Hi I've a base image and other images that I'd like to rotate with the same angle as the base image. this is my base image. this is an example image that I'd like to rotate. here my full code. #include <stdio.h> #include <iostream> #include "opencv2/core/core.hpp" #include "opencv2/features2d/features2d.hpp" #include "opencv2/highgui/highgui.hpp" #include "opencv2
嗨，我有一个基础图像和其他图像，我想旋转与基本图像相同的角度。 这是我的基本形象。 这是我想要旋转的示例图像。 这里是我的完整代码。 #include <stdio.h> #include <iostream> #include "opencv2/core/core.hpp" #include "opencv2/features2d/features2d.hpp" #include "opencv2/highgui/highgui.hpp" #include "opencv2/calib3d/calib3d.hpp" #include "opencv2/nonfree/nonfree.hpp" #include "open
Briefly, I would like to sum up values in a Mat matrix. For now I have a 256 by 1 Mat(which is actually a vector, but the Mat format will be important later on). In order to see what happens I'm trying to print it in the loop ` calcFractile(Mat* in){ cout << "Input = " << *in << endl; cout << "?!?! "; for(int k = 0; k<in->rows; k++){ cout << static_
简而言之，我想总结一个Mat矩阵中的值。 现在我有一个256乘1 Mat（这实际上是一个向量，但Mat格式稍后会很重要）。 为了看看会发生什么，我试图在循环中打印它 ` calcFractile(Mat* in){ cout << "Input = " << *in << endl; cout << "?!?! "; for(int k = 0; k<in->rows; k++){ cout << static_cast<int>(in->at<uint8_t>(0,k)) << ", "; sum += (int)in-
I am having difficulty with reading an image, extracting features for training, and testing on new images in OpenCV using SVMs. can someone please point me to a great link? I have looked at the OpenCV Introduction to Support Vector Machines. But it doesn't help with reading in images, and I am not sure how to incorporate it. My goals are to classify pixels in an image. These pixel would
我在阅读图像，提取训练功能以及使用SVM在OpenCV中测试新图像方面遇到困难。 有人能指点我一个很好的链接吗？ 我已经看过支持向量机的OpenCV简介。 但它不能帮助阅读图像，我不知道如何将其纳入。 我的目标是分类图像中的像素。 这些像素将属于曲线。 我理解形成训练矩阵（例如，图像A 1,1 1,2 1,3 1,4 1,5 2,1 2,2 2,3 2,4 2,5 3,1 3,2 3， 3 3,4 3,5 我将把训练矩阵形成为[3] [2] = {{1,1} {1,2} {1,3} {1,4} {1,5} {
I need to create a 'red' image from a grayscale image. I am using this code: void build_red(const cv::Mat& in, cv::Mat& out) { out = Mat::zeros(in.rows, in.cols, CV_8UC1); Mat zeros = Mat::zeros(in.rows, in.cols, CV_8UC1); Mat tmp; in.convertTo(tmp, CV_8UC1); vector<Mat> ch; ch.push_back(zeros); ch.push_back(zeros); ch.push_back(tmp);
我需要从灰度图像创建一个“红色”图像。 我正在使用此代码： void build_red(const cv::Mat& in, cv::Mat& out) { out = Mat::zeros(in.rows, in.cols, CV_8UC1); Mat zeros = Mat::zeros(in.rows, in.cols, CV_8UC1); Mat tmp; in.convertTo(tmp, CV_8UC1); vector<Mat> ch; ch.push_back(zeros); ch.push_back(zeros); ch.push_back(tmp); cout << "Using " <&
I know that in OpenCV 2.1 we had a function to set ROI: cvSetImageROI(), but such a function does not exist in 2.4 (or at least I cant find it in its manuals and help section.) however here is the only helpful code I could find which uses opencv 2.4 for mage ROI, but I am having trouble understanding it: // define image ROI cv::Mat imageROI; imageROI= image(cv::Rect(385,270,logo.cols,logo.rows
我知道在OpenCV 2.1中我们有一个函数来设置ROI：cvSetImageROI（），但是这个函数在2.4中不存在（或者至少我不能在它的手册和帮助部分中找到它）。 然而，这里是唯一有用的代码，我可以找到哪些使用opencv 2.4的法师投资回报率，但我无法理解它： // define image ROI cv::Mat imageROI; imageROI= image(cv::Rect(385,270,logo.cols,logo.rows)); // add logo to image cv::addWeighted(imageROI,1.0,logo,0.3,0.,imageROI);
I have searched internet and stackoverflow thoroughly, but I haven't found answer to my question: How can I get/set (both) RGB value of certain (given by x,y coordinates) pixel in OpenCV? What's important-I'm writing in C++, the image is stored in cv::Mat variable. I know there is an IplImage() operator, but IplImage is not very comfortable in use-as far as I know it comes from C
我已经彻底搜索了互联网和计算器，但是我没有找到对我的问题的答案： 如何在OpenCV中获取/设置（都）某些（由x，y坐标给定的）像素的RGB值？ 重要的是 - 我用C ++编写，图像存储在cv :: Mat变量中。 我知道有一个IplImage（）运算符，但IplImage在使用中并不是很舒服 - 据我所知它来自C API。 是的，我知道在OpenCV 2.2线程中已经有了这个Pixel访问权限，但它只是关于黑白位图。 编辑： 非常感谢您的答复。 我发现有
I need a library (C/C++) that handles the basic operations of a low level pager layer on disk. The library must include methods to get a disk page, add data, write the page to disk etc. To give a bit of background: Assume there's a particular dataset which runs query q. I have a particular grouping of the data on disk so that q can be processed faster. This library will help me write the
我需要一个库（C / C ++）来处理磁盘上低层寻呼机层的基本操作。 该库必须包含获取磁盘页面，添加数据，将页面写入磁盘等的方法。 给出一些背景知识：假设有一个运行查询q的特定数据集。 我有一个特定的磁盘上的数据分组，以便更快地处理q。 根据分组，这个库将帮助我在页面中写入数据。 感谢任何建议。 您不指定操作系统，但这并不重要：所有常见操作系统都会禁止此操作。 相反，使用内存映射文件。 要从磁盘读取页
According to C++03 3.10/1 every expression is either an lvalue or an rvalue. When I use = to assign a new value to a variable the variable name on the left of the assignment is an lvalue expression. And it looks like whatever I try to do with a variable it'll still use some expression. Is there any way to manipulate a variable in C++ other than by using an expression? The only way would
根据C ++ 03 3.10 / 1，每个表达式都是左值或右值。 当我使用=为变量分配一个新值时，赋值左侧的变量名称是一个左值表达式。 它看起来像我试图做的一个变量，它仍然会使用一些表达式。 除了使用表达式之外，还有什么方法可以在C ++中操作变量吗？ 唯一的方法是通过一个声明，而不是通过这种声明的一部分的表达。 一个例子是一个定义， std::string x; 。 这将调用x上的默认ctor。 但这是否会算作是对你的操纵？ 其实
I want to pass a callable ( std::function object) into a class Foo . The callable refers to a member method of another class which has arbitrary arguments, hence the Foo must be a variadic template. Consider this code: struct Bar { void MemberFunction(int x) {} }; template<typename ...Args> class Foo { public: Foo(std::function<void(Bar*, Args...)> f) {} }; int main() { Fo
我想将可调用（ std::function对象）传递给Foo类。 可调用是指另一个具有任意参数的类的成员方法，因此Foo必须是可变参数模板。 考虑这个代码： struct Bar { void MemberFunction(int x) {} }; template<typename ...Args> class Foo { public: Foo(std::function<void(Bar*, Args...)> f) {} }; int main() { Foo<int> m1(&Bar::MemberFunction); return 0; } 这编译好。 现在我想写一
I recently thought of a problem. Let's say there is a variadic template like this one: template <typename... Types> class example { //something }; Now what I want to achieve is that when I create an object of example<int, double, float> , this template instance will be compiled: class example<int, double, float> { int int_array[5]; double double_array[5];
我最近想到了一个问题。 假设有这样一个可变模板： template <typename... Types> class example { //something }; 现在我想实现的是当我创建一个example<int, double, float>的对象时，这个模板实例将被编译： class example<int, double, float> { int int_array[5]; double double_array[5]; float float_array[5]; } 当我创建一个example<char, long, myClass2, myClass3> ，这