning function that takes the lengths of the sides of a triangle as arguments and returns both the area and perimeter of the triangle. Prompt the user to enter the side lengths from the keyboard in the main function and then call the second function. Display th

python中的三角形

我有我的程序有问题,我必须做...这里是说明:编写一个名为triangle.py的程序,该程序使用一个返回值函数,该函数将三角形边的长度作为参数,并返回区域和三角形的周长。 提示用户在主功能键盘上输入边长,然后调用第二个功能。 将区域和周边显示精确到小数点后一位。 注意:使用Heron的公式来查找区域。 我做到了,但它的工作原理是他希望我们使用一个函数返回面积和周长..所以我重新做了一个函数的程序,但我不断收到一个

Python: how to avoid writing numerous if/elifs in a function?

I've written a function that performs as a calculator. It works for the variables below. However I want to scale it up to handle 15 different levels values, and 15 different sales and cost values. The function would apply different sales and cost calculations per level as below. (In that each calculation applies to a particular level, the calculations could potentially be defined outside

Python:如何避免在函数中编写多个if / elifs?

我写了一个函数,可以作为一个计算器。 它适用于下面的变量。 不过,我想要扩展它以处理15个不同的levels值,以及15个不同的sales和cost值。 该功能将按照以下级别应用不同的销售和成本计算。 (因为每个计算都适用于特定级别,所以可能会在函数外部定义计算。) 我可以为15个关卡中的每一个编写大量的if / elif语句,但这看起来并不是Pythonic。 有没有一种方法可以通过编程来扩展这样一个功能,以获得更多的销售额,等

How to return multiple values from *args?

I have a hello function and it takes n arguments (see below code). def hello(*args): # return values I want to return multiple values from *args . How to do it? For example: d, e, f = hello(a, b, c) SOLUTION: def hello(*args): values = {} # values rst = [] # result for arg in args: rst.append(values[arg]) return rst a, b, c = hello('d', 'e', f) a, b = hello('d', 'f') Just r

如何从* args返回多个值?

我有一个hello函数,它需要n个参数(见下面的代码)。 def hello(*args): # return values 我想从*args返回多个值。 怎么做? 例如: d, e, f = hello(a, b, c) 解: def hello(*args): values = {} # values rst = [] # result for arg in args: rst.append(values[arg]) return rst a, b, c = hello('d', 'e', f) a, b = hello('d', 'f') 只是返回列表。 :):D 所以,你想要返回一个长度与args相同

Loop calculations in Python

This question already has an answer here: How do you return multiple values in Python? 13 answers A return statement (if present) is the last statement that gets executed in a function. So, as soon as it returns the value for the female category, the control exits the function. Since your return statement is inside the for loop, the next category doesn't get processed. You can move th

在Python中循环计算

这个问题在这里已经有了答案: 你如何在Python中返回多个值? 13个答案 返回语句(如果存在)是在函数中执行的最后一个语句。 所以,只要它返回女性类别的值,控制就退出该功能。 由于你的return语句在for循环中,所以下一个类不会被处理。 您可以将回车移到for循环外部,并有一个列表来存储您想要返回的每个值。

what I should change in this code to return two lists?

This question already has an answer here: How do you return multiple values in Python? 13 answers Change the last part of your program in the following way: for tokens in token: if tokens in words_to_match: positive_tokens.append(tokens) if tokens in words_to_match2: negative_tokens.append(tokens) return (positive_tokens, negative_tokens) this will return a tuple wi

在这段代码中我应该改变什么来返回两个列表?

这个问题在这里已经有了答案: 你如何在Python中返回多个值? 13个答案 按以下方式更改程序的最后部分: for tokens in token: if tokens in words_to_match: positive_tokens.append(tokens) if tokens in words_to_match2: negative_tokens.append(tokens) return (positive_tokens, negative_tokens) 这将返回一个包含两个元素的元组。 你这样使用它: (positive_tokens, negative_tokens) =

How to pass variables in and out of functions in Python

This question already has an answer here: How do you return multiple values in Python? 13 answers 你可以利用kwargs来解压命名变量def foo(**kwargs): kwargs['var1'] = do_something(kwargs['var1']) ... return kwargs If you find yourself writing a lot of functions that act on the same data, one better way would be using classes to contain your data. class Thing: def __init__(self,

如何在Python中传入和传出函数中的变量

这个问题在这里已经有了答案: 你如何在Python中返回多个值? 13个答案 你可以利用kwargs来解压命名变量def foo(**kwargs): kwargs['var1'] = do_something(kwargs['var1']) ... return kwargs 如果您发现自己编写了许多对相同数据起作用的函数,则更好的方法是使用类来包含您的数据。 class Thing: def __init__(self, a, b, c): var_1 = a var_2 = b var_3 = c # you can t

Pythonic way to return a boolean value and a message

This question already has an answer here: How do you return multiple values in Python? 13 answers An empty string in Python is "falsey", so it's somewhat redundant to return (False, ''). I might do this instead: def processGroupFound(): if _isProcessRunning('ps auwxx | grep duplicity'): return 'Duplicity' elif _isProcessRunning('who | grep pts'):

Pythonic方式返回布尔值和消息

这个问题在这里已经有了答案: 你如何在Python中返回多个值? 13个答案 Python中的空字符串“falsey”,所以返回有点多余(False,'')。 我可能会这样做: def processGroupFound(): if _isProcessRunning('ps auwxx | grep duplicity'): return 'Duplicity' elif _isProcessRunning('who | grep pts'): return 'SSH' elif _isProcessRunning('netstat -na | grep ESTA | grep 5901'):