Possible Duplicate: Is there any guarantee of alignment of address return by C++'s new operation? In this program, i am printing each address returned by new for unsigned chars. Then deleting them backwards in the end. #include "stdafx.h" #include<stdlib.h> void func(); int main() { int i=10; while(i-->0)printf("loaded %i n", (new unsigned char)); getchar(); un
可能重复： C ++的新操作对地址返回是否有任何保证？ 在这个程序中，我打印每个由无符号字符组成的新地址。 然后最后将它们向后删除。 #include "stdafx.h" #include<stdlib.h> void func(); int main() { int i=10; while(i-->0)printf("loaded %i n", (new unsigned char)); getchar(); unsigned char *p=new unsigned char;printf("last pointer loaded %i n", p); i=10; while(i--&g
I can create an array and initialize it like this: int a[] = {10, 20, 30}; How do I create a std::vector and initialize it similarly elegant? The best way I know is: std::vector<int> ints; ints.push_back(10); ints.push_back(20); ints.push_back(30); Is there a better way? 一种方法是使用数组来初始化向量static const int arr[] = {16,2,77,29}; vector<int> vec (arr, arr + sizeof(arr
我可以创建一个数组并像这样初始化它： int a[] = {10, 20, 30}; 如何创建一个std::vector并初始化它类似于优雅？ 我知道的最好方法是： std::vector<int> ints; ints.push_back(10); ints.push_back(20); ints.push_back(30); 有没有更好的办法？ 一种方法是使用数组来初始化向量static const int arr[] = {16,2,77,29}; vector<int> vec (arr, arr + sizeof(arr) / sizeof(arr[0]) ); 如果你的编译器支持
I have a std::vector<int>, and I want to delete the n'th element. How do I do that? std::vector<int> vec; vec.push_back(6); vec.push_back(-17); vec.push_back(12); vec.erase(???); To delete a single element, you could do: std::vector<int> vec; vec.push_back(6); vec.push_back(-17); vec.push_back(12); // Deletes the second element (vec[1]) vec.erase(vec.begin() + 1); O
我有一个std :: vector <int>，我想删除第n个元素。 我怎么做？ std::vector<int> vec; vec.push_back(6); vec.push_back(-17); vec.push_back(12); vec.erase(???); 要删除一个元素，你可以这样做： std::vector<int> vec; vec.push_back(6); vec.push_back(-17); vec.push_back(12); // Deletes the second element (vec[1]) vec.erase(vec.begin() + 1); 或者，一次删除多个元素： // Deletes the
如何连接两个std::vector ？ vector1.insert( vector1.end(), vector2.begin(), vector2.end() ); If you are using C++11, and wish to move the elements rather than merely copying them, you can use std::move_iterator (http://en.cppreference.com/w/cpp/iterator/move_iterator) along with insert (or copy): #include <vector> #include <iostream> #include <iterator> int main(int argc, char*
如何连接两个std::vector ？ vector1.insert( vector1.end(), vector2.begin(), vector2.end() ); 如果您正在使用C ++ 11，并且希望移动元素而不是仅仅复制元素，则可以使用std :: move_iterator（http://en.cppreference.com/w/cpp/iterator/move_iterator）以及insert （或复制）： #include <vector> #include <iostream> #include <iterator> int main(int argc, char** argv) { std::vector<int>
Having this class : class Automat { private: // some members ... public: Automat(); ~Automat(); void addQ(string& newQ) ; void addCharacter(char& newChar) ; void addLamda(Lamda& newLamda) ; void setStartSituation(string& startQ) ; void addAccQ(string& newQ) ; bool checkWord(string& wordToCheck) ; friend istream& operator &
有这个课程： class Automat { private: // some members ... public: Automat(); ~Automat(); void addQ(string& newQ) ; void addCharacter(char& newChar) ; void addLamda(Lamda& newLamda) ; void setStartSituation(string& startQ) ; void addAccQ(string& newQ) ; bool checkWord(string& wordToCheck) ; friend istream& operator >>
I am working on an implementation of merge-sort which will sort a list of songs by their length. I have written the following and have been unable to fins the flaw in my logic. Instead of returning a sorted list these functions return a list of one item from the middle of the original list. vector<song> merge( vector<song> firstList, vector<song> secondList){ vector<song&
我正在研究一种合并排序的实现，它将按照歌曲的长度对歌曲列表进行排序。 我写了以下内容，并且无法理解我的逻辑中的缺陷。 这些函数不是返回一个排序列表，而是从原始列表的中间返回一个项目的列表。 vector<song> merge( vector<song> firstList, vector<song> secondList){ vector<song> outPut; int i = 0; int n = 0; while( outPut.size() < (firstList.size() + secondList.size()-1 )){
First question here, and yes this is a homework question. We are tasked with performing merge sort on an array (which I am familiar with), but in a way I am unsure of how to do. Usually I would have a separate merge and merge sort function, and use the two. However, it sounds like he wants everything in one method? I was just hoping maybe someone could help clear things up for me, or put them
这里的第一个问题，是的，这是一个家庭作业问题。 我们负责在一个数组上执行合并排序（我熟悉这个数组），但以某种方式，我不确定如何去做。 通常我会有一个单独的合并和合并排序功能，并使用这两个。 然而，这听起来像他希望在一种方法中的一切？ 我只是希望也许有人能帮我解决问题，或者把它们放到我能更好理解的地方。 来自作业： 您将需要实现合并排序算法的非递归版本。 排列两个嵌套循环来完成此任务。 外部循环
I am writing a IRC client in C++ (with the help of the SFML library), but it is behaving strangely. I send the NICK and USER commands and I can connect to the server, but the JOIN command has many strange thing happening that I have to write "Random code that magically works" to solve. I am pretty sure that the commands adhere to the IRC RFC as well. I know that the sockets are send
我正在用C ++写一个IRC客户端（在SFML库的帮助下），但它表现得很奇怪。 我发送NICK和USER命令，我可以连接到服务器，但JOIN命令有很多奇怪的事情发生，我必须写出“神奇地工作的随机代码”来解决。 我很确定这些命令也遵循IRC RFC。 我知道套接字正在发送它们应该发送的内容，并且我已经使用Wireshark进行了验证，所以我在这里发布的是数据包的消息。 在以下示例中，套接字已连接到IRC服务器（在本例中为irc.freenode.net）
Intro So we spent some days with all our team that consists of 2 individuals including me (meaning that our efforts were not as professional as yours could be) at CloudObserver triing to make it out with ASL. We have found out how to compile ASL on windows and Mac OS. We have created some visual/graphical GUI simple tutorials on ASL that worked perfectly with Mac OS X and Windows, so we hav
介绍 因此，我们花了一些时间与包括我在内的2个人组成的所有团队（意味着我们的努力不像您的职业一样专业）在CloudObserver试图使用ASL进行测试。 我们已经发现如何在Windows和Mac OS上编译ASL。 我们已经在ASL上创建了一些可视化/图形化GUI简单教程，这些教程完全适用于Mac OS X和Windows，所以我们已经看到Adobe Source Libraries可用于创建至少简单的UI和对话框。 比我们开始尝试使它在Linux上工作。 肉 我们已经
I am running C++ code where I need to import data from txt file. The text file contains 10,000 lines. Each line contains n columns of binary data. The code has to loop 100,000 times, each time it has to randomly select a line out of the txt file and assign the binary values in the columns to some variables. What is the most efficient way to write this code? should I load the file first int
我正在运行C ++代码，我需要从txt文件导入数据。 该文本文件包含10,000行。 每行包含n列二进制数据。 代码必须循环100,000次，每次必须从txt文件中随机选择一行，并将列中的二进制值分配给某些变量。 什么是写这段代码最有效的方法？ 我应该首先将文件加载到内存中，还是应该随机打开一个随机行号？ 我如何在C ++中实现这一点？ 要随机访问文本文件中的一行，所有行都需要具有相同的字节长度。 如果你没有这个，你需