I have a tuple of tuples from a MySQL query like this: T1 = (('13', '17', '18', '21', '32'), ('07', '11', '13', '14', '28'), ('01', '05', '06', '08', '15', '16')) I'd like to convert all the string elements into integers and put them back into a list of lists: T2 = [[13, 17, 18, 21, 32], [7, 11, 13, 14, 28], [1, 5, 6, 8, 15, 16]] I tried to achieve it with eval but didn't
我有一个像这样的MySQL查询的元组元组： T1 = (('13', '17', '18', '21', '32'), ('07', '11', '13', '14', '28'), ('01', '05', '06', '08', '15', '16')) 我想将所有字符串元素转换为整数，并将它们放回列表中： T2 = [[13, 17, 18, 21, 32], [7, 11, 13, 14, 28], [1, 5, 6, 8, 15, 16]] 我试图用eval来实现它，但还没有得到任何体面的结果。 int()是Python标准内置函数，用于将字符串转换为整数值。 你用
In the Python console, when I type: >>> "n".join(['I', 'would', 'expect', 'multiple', 'lines']) Gives: 'Inwouldnexpectnmultiplenlines' Though I'd expect to see such an output: I would expect multiple lines What am I missing here? The console is printing the representation, not the string itself. If you prefix with print , you'll get what you expect. See this question
在Python控制台中，当我键入： >>> "n".join(['I', 'would', 'expect', 'multiple', 'lines']) 得到： 'Inwouldnexpectnmultiplenlines' 虽然我期望看到这样的输出： I would expect multiple lines 我在这里错过了什么？ 控制台打印表示，而不是字符串本身。 如果你print前缀，你会得到你所期望的。 有关字符串与字符串表示之间的区别的详细信息，请参阅此问题。 超级简化的表示形式就是您在源代码中输入
I have extracted some data from a file and want to write it to a second file. But my program is returning the error: sequence item 1: expected string, list found This appears to be happening because write() wants a string but it is receiving a list. So, with respect to this code, how can I convert the list buffer to a string so that I can save the contents of buffer to file2 ? file = open('
我已经从文件中提取了一些数据，并希望将其写入第二个文件。 但我的程序正在返回错误： sequence item 1: expected string, list found 这似乎正在发生，因为write()一个字符串，但它正在接收一个列表。 所以，就这段代码而言，我如何将列表buffer转换为字符串，以便将buffer的内容保存到file2 ？ file = open('file1.txt','r') file2 = open('file2.txt','w') buffer = [] rec = file.readlines() for line in rec : f
I have written the function below that converts underscore to camelcase with first word in lowercase, ie "get_this_value" -> "getThisValue". Also I have requirement to preserve leading and trailing underscores and also double (triple etc.) underscores, if any, ie "_get__this_value_" -> "_get_ThisValue_". The code: def underscore_to_camelcase(value): output = ""
我写了下面的函数，它将下划线转换为camelcase，第一个单词是小写，即“get_this_value” - >“getThisValue”。 此外，我还要求保留前导和尾部下划线，并且还需要双（下划线等）下划线，如果有的话，也就是说 "_get__this_value_" -> "_get_ThisValue_". 代码： def underscore_to_camelcase(value): output = "" first_word_passed = False for word in value.split("_"): if not word:
I am using the following class to easily store data of my songs. class Song: """The class to store the details of each song""" attsToStore=('Name', 'Artist', 'Album', 'Genre', 'Location') def __init__(self): for att in self.attsToStore: exec 'self.%s=None'%(att.lower()) in locals() def setDetail(self, key, val): if key in self.attsToStore:
我使用以下课程轻松存储我的歌曲数据。 class Song: """The class to store the details of each song""" attsToStore=('Name', 'Artist', 'Album', 'Genre', 'Location') def __init__(self): for att in self.attsToStore: exec 'self.%s=None'%(att.lower()) in locals() def setDetail(self, key, val): if key in self.attsToStore: exec 'self.%s=val'%(key.lowe
I have a list of tuples like this: [(a,3), (b, 4), (c, 5), (d, 1), (e,2)] and I'd like to extract a list like this from it: [3, 4, 5, 1, 2] How would I go about this? I haven't been able to figure out how to do it. Readability is secondary to speed in this context, as this code will be tucked away in a relatively well commented function. If goal is efficiency, let's look at t
我有一个这样的元组列表： [(a,3), (b, 4), (c, 5), (d, 1), (e,2)] 我想从中提取一个像这样的列表： [3, 4, 5, 1, 2] 我将如何去做这件事？ 我一直无法弄清楚如何去做。 在这种情况下，可读性对于速度来说是次要的，因为这些代码将被隐藏在相对良好的评论函数中。 如果目标是效率，让我们看看不同的方法： from timeit import timeit from operator import itemgetter T = [('a',3), ('b', 4), ('c', 5), ('d', 1), (
I've got one dict from an api: initial_dict = { "content": { "text": }, "meta": { "title": "something", "created": "2016-03-04 15:30", "author": "Pete", "extra": { "a": 123, "b": 456 } } } and I need to map this to another dict: new_dict = { "content_text": initial_dict['content']['text'], "meta
我从api得到了一个字典： initial_dict = { "content": { "text": }, "meta": { "title": "something", "created": "2016-03-04 15:30", "author": "Pete", "extra": { "a": 123, "b": 456 } } } 我需要将其映射到另一个字典： new_dict = { "content_text": initial_dict['content']['text'], "meta_title": initial_dict[
Here is the sample code1 and its result. d ={ "name":"looser", "roll":6666, "profile" : "developer" } print("list formatted dict is {}".format([d])) for k,v in [d.items()]: if d[k] is "developer": d.pop(k) else: print(k) result: list formatted dict is [{'name': 'looser', 'roll': 6666, 'profile': 'developer'}] Traceback (most recent call last): File "/Use
以下是示例代码1及其结果。 d ={ "name":"looser", "roll":6666, "profile" : "developer" } print("list formatted dict is {}".format([d])) for k,v in [d.items()]: if d[k] is "developer": d.pop(k) else: print(k) 结果： list formatted dict is [{'name': 'looser', 'roll': 6666, 'profile': 'developer'}] Traceback (most recent call last): File "/Users/rough/try.py"
I have this code in ruby: class Package def initialize(name) @name = name @elements = [] end [:type, :block].each do |bindtype| define_method "get_#{bindtype}_by_name" do |name| get_by_name(name, bindtype) end end def get_by_name(name, bindtype=nil) @elements.each do |element| return if element.name == name end return nil end I've read this que
我在ruby中有这样的代码： class Package def initialize(name) @name = name @elements = [] end [:type, :block].each do |bindtype| define_method "get_#{bindtype}_by_name" do |name| get_by_name(name, bindtype) end end def get_by_name(name, bindtype=nil) @elements.each do |element| return if element.name == name end return nil end 我已经阅读了关于python
I have a line of code like this: list1=[string1[i:i+int1] for i in range(0, len(string1), int1)] I remember my teacher saying that we should start new lines when there is 'for' so, is there a way to write this code that looks like: for i in range(0, len(string1), int1): #something here or something else? You mean to extract a boring old regular for loop from a list-comprehension
我有这样的一行代码： list1=[string1[i:i+int1] for i in range(0, len(string1), int1)] 我记得我的老师说我们应该在有'for'的时候开始新行，那么有没有办法编写这样的代码： for i in range(0, len(string1), int1): #something here 或者是其他东西？ 你的意思是从list-comprehension提取一个无聊的旧规则for loop ？ list1=[string1[i:i+int1] for i in range(0, len(string1), int1)] 变为： list1 =