import sys print (sys.platform) print (2 ** 100) raw_input( ) I am using Python 3.1 and can't get the raw_input to "freeze" the dos pop-up. The book I'm reading is for 2.5 and I'm using 3.1 What should I do to fix this? raw_input() was renamed to input() From http://docs.python.org/dev/py3k/whatsnew/3.0.html 这适用于Python 3.x和2.x： # Fix Python 2.x. try: input = ra
import sys print (sys.platform) print (2 ** 100) raw_input( ) 我正在使用Python 3.1，无法获取raw_input来“冻结”dos弹出窗口。 我正在阅读的书是2.5，而我正在使用3.1 我应该怎么做才能解决这个问题？ raw_input()被重命名为input() 从http://docs.python.org/dev/py3k/whatsnew/3.0.html 这适用于Python 3.x和2.x： # Fix Python 2.x. try: input = raw_input except NameError: pass print("Hi " + input("Say some
是否有可能终止正在运行的线程而不设置/检查任何标志/信号/等等？ It is generally a bad pattern to kill a thread abruptly, in Python and in any language. Think of the following cases: the thread is holding a critical resource that must be closed properly the thread has created several other threads that must be killed as well. The nice way of handling this if you can afford it (if you are mana
是否有可能终止正在运行的线程而不设置/检查任何标志/信号/等等？ 在Python和任何语言中，突然杀死一个线程通常是一种不好的模式。 考虑以下情况： 该线程持有必须正确关闭的关键资源 该线程还创建了其他几个线程，这些线程也必须被杀死。 如果你能负担得起（如果你正在管理你自己的线程），处理这个问题的好方法是有一个exit_request标志，每个线程定期检查它是否是时候退出。 例如： import threading class Stoppab
Here's a middleware that I use: class StatsMiddleware(object): def process_view(self, request, view_func, view_args, view_kwargs): # get number of db queries before we do anything n = len(connection.queries) # time the view start = time.time() response = view_func(request, *view_args, **view_kwargs) totTime = time.time() - start #
这是我使用的中间件： class StatsMiddleware(object): def process_view(self, request, view_func, view_args, view_kwargs): # get number of db queries before we do anything n = len(connection.queries) # time the view start = time.time() response = view_func(request, *view_args, **view_kwargs) totTime = time.time() - start # compute the db
So here's my problems. Let's say I have a Python file and I'm typing a really long line, like the last one here: class SomeClass(object): def some_method(self): some_variable = SomeOtherClass.some_other_method(some_parameter=some_value) When I type this in Vim, this happens: class SomeClass(object): def some_method(self): some_variable = SomeOtherClass.some_other_m
所以这是我的问题。 假设我有一个Python文件，并且正在输入一个很长的行，就像这里的最后一行： class SomeClass(object): def some_method(self): some_variable = SomeOtherClass.some_other_method(some_parameter=some_value) 当我在Vim中输入时，会发生这种情况： class SomeClass(object): def some_method(self): some_variable = SomeOtherClass.some_other_method(some_parameter=some_value) 这
Based on this answer, I'd like to run this multiprocessing job with Python 2.7 / Windows: def main(): import itertools as it from multiprocessing import Pool def dothejob(i, j, k): print i, j, k the_args = it.product(range(100), range(100), range(100)) pool = Pool(4) def jobWrapper(args): return dothejob(*args) res = pool.map(jobWrapper, the_a
基于这个答案，我想用Python 2.7 / Windows来运行这个multiprocessing作业： def main(): import itertools as it from multiprocessing import Pool def dothejob(i, j, k): print i, j, k the_args = it.product(range(100), range(100), range(100)) pool = Pool(4) def jobWrapper(args): return dothejob(*args) res = pool.map(jobWrapper, the_args) if __name__ == '
#!/usr/bin/env python2 from multiprocessing import Process import pcap import sys import string from multiprocessing import Pool def capture_f(p): # print "Size Of Queue: %d" %n return p.next() def parsing_f(buffer): print len(buffer) p = pcap.pcapObject() packet_buffer = [] pool = Pool(4) if len(sys.argv) < 3: print 'usage: sniff.py <interface> <expr>' sys.
#!/usr/bin/env python2 from multiprocessing import Process import pcap import sys import string from multiprocessing import Pool def capture_f(p): # print "Size Of Queue: %d" %n return p.next() def parsing_f(buffer): print len(buffer) p = pcap.pcapObject() packet_buffer = [] pool = Pool(4) if len(sys.argv) < 3: print 'usage: sniff.py <interface> <expr>' sys.
I want to use multiprocessing on a large dataset to find the distance between two gps points. I constructed a test set, but I have been unable to get multiprocessing to work on this set. import pandas as pd from geopy.distance import vincenty from itertools import combinations import multiprocessing as mp df = pd.DataFrame({'ser_no': [1, 2, 3, 4, 5, 6, 7, 8, 9, 0], 'co_nm': ['a
我想在大数据集上使用multiprocessing来查找两个gps点之间的距离。 我构建了一个测试集，但是我一直无法获得multiprocessing来处理这个集合。 import pandas as pd from geopy.distance import vincenty from itertools import combinations import multiprocessing as mp df = pd.DataFrame({'ser_no': [1, 2, 3, 4, 5, 6, 7, 8, 9, 0], 'co_nm': ['aa', 'aa', 'aa', 'bb', 'bb', 'bb', 'bb', 'cc', 'cc', 'c
I have some links in a database which I want to download parallely. I tried doing it serially but it took too much time. I have around 1877 links. I tried this code for running the downloads parallely but it throws an error: failed: 'tuple' object has no attribute 'read' #!/usr/bin/env python import urllib from stream import ThreadPool URLs = [ 'http://www.cnn.com/', 'h
我在一个数据库中有一些我想要并行下载的链接。 我试着连续做，但花了太多时间。 我有大约1877个链接。 我试着用这个代码来并行运行下载，但是它会抛出一个错误：failed：'tuple'object has no attribute'read' #!/usr/bin/env python import urllib from stream import ThreadPool URLs = [ 'http://www.cnn.com/', 'http://www.bbc.co.uk/', 'http://www.economist.com/', 'http://nonexistant.
When I run import sys print sys.path on my Mac (Mac OS X 10.6.5, Python 2.6.1), I get the following results. /Library/Python/2.6/site-packages/ply-3.3-py2.6.egg ... /Library/Python/2.6/site-packages/ipython-0.10.1-py2.6.egg /System/Library/Frameworks/Python.framework/Versions/2.6/lib/python26.zip /System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6 /System/Library/Framework
当我跑步 import sys print sys.path 在我的Mac上（Mac OS X 10.6.5，Python 2.6.1），我得到以下结果。 /Library/Python/2.6/site-packages/ply-3.3-py2.6.egg ... /Library/Python/2.6/site-packages/ipython-0.10.1-py2.6.egg /System/Library/Frameworks/Python.framework/Versions/2.6/lib/python26.zip /System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6 /System/Library/Frameworks/Python.fr
I setup mod_wsgi, and checked it works fine. I also came up with simple django project, and also checked it works fine with the following command django-admin.py runserver --settings=mysite.settings However, when I run the following wsgi, import os import sys mysite = '/Users/smcho/Desktop/django/mysite' if mysite not in sys.path: sys.path.insert(0,'/Users/smcho/Desktop/django/mysite')
我设置mod_wsgi，并检查它工作正常。 我也想出了简单的django项目，并且使用以下命令检查它是否正常工作 django-admin.py runserver --settings=mysite.settings 但是，当我运行以下wsgi时， import os import sys mysite = '/Users/smcho/Desktop/django/mysite' if mysite not in sys.path: sys.path.insert(0,'/Users/smcho/Desktop/django/mysite') django = '/Users/smcho/Desktop/django' if django not in sys.p